imem | imem 是important和emergent的开头两个字母
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imem 是important和emergent的开头两个字母
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QUESTION
I've got a WPF - C# project and I'm trying to speed up the image processing I'm doing in there; by doing it using OpenCL and Cloo.
I did manage to get a kernel working that can change a bitmap to grayscale, but for some reason the black and white kernel I've made only outputs a completely black image.
Here's my kernel .cl
code :
ANSWER
Answered 2021-Feb-15 at 07:12read_imagef
returns color/alpha values in the range [0.0f, 1.0f]
and not [0.0f, 255.0f]
. This means you have to set:
QUESTION
Why PC in RISC V architecture connect with PC+4 instead of PC+2 or PC+1. I think it depend on the width of memory cell of the Instruction Memory (IMEM). If the width is 16 bits, then we need to load two adjacent addresses to fill 32 bits instruction or if the width is 32 bits, we only need to load one address to take the full instruction.
...ANSWER
Answered 2020-Sep-16 at 09:10RISC-V deals with everything in byte addresses (from page 19 of the ISA manual: "RV32I provides a 32-bit user address space that is byte-addressed and little-endian"). So when using byte addresses, it makes sense to think of the PC as incrementing by 4, as each of the RV32 instructions are 4 bytes.
When we say RISC-V increments the PC by 4, what that means is that for any given byte address X
of a 32-bit RISC-V instruction, the next instruction will begin in memory at address X+4
. (Note that when using compressed instructions, which are 16 bits / 2 bytes, the PC is incremented by 2).
An IMEM read width of 16 bits means 2 reads from IMEM are necessary to get a full instruction, and an IMEM read width of 32 bits means only 1 read from IMEM is necessary to get a full instruction. But these are implementation considerations, not an ISA considerations -- you could hypothetically implement an ISA-compliant RISC-V processor with either type of IMEM.
QUESTION
Code:
...ANSWER
Answered 2020-Jul-22 at 04:22First, you have an extra u200b character
. And second, you can use setTimeout
function.
QUESTION
I am developing a CPU in VHDL. I am using ModelSim for simulation and testing. In the simulation script I load a program from a binary file to the instruction memory. Now I want to automatically check if the program fits into memory and abort simulation if it doesn't. Since the memory is basically an array of std_logic_vectors, all I would have to do is read the corresponding signal attribute for use in a comparison. My problem is: How do I access a VHDL signal attribute in TCL inside ModelSim?
The closest I have gotten so far is to use the describe command:
...ANSWER
Answered 2018-Nov-12 at 16:57Disclaimer: I'm not a Tcl expert, so there's probably a more optimized solution out there.
There's a command called examine
that you can use to get the value of obejcts.
I created a similar testbench here with a 256 x 32 array, the results were
QUESTION
Can someone explain this for me?
Addresses are for individual bytes (8 bits)
I have pasted the entire paragraph below:
The MIPS has a 32 bit architecture, with 32 bit instructions, a 32 bit data word, and 32 bit addresses. It has 32 addressable internal registers requiring a 5 bit register address. Register 0 always has the the constant value 0.
Addresses are for individual bytes (8 bits) but instructions must have addresses which are a multiple of 4. This is usually stated as “instructions must be word aligned in memory.
Link to pdf:
http://web.cs.mun.ca/~paul/cs3725/material/review.pdf
In the code below, I don't understand IMem[i] = bitset<8>(line)
ANSWER
Answered 2019-Sep-24 at 02:06explain this “Addresses are for individual bytes (8 bits)” for me?
It means that size of a byte is 8 bits. Two adjacent addresses will be 8 bits apart. A 32 bit word consists of 4 bytes.
Furthermore it means that - even though address operands of instructions must be aligned to a 4 byte boundary as explained in the following sentence - each byte has a unique address.
By unique address, do you mean unique 5 bit values?
No. The memory addresses are 32 bit values.
where are addresses usually saved?
Where-ever any values are saved. In the given description, two possible places have been described: In memory, or in a register.
QUESTION
So I have this encryption / decryption code:
...ANSWER
Answered 2017-Apr-02 at 21:05Your using
statement will make sure that the stream gets closed and therefore flushed automatically. Unfortunately you retrieve the ciphertext / plaintext from the MemoryStream
before that.
Don't use PasswordDeriveBytes
, especially not for more than 20 bytes, it's insecure. Rather use `Rfc2898DeriveBytes.
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