gerbil | friendly animals | Unit Testing library
kandi X-RAY | gerbil Summary
kandi X-RAY | gerbil Summary
n. Gerbils: Inquisitive, friendly animals that rarely bite, TDD for the rest of us. Gerbil attemps to be an uber simple and minimalistic testing framework for javascript.
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Trending Discussions on gerbil
QUESTION
I am trying to stay ahead of my Year 12 Software class. Starting to work with records and arrays. I have answered the question, but the solution feels very clunky. I am hoping someone has suggestions/links for completing this task in a more efficient way. The task: read in lines from a text file and into a structure, and then loop through that, populating four list boxes if an animal hasn't been vaccinated. Here's the code:
...ANSWER
Answered 2021-Mar-12 at 06:22If you don't need the 'PetsRecord' array to store data, take a look at the following code:
QUESTION
I'm looking at figures from Moreira et al. (Nature, 2020) where they have graphs indicating sample size and treatments under the barplots such as this:
Is there a way to reproduce this in ggplot? This would be very useful to indicate all the necessary information regarding an experiment in a compact manner.
Some dummy data for the plot:
...ANSWER
Answered 2021-Jan-13 at 18:46There are probably two or three approaches to achieve your desired result. Personally I prefer to do it via patchwork
, i.e create a second plot with the additional information you want to display and glue it to your main plot:
QUESTION
Sqlite3
How do I select animals which are only pets and not food? POF is "pet or food" column. An animal can belong to both groups. This is a smaller version of the real problem. I don't want to split this into more tables.
...ANSWER
Answered 2020-Aug-19 at 22:19One method uses aggregation:
QUESTION
Suppose I have two csv files. One is
...ANSWER
Answered 2020-May-12 at 21:03This is a simple solution assuming there's always exactly one match, and you don't care about output order. Change the output path to csv1 to overwrite.
I added headers manually in both input files, but you can specify them in Import-Csv instead if you'd rather avoid changing your files.
QUESTION
User enters a pet name and if found in the dictionary, code returns the price of the pet, otherwise asks the user to try a different name. Wondering if this could be done in a cleaner way, with fewer lines of code?
...ANSWER
Answered 2020-May-03 at 16:46You could cut it down a bit by doing:
QUESTION
sex age pets
0 M 21 [cat, dog]
1 M 45 [hamster]
2 F 23 [cat, gerbil]
3 M 56 [fish, hamster, gerbil]
4 F 47 [cat]
5 F 70 [dog]
6 F 34 [dog]
7 M 30 [cat]
8 F 19 [rabbit, cat]
9 M 62 [dog]
...ANSWER
Answered 2020-Mar-18 at 06:47Try this:
QUESTION
I'm writing a simple text-based game for a friend's website. I need to be able to change an HTML element or update the HTML page without running into the Maximum call stack exceeded error. I'm currently using
...ANSWER
Answered 2020-Mar-13 at 05:57QUESTION
If I have a list with completely unpredictable and seemingly nonsensical nesting like so:
...ANSWER
Answered 2019-Jul-04 at 06:44One way in base R would be to write a recursive function which checks for names at every level if any
name in the list contains the name "Rabbit"
QUESTION
I have data in text format, where key/value pairs are separated by semi-colon, may be followed by whitespace, maybe not, e.g., ";" or "; ", or even " ; ". There will always be a semi-colon between pairs, and the string is terminated with a semi-colon.
Keys and values are separated by whitespace.
This string is flat. There's never anything nested. Strings are always quoted and numerical values are never quoted. I can count on this being consistent in the input. So for example,
...ANSWER
Answered 2019-May-25 at 16:44It might be easier to use findall()
instead of split()
here. This will let you use a capture group to pull out just the part you want. Then you can split the groups, cleanup, etc:
QUESTION
I'm trying to create a new column in a dataframe that labels animals that are domesticated with a 1. I'm using a for loop, but for some reason, the loop only picks up the last item in the pets
list. dog
, cat
, and gerbil
should all be assigned a 1 under the domesticated
column. Anyone have a fix for this or a better approach?
ANSWER
Answered 2019-Mar-20 at 23:26You are setting all non gerbil to 0
in your last loop iteration. That is, when pet
is gerbil
in your last iteration, ALL entries that are not equal to gerbil
will correspond to 0
. This includes entries that are dog
or cat
. You should check all values in pets
at once. Try this:
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