follow | Very stable , very reliable , NodeJS CouchDB

 by   iriscouch JavaScript Version: Current License: Apache-2.0

kandi X-RAY | follow Summary

kandi X-RAY | follow Summary

follow is a JavaScript library. follow has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Follow (upper-case F) comes from an internal Iris Couch project used in production for over a year. It works in the browser (beta) and is available as an NPM module.
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            kandi-support Support

              follow has a low active ecosystem.
              It has 386 star(s) with 83 fork(s). There are 18 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 37 open issues and 23 have been closed. On average issues are closed in 138 days. There are 5 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of follow is current.

            kandi-Quality Quality

              follow has 0 bugs and 0 code smells.

            kandi-Security Security

              follow has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              follow code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              follow is licensed under the Apache-2.0 License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              follow releases are not available. You will need to build from source code and install.
              Installation instructions are not available. Examples and code snippets are available.

            Top functions reviewed by kandi - BETA

            kandi has reviewed follow and discovered the below as its top functions. This is intended to give you an instant insight into follow implemented functionality, and help decide if they suit your requirements.
            • Make a request
            • Main entry point for changes .
            • Search listeners for listeners .
            • response callback function
            • grow the listener tree
            • handle the feed
            • Exports a file to the target module
            • Base64 encode string
            • Handle a change event .
            • Handle pending changes
            Get all kandi verified functions for this library.

            follow Key Features

            No Key Features are available at this moment for follow.

            follow Examples and Code Snippets

            What rules does the parsing engine follow?
            npmdot img1Lines of Code : 2dot img1no licencesLicense : No License
            copy iconCopy
            {MULTILINE: 'new
            line'}
            
              
            Follow a user .
            pythondot img2Lines of Code : 16dot img2License : Permissive (MIT License)
            copy iconCopy
            def follow(username):
                form = EmptyForm()
                if form.validate_on_submit():
                    user = User.query.filter_by(username=username).first()
                    if user is None:
                        flash(_('User %(username)s not found.', username=username))
                         
            Click to follow
            pythondot img3Lines of Code : 11dot img3License : Permissive (MIT License)
            copy iconCopy
            def click_to_follow(browser):
                # my_follow_btn_xpath = "//a[contains(text(), 'Follow')][not(contains(text(), 'Following'))]"
                # my_follow_btn_xpath = "//*[contains(text(), 'Follow')][not(contains(text(), 'Following'))]"
                my_follow_btn_xpath   
            Follow the specified album .
            javadot img4Lines of Code : 3dot img4License : Permissive (MIT License)
            copy iconCopy
            void followAlbum(Album album) {
                    this.followingAlbums.add(album);
                }  

            Community Discussions

            QUESTION

            How do purely functional languages handle index-based algorithms?
            Asked 2022-Apr-05 at 12:51

            I have been trying to learn about functional programming, but I still struggle with thinking like a functional programmer. One such hangup is how one would implement index-heavy operations which rely strongly on loops/order-of-execution.

            For example, consider the following Java code:

            ...

            ANSWER

            Answered 2022-Mar-07 at 21:17

            This is not an index-heavy operation, in fact you can do this with a one-liner with scanl1 :: (a -> a -> a) -> [a] -> [a]:

            Source https://stackoverflow.com/questions/71387267

            QUESTION

            Error: Member not found: 'packageRoot', how to solve ignore: deprecated_member_use in Flutter?
            Asked 2022-Apr-05 at 06:52

            In my flutter project, I have made some updates of plugins and then used flutter upgrade. After that, whenever I am running my flutter project it is showing following error-

            ...

            ANSWER

            Answered 2021-Dec-16 at 11:49

            For me, cleaning and getting the packages didn't work. This error started after I upgraded flutter. I was on the master channel, a quick fix for me was to switch to stable.

            Source https://stackoverflow.com/questions/70363918

            QUESTION

            Error while creating new React app ("You are running `create-react-app` 4.0.3, which is behind the latest release (5.0.0)")
            Asked 2022-Apr-04 at 11:58

            I am getting this create React app error again and again even after doing the uninstall part.

            npm uninstall -g create-react-app

            up to date, audited 1 package in 570ms

            found 0 vulnerabilities

            npx create-react-app test-app

            Need to install the following packages: create-react-app Ok to proceed? (y) y

            You are running create-react-app 4.0.3, which is behind the latest release (5.0.0).

            We no longer support global installation of Create React App.

            Please remove any global installs with one of the following commands:

            • npm uninstall -g create-react-app
            • yarn global remove create-react-app

            The latest instructions for creating a new app can be found here: https://create-react-app.dev/docs/getting-started/

            ...

