pebbles | Actionable Javascript Library for 0-line AJAX interactions
kandi X-RAY | pebbles Summary
kandi X-RAY | pebbles Summary
Goals of Pebbles: * so easy that a designer could write complicated AJAX! * 0 lines of javascript * complicated ajax websites * 0 lines of javascript * no bugs * 0 lines of javascript * very fast speed and optimality. * backwards compatibility with clients who have javascript off (this was more important 4 years ago when I first made this).
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Trending Discussions on pebbles
QUESTION
I am try to use the following Bootstrap code however it is only showing the first slide and not moving to the next one. Not sure whats going on :(
...ANSWER
Answered 2022-Apr-03 at 13:51If you are on Bootstrap 5 then the answer will be that you're using Bootstrap 3 syntax on one of the attributes.
QUESTION
Input description
The first line of my input contains two numbers: 𝑛 and 𝑑, denoting respectively the number of containers (2 ≤ 𝑛 ≤ 20,000)
and the number of deliveries (not more than 100,000
)
In the following 𝑑 lines there are pairs of numbers: 𝑤 and 𝑧, where 𝑤 is the number of wagons in the delivery
(no more than 20,000
) and 𝑧 is the number of gravel in each wagon (no more than 20,000
).
The total number of wagons from all deliveries will not exceed 1,000,000
.
There will be no situation in any of the inputs where the container will contain more
than 1,000,000,000
gravel.
Problem statement
Wagons are emptied one at a time, evenly into two consecutive containers. These are the rules for determining which two adjacent containers are chosen (where containers[]
denotes a list of the n
current container sizes):
- Among all pairs
(containers[i], containers[i+1])
with0 <= i < n - 1
, choose the pair which minimizesmin(containers[i], containers[i+1])
- If there is a tie, choose among the tied pairs, the pair which minimizes
max(containers[i], containers[i+1])
(i.e. minimizes the second smallest element in the pair) - If there is still a tie, choose the pair
(containers[i], containers[i+1])
with minimum indexi
among the tied pairs.
The gravel is distributed equally into the pair. If there is an odd number of gravel in a wagon, the container with the smaller ID gains the surplus (1 pebble).
At first, all containers are empty.
For example:
...ANSWER
Answered 2022-Mar-06 at 03:59You can solve this much more efficiently by using a min-heap (i.e. priority queue), such as the one provided in Python's standard library. The main purpose of a heap is for efficiently tracking the minimum element of a collection, removing that minimum, and adding new elements, which accurately reflects your problem.
Currently, the line:
QUESTION
I just started using bootstrap, I am trying to use the carousel slide, I am adding the buttons as well as automatic slide. I implemented the bootstrap carousel slide in my code but it is just not moving. I press the button and it still wont move. I don't know what I am doing wrong.
I just edited the code adding the whole script, the problem I am facing is in the testimonials section...
this is my code;
...ANSWER
Answered 2021-Dec-24 at 01:49When I added the bootstrap.min.js
and bootstrap.min.css
reference to the project, I observed that it moves both automatically and manually:
QUESTION
ANSWER
Answered 2022-Jan-11 at 04:45Hey buddy I really don't know if this is the correct way of doing it, but it seems to work just fine. What I did was change the width to max width the make it from 60% to 18%. It looks good and like the lesson. then when you switch it to tablet or mobile, I had the @media function change it back to 60% so it didn't shrink all the way down and look weird. idk if I'm explaining it correctly but here's the code:
QUESTION
I am currenly learning web development in Udemy course of Dr Angela Yu. The "Tintdog" exercise trying to apply the Carousel with controls. The slide does not slide at all even I click the next button. I also included the Bootstrap-5 and Bundle to my page. The code is as below
...ANSWER
Answered 2022-Jan-06 at 18:08Bootstrap 5 uses data-bs-
instead of data-
attributes. It should be data-bs-ride="carousel"
and data-bs-slide
, etc..
QUESTION
I'm trying to make two List
components: one of them is static and small, the second is incredibly large and dynamic. In the first List
I store food categories: Alcoholic products, Soups, Cereals, etc. In the second List
, the word is searched directly from the database - it can be anything: a dish or a category of dishes. Below is the code - it displays the start page. Initially, the first static and small List
is located on it, as well as the Search component (Navigationview.seacrhable()
). When you type a word into the search bar, the first List
disappears and the second one appears. At the moment, both sheets are loaded asynchronously. This is necessary because the second sheet is really big (thousands of rows). This is where my problem begins. Sometimes, when you type a word into the search bar, a copy of this sheet appears on top of it, as shown in the image. It only happens for a fraction of a second, but it's still noticeable. The problem is most likely due to asynchronous loading, before I added it, the List
was loading super slowly, but without such bugs.
