hott | Global hotkeys for Windows , with node

 by   jon-hall JavaScript Version: 0.0.4 License: MIT

kandi X-RAY | hott Summary

kandi X-RAY | hott Summary

hott is a JavaScript library typically used in Electron applications. hott has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can install using 'npm i hott' or download it from GitHub, npm.

Global hotkeys for Windows, with node
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              hott has a low active ecosystem.
              It has 4 star(s) with 2 fork(s). There are 1 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 2 open issues and 1 have been closed. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of hott is 0.0.4

            kandi-Quality Quality

              hott has no bugs reported.

            kandi-Security Security

              hott has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              hott is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

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              hott releases are not available. You will need to build from source code and install.
              Deployable package is available in npm.
              Installation instructions are not available. Examples and code snippets are available.

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            hott Key Features

            No Key Features are available at this moment for hott.

            hott Examples and Code Snippets

            No Code Snippets are available at this moment for hott.

            Community Discussions

            QUESTION

            Printing to stdout returning gibbersih
            Asked 2020-Jul-21 at 12:01

            I am using gcc 10.1.1 on Fedora 32. The following program is to read from a file given by the user and print it into stdout. The code is an example in Modern C by Jens Gusdets.

            ...

            ANSWER

            Answered 2020-Jul-21 at 12:01

            argv[0] is always the program name. You're printing the contents of your executable in addition to any extra files identified by the filenames passed in the arguments by starting your for loop at i = 0.

            If you start at i = 1, it will exclude your executable.

            Source https://stackoverflow.com/questions/63006657

            QUESTION

            Casting from a to b then b to a is identity?
            Asked 2020-May-11 at 08:49

            Given the definition:

            ...

            ANSWER

            Answered 2020-May-11 at 08:49

            I am not completely sure, but it seems to me that what you are trying to prove is no different from forall a (p:a=a), p = eq_refl. If so, you cannot prove it in Coq, unless you know something about a, e.g., decidable equality. In that case, you can use the results on UIP (unicity of identity proofs) from the standard library.

            Source https://stackoverflow.com/questions/61724904

            QUESTION

            Replace all observations whose character string is greater than X
            Asked 2020-Apr-29 at 11:48

            I have some data which looks like:

            ...

            ANSWER

            Answered 2020-Apr-29 at 11:36

            nchar() is the function you want:

            Source https://stackoverflow.com/questions/61500808

            QUESTION

            Agda pattern matching inside type declarations
            Asked 2020-Mar-06 at 16:15

            I am learning HoTT with Agda form beginning. I followed instructions in https://www.cs.bham.ac.uk/~mhe/HoTT-UF-in-Agda-Lecture-Notes/

            When I started to type in declaration of dependent sum type induction just like the notes instructed,

            ...

            ANSWER

            Answered 2020-Mar-06 at 16:15

            The ability to pattern-match on records in telescopes will be available in the (soon) upcoming version Agda 2.6.1.

            Cf. the documentation of the development branch: https://agda.readthedocs.io/en/latest/language/telescopes.html#irrefutable-patterns-in-binding-positions

            Source https://stackoverflow.com/questions/60557445

            QUESTION

            Reason for equality definition in COQ and HOTT
            Asked 2019-May-24 at 19:21

            In HOTT and also in COQ one cannot prove UIP, i.e.
            \Prod_{p:a=a} p = refl a

            But one can prove:
            \Prod_{p:a=a} (a,p) = (a, refl a)

            Why is this defined as it is? Is it, because one wants to have a nice homotopy interpretation? Or is there some natural, deeper reason for this definition?

            ...

            ANSWER

            Answered 2019-May-24 at 19:21

            Today we know of a good reason for rejecting UIP: it is incompatible with the principle of univalence from homotopy type theory, which roughly says that isomorphic types can be identified. However, as far as I am aware, the reason that Coq's equality does not validate UIP is mostly a historical accident inherited from one of its ancestors: Martin-Löf's intensional type theory, which predates HoTT by many years.

            The behavior of equality in ITT was originally motivated by the desire to keep type checking decidable. This is possible in ITT because it requires us to explicitly mark every rewriting step in a proof. (Formally, these rewriting steps correspond to the use of the equality eliminator eq_rect in Coq.) By contrast, Martin-Löf designed another system called extensional type theory where rewriting is implicit: whenever two terms a and b are equal, in the sense that we can prove that a = b, they can be used interchangeably. This relies on an equality reflection rule which says that propositionally equal elements are also definitionally equal. Unfortunately, there is a price to pay for this convenience: type checking becomes undecidable. Roughly speaking, the type-checking algorithm relies crucially on the explicit rewriting steps of ITT to guide its computation, whereas these hints are absent in ETT.

