koko | KoKo 是 JumpServer 字符协议资产安全连接组件,支持 SSH, Telnet, MySQL, Kubernets, SFTP, SQL Server, Redis

 by   jumpserver JavaScript Version: v3.3.1 License: GPL-3.0

kandi X-RAY | koko Summary

kandi X-RAY | koko Summary

koko is a JavaScript library. koko has no bugs, it has no vulnerabilities, it has a Strong Copyleft License and it has low support. You can download it from GitHub.

Koko 是 JumpServer 连接字符协议的终端组件,支持 SSH、TELNET、MySQL、Redis 等协议。. Koko 使用 Golang 和 Vue 来实现,名字来自 Dota 英雄 Kunkka。.

            kandi-support Support

              koko has a low active ecosystem.
              It has 445 star(s) with 178 fork(s). There are 20 watchers for this library.
              There were 10 major release(s) in the last 12 months.
              koko has no issues reported. On average issues are closed in 92 days. There are 8 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of koko is v3.3.1

            kandi-Quality Quality

              koko has 0 bugs and 0 code smells.

            kandi-Security Security

              koko has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              koko code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              koko is licensed under the GPL-3.0 License. This license is Strong Copyleft.
              Strong Copyleft licenses enforce sharing, and you can use them when creating open source projects.

            kandi-Reuse Reuse

              koko releases are available to install and integrate.
              Installation instructions are not available. Examples and code snippets are available.

            Top functions reviewed by kandi - BETA

            kandi's functional review helps you automatically verify the functionalities of the libraries and avoid rework.
            Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of koko
            Get all kandi verified functions for this library.

            koko Key Features

            No Key Features are available at this moment for koko.

            koko Examples and Code Snippets

            No Code Snippets are available at this moment for koko.

            Community Discussions


            String class with concatenation с++
            Asked 2021-Apr-22 at 16:10

            I recently started learning c++ and I have a problem with implementing my own string class with string concatenation. When the strings are added together, an error appears in debugging : I checked on many lines and noticed that the program works fine when the line is short , but stops working at all with long lines I think I messed up my memory somewhere , but I can't find where I will be very glad of any help



            Answered 2021-Apr-22 at 16:10

            There are a lot of things wrong with your code.

            • Where is your operator=? You appear to have violated the Rule of Three. This is a massive memory bug.
            • for (int i = 1; i <= length; i++) if (i % 2 == 0) seems like a weird way to write for (int i = 2; i <= length; i+=2). This works fine, it's just weird.
            • operator+ does not allocate enough bytes for a null terminator, so all operations after that will read past the end of the buffer. This is a massive memory bug.
            • String(char* str) doesn't make a copy of the data, it assumes ownership of the pointer passed in. Which might work, except that operator+ constructs a String from tmp, and then deletes tmp, so now the String's data is gone. This is a massive memory bug.

            Source https://stackoverflow.com/questions/67216829


            Javafx Is there a better way to add myObjects to GridPane?
            Asked 2021-Apr-17 at 14:54

            i was searching for answer and trying so many options. Finally i found way to pass my own javaxf object to GridPane. But I still think there is a better way to this than I am doing. So here is my code: Main:



            Answered 2021-Apr-17 at 14:54

            As @JimD already commented, embedding a reference to the parent of a Node into a node is bad practice. There's nothing special about the Rectangles other than the event handler which toggles the colour. Assuming that you don't want to access the "selected" state of the Rectangles, you can ditch the custom class altogether.

            The following code does everything that your sample does, except the call to the [not included] "ShelfShowUp.display("KOKOS", 7)" :

            Source https://stackoverflow