My minimal reproducible example:
ContentView.sfiwt
Main List, displaying the food categories available for selection.
...ANSWER
Answered 2021-Nov-19 at 22:27Besides using id
for the IDs, as mentioned in the comments, you can do some refactoring to get SwiftUI to not re-render as much of the view hierarchy and instead reuse components. For example, you have an if
condition and in each you have separate Section
, ForEach
, etc components. Instead, you could render the content of the ForEach
based on the state of the search:
QUESTION
I am trying to do an Optimization problem with PuLP but I am having an issue with writing my objective function.
I've simplified my real-life example to a simpler one using cereal. So let's say I have a list of products and a number of Aisles I can put them into (for this example 2). Each product has a number we normally sell each week (ex: we sell 20 boxes of Fruit Loops and 6 boxes of Cheerios each week). Each item also needs a certain amount of shelves (ex: Frosted Flakes needs 1 shelf, but Corn Flakes needs 2).
Product Sales Shelves Assigned Aisle Fruit Loops 20 2 Frosted Flakes 15 1 Cocoa Pebbles 8 1 Fruitty Pebbles 9 1 Corn Flakes 12 2 Cheerios 6 1Each aisle only has 4 shelves. So in theory I could put Fruit Loops and Corn Flakes together in one Aisle (2 shelves + 2 shelves). If I put those in an Aisle the weekly sales from that Aisle would be 20 + 12 = 32. If I put the other 4 items (1 shelf + 1 + 1 + 1) in an Aisle then that Aisles sales would be 15 + 8 + 9 + 6 = 38. The average sales in an Aisle should be 35. The goal of my optimization problem is for each Aisle to be as close to that Average number as possible. I want to minimize the total absolute difference between each Aisles Total Weekly Sales and the Average number. In this example my deviation would be ABS(38-35) + ABS(32-35) = 6. And this is the number I want to minimize.
I cannot figure out the way to write that so PuLP accepts my objective. I can't find an example online with that level of complexity where it's comparing each value to an average and taking the cumulative absolute deviation. And when I write out code that technically would calculate that PuLP doesn't seem to accept it.
Here's some example code:
...ANSWER
Answered 2021-Oct-19 at 16:15Your main issue here is that the ABS function is non-linear. (So is whatever sorting thing you were trying to do... ;) ). So you have to reformulate. The typical way to do this is to introduce a helper variable and consider the "positive" and "negative" deviations separately from the ABS function as both of those are linear. There are several examples of this on the site, including this one that I answered a while back:
How to make integer optimization with absolute values in python?
That introduces the need bring the aisle selection into the index, because you will need to have an index for the aisle sums or diffs. That is not too hard.
Then you have to (as I show below) put in constraints to constrain the new aisle_diff
variable to be larger than both the positive or negative deviation from the ABS.
So, I think the below works fine. Note that I introduced a 3rd aisle to make it more interesting/testable. And I left a few comments on your now dead code.
QUESTION
I'm trying to make a boxplot where my MFR (manufacturers) are displayed on the x axis and the rating is on the y axis. However I want to color the different boxplots based on the mean shelf value. (Shelf is a value between 1 and 3)
I tried this code:
...ANSWER
Answered 2021-Sep-28 at 08:49ggplot2
QUESTION
I'm trying to display a pebble (message) in my Feed component on my App. I am not entirely sure how to define index currently as everything is just wrapped in Text components for the time being.
Current code -
...ANSWER
Answered 2021-Aug-21 at 01:19const toSend = () => linkTo('/Send')
return (<>
{pebbles.map((pebble, index) => (
{currentUser.name}
{pebble.title}
{pebble.message}
))}
Send New Pebble
)
QUESTION
I am currently taking a course on Udemy and it is about Bootstrap, well the problem is that the course was released since 2018, and now while I am following along, there are a lots things that are not responsive. like text wont get the size assigned to it, or the front assign to it. it is supper annoying. if someone understand what is going on, please help! The is not taking the parameters assigned to it
...ANSWER
Answered 2021-Aug-19 at 17:03Your current layout appears to be responsive. Based on the limited col
classes you have assigned.
However, your issue is not down to responsiveness (how it reacts to viewport changes) but styling. It is likely to do with the order of your stylesheets.
Your Bootstrap styles should be first, followed by your custom styles - CSS - Cascading Style Sheets - You are effectively adding styles on-top of the Bootstrap ones (which is why you will often run into specificity issues with Bootstrap).
What is currently happening is you custom styles are being loaded, then being overwritten by the Bootstrap stylesheet. You of course want this the other way around.
I would suggest something like this
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