            We can prove UIP easily in ETT because of the equality reflection rule; however, it was unknown for a long time whether UIP was provable in ITT. We had to wait until the 90's for the work of Hofmann and Streicher, which showed that UIP cannot be proved in ITT by constructing a model where UIP is not valid. (Check also these slides by Hofmann, which explain the issue from a historic perspective.)

            Edit

            This doesn' t mean that UIP is incompatible with decidable type checking: it was shown later that it can be derived in other decidable variants of Martin-Löf type theory (such as Agda), and it can be safely added as an axiom in a system like Coq.

            Source https://stackoverflow.com/questions/46927295

            QUESTION

            Interval extensionality?
            Asked 2018-Nov-30 at 15:21

            I asked the following question on the CS SE:

            For example, in the proof of lemma 6.4.1 in the HoTT book, a function inductively defined over a function is simply applied on paths loop and refl, and then a path between loop and refl is used (presumably by congruence via f) to construct a path between f loop and f refl:

            Suppose that loop = refl base. [...] with x : A and p : x = x, there is a function f : S1 → A defined by f(base) :≡ x and f(loop) := p, we have

            ...

            ANSWER

            Answered 2018-Nov-26 at 09:45

            See Saizan's answer for a solution along the original lines. Alternatively, there is a simple solution:

            Source https://stackoverflow.com/questions/53464314

            QUESTION

            Path induction using eq_rect
            Asked 2018-Nov-30 at 10:13

            According to Homotopy Type Theory (page 49), this is the full induction principle for equality :

            ...

            ANSWER

            Answered 2018-Sep-02 at 14:55

            I think you are referring to the fact that the result type of path_induction mentions the path that is being destructed, whereas the one of eq_rect does not. This omission is the default for inductive propositions (as opposed to what happens with Type), because the extra argument is not usually used in proof-irrelevant developments. Nevertheless, you can instruct Coq to generate more complete induction principles with the Scheme command: https://coq.inria.fr/distrib/current/refman/user-extensions/proof-schemes.html?highlight=minimality. (The Minimality variant is the one used for propositions by default.)

            Source https://stackoverflow.com/questions/52137987

            QUESTION

            Is the univalence axiom injective?
            Asked 2018-Nov-22 at 06:06

            Is the univalence axiom invertible (modulo paths)? Is it possible to prove, using Agda's Cubical library, to prove the following:

            ...

            ANSWER

            Answered 2018-Nov-14 at 15:16

            Sure, ua is an equivalence, so it's injective. In the HoTT book, the inverse of ua is idtoeqv, so by congruence idtoeqv (ua f) ≡ idtoeqv (ua g) and then by inverses f ≡ g. I'm not familiar with the contents of cubical Agda prelude but this should be provable since it follows directly from the statement of univalence.

            Source https://stackoverflow.com/questions/53302504

            QUESTION

            Why J axiom takes 2 x when giving signature of x, y?
            Asked 2018-Oct-24 at 09:00

            First, I've already looked up into several related materials, including the HoTT book & this question.

            But I'm still confused, and I'm wishing for a explanation free from Agda, but directly from its mathematical formula. After removing the dot notation, J axiom then says like this, whose type signature is completely the same in the answer of the question I've mentioned above:

            ...

            ANSWER

            Answered 2018-Oct-17 at 02:48

            When you pattern match on p at refl in the definition of J, its type is refined from x ≡ y to x ≡ x (since the type of the constructor refl is ∀ {x} -> x ≡ x, i.e. it sets both indices to x), which means we can refine both the left- and the right-hand sides by x ~ y, which is both why the y in the pattern becomes x (or, alternatively, .x in Agda to make it explicit that it is an inaccessable pattern), and also why c x : C x x refl passes on the right-hand side for the result type C x y p.

            Source https://stackoverflow.com/questions/52840720

            QUESTION

            Is there a type theory in which the equivalence of identically shaped inductive datatypes is representable?
            Asked 2018-Sep-19 at 07:08

            Say I have two inductively defined datatypes:

            ...

            ANSWER

            Answered 2018-Sep-19 at 07:08

            In HoTT with univalence, it is indeed provable that list1 A is equal to list2 A for all A. Given a proof p : list1 A = list2 A, transport (or subst) gives you P (list1 A) -> P (list2 A) for any P. In cubical type theories, such transporting may also compute as expected. To my knowledge, cubical type theory (CCHM or cartesian) is the only setting where this currently works. cubicaltt is the most usable (but still not really practical) implementation.

            Source https://stackoverflow.com/questions/48355427

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install hott

            You can install using 'npm i hott' or download it from GitHub, npm.

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            gh repo clone jon-hall/hott

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