            ANSWER

            Answered 2022-Jan-01 at 22:34

            You will have to clear the npx cache to make it work.

            You can locate the location of the folder where create-react-app is installed using npm ls -g create-react-app.

            Also, to clear the cache, refer to this answer in How can I clear the central cache for `npx`?

            Source https://stackoverflow.com/questions/70358474

            QUESTION

            Publish error: Found multiple publish output files with the same relative path
            Asked 2022-Mar-21 at 05:58

            When I publish my ABP project I get the following error:

            ...

            ANSWER

            Answered 2022-Jan-13 at 21:59

            Issue:

            The issue raises after .NET 6 migration. There's a new feature that blocks multiple files from being copied to the same target directory with the same file name. See https://docs.microsoft.com/en-us/dotnet/core/compatibility/sdk/6.0/duplicate-files-in-output

            Solution #1 (workaround):

            You can add the following build property to all your publishable (*.Web) projects' *.csproj files. This property will bypass this check and works as previously, in .NET5.

            Source https://stackoverflow.com/questions/69919664

            QUESTION

            ASP.NET Core 6 how to access Configuration during startup
            Asked 2022-Mar-08 at 11:45

            In earlier versions, we had Startup.cs class and we get configuration object as follows in the Startup file.

            ...

            ANSWER

            Answered 2021-Oct-26 at 12:26

            WebApplicationBuilder returned by WebApplication.CreateBuilder(args) exposes Configuration and Environment properties:

            Source https://stackoverflow.com/questions/69722872

            QUESTION

            jcenter.bintray.com is down Error: 502 Bad Gateway
            Asked 2022-Jan-30 at 23:50

            When trying to build my project I am getting the following error:

            Could not GET
            'https://jcenter.bintray.com/androidx/lifecycle/lifecycle-common/maven-metadata.xml'.
            Received status code 502 from server: Bad Gateway

            • In my build.gradle repositories I don't have JCenter, so this error I'm getting is from dependencies that are still pointing to JCenter.
            • Gradle offline mode is not the solution I'm expecting.
            • I know that JCenter is down and that we should all move to Maven Central (I already did)

            Is there a workaround?

            ...

            ANSWER

            Answered 2022-Jan-30 at 23:31

            It's a global outage in JCenter. You can monitor status at https://status.gradle.com. It replaces the bintray status page which seems is now fully sunset and returns a 502 error.

            UPDATE Jan 13, 06:35 UTC

            JCenter is now back online, and systems are fully operational.

            UPDATE Jan 20

            Gradle Plugin resolution outage postmortem

            https://blog.gradle.org/plugins-jcenter

            Following this incident, the Gradle Plugin Portal now uses a JCenter mirror hosted by Gradle instead of JCenter directly. This should shield users from short JCenter outages for libraries that have been cached by the mirror. We saw another short outage of JCenter over the weekend and this did not appear to impact Gradle Plugin Portal users.

            Source https://stackoverflow.com/questions/70687342

            QUESTION

            Why does the first element outside of a defined array default to zero?
            Asked 2021-Dec-23 at 08:46

            I'm studying for the final exam for my introduction to C++ class. Our professor gave us this problem for practice:

            Explain why the code produces the following output: 120 200 16 0

            ...

            ANSWER

            Answered 2021-Dec-13 at 20:55

            It does not default to zero. The sample answer is wrong. Undefined behaviour is undefined; the value may be 0, it may be 100. Accessing it may cause a seg fault, or cause your computer to be formatted.

            As to why it's not an error, it's because C++ is not required to do bounds checking on arrays. You could use a vector and use the at function, which throws exceptions if you go outside the bounds, but arrays do not.

            Source https://stackoverflow.com/questions/70340719

            QUESTION

            Why is a segmentation fault not recoverable?
            Asked 2021-Dec-13 at 08:36

            Following a previous question of mine, most comments say "just don't, you are in a limbo state, you have to kill everything and start over". There is also a "safeish" workaround.

            What I fail to understand is why a segmentation fault is inherently nonrecoverable.

            The moment in which writing to protected memory is caught - otherwise, the SIGSEGV would not be sent.

            If the moment of writing to protected memory can be caught, I don't see why - in theory - it can't be reverted, at some low level, and have the SIGSEGV converted to a standard software exception.

            Please explain why after a segmentation fault the program is in an undetermined state, as very obviously, the fault is thrown before memory was actually changed (I am probably wrong and don't see why). Had it been thrown after, one could create a program that changes protected memory, one byte at a time, getting segmentation faults, and eventually reprogramming the kernel - a security risk that is not present, as we can see the world still stands.

            1. When exactly does a segmentation fault happen (= when is SIGSEGV sent)?
            2. Why is the process in an undefined behavior state after that point?
            3. Why is it not recoverable?
            4. Why does this solution avoid that unrecoverable state? Does it even?
            ...

            ANSWER

            Answered 2021-Dec-10 at 15:05

            When exactly does segmentation fault happen (=when is SIGSEGV sent)?

            When you attempt to access memory you don’t have access to, such as accessing an array out of bounds or dereferencing an invalid pointer. The signal SIGSEGV is standardized but different OS might implement it differently. "Segmentation fault" is mainly a term used in *nix systems, Windows calls it "access violation".

            Why is the process in undefined behavior state after that point?

            Because one or several of the variables in the program didn’t behave as expected. Let’s say you have some array that is supposed to store a number of values, but you didn’t allocate enough room for all them. So only those you allocated room for get written correctly, and the rest written out of bounds of the array can hold any values. How exactly is the OS to know how critical those out of bounds values are for your application to function? It knows nothing of their purpose.

            Furthermore, writing outside allowed memory can often corrupt other unrelated variables, which is obviously dangerous and can cause any random behavior. Such bugs are often hard to track down. Stack overflows for example are such segmentation faults prone to overwrite adjacent variables, unless the error was caught by protection mechanisms.

            If we look at the behavior of "bare metal" microcontroller systems without any OS and no virtual memory features, just raw physical memory - they will just silently do exactly as told - for example, overwriting unrelated variables and keep on going. Which in turn could cause disastrous behavior in case the application is mission-critical.

            Why is it not recoverable?

            Because the OS doesn’t know what your program is supposed to be doing.

            Though in the "bare metal" scenario above, the system might be smart enough to place itself in a safe mode and keep going. Critical applications such as automotive and med-tech aren’t allowed to just stop or reset, as that in itself might be dangerous. They will rather try to "limp home" with limited functionality.

            Why does this solution avoid that unrecoverable state? Does it even?

            That solution is just ignoring the error and keeps on going. It doesn’t fix the problem that caused it. It’s a very dirty patch and setjmp/longjmp in general are very dangerous functions that should be avoided for any purpose.

            We have to realize that a segmentation fault is a symptom of a bug, not the cause.

            Source https://stackoverflow.com/questions/70258418

            QUESTION

            Why is Python list slower when sorted?
            Asked 2021-Dec-02 at 05:34

            In the following code, I create two lists with the same values: one list unsorted (s_not), the other sorted (s_yes). The values are created by randint(). I run some loop for each list and time it.

            ...

            ANSWER

            Answered 2021-Nov-15 at 21:05

            Cache misses. When N int objects are allocated back-to-back, the memory reserved to hold them tends to be in a contiguous chunk. So crawling over the list in allocation order tends to access the memory holding the ints' values in sequential, contiguous, increasing order too.

            Shuffle it, and the access pattern when crawling over the list is randomized too. Cache misses abound, provided there are enough different int objects that they don't all fit in cache.

            At r==1, and r==2, CPython happens to treat such small ints as singletons, so, e.g., despite that you have 10 million elements in the list, at r==2 it contains only (at most) 100 distinct int objects. All the data for those fit in cache simultaneously.

            Beyond that, though, you're likely to get more, and more, and more distinct int objects. Hardware caches become increasingly useless then when the access pattern is random.

            Illustrating:

            Source https://stackoverflow.com/questions/69950010

            QUESTION

            Doesn't constraining the "auto" in C++ defeat the purpose of it?
            Asked 2021-Nov-15 at 02:21

            In C++20, we are now able to constrain the auto keyword to only be of a specific type. So if I had some code that looked like the following without any constraints:

            ...

            ANSWER

            Answered 2021-Nov-01 at 18:38

            A constraint on the deduced auto type doesn't mean it needs to be a specific type, it means it needs to be one of a set of types that satisfy the constraint. Note that a constraint and a type are not the same thing, and they're not interchangeable.

            e.g. a concept like std::integral constrains the deduced type to be an integral type, such as int or long, but not float, or std::string.

            If I really need a std::integral datatype, couldn't I just omit the auto completely?

            In principle, I suppose you could, but this would at the minimum lead to parsing difficulties. e.g. in a declaration like

            Source https://stackoverflow.com/questions/69801126

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install follow

            You can download it from GitHub.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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            https://github.com/iriscouch/follow.git

          • CLI

            gh repo clone iriscouch/follow

          • sshUrl

            git@github.com:iriscouch/follow.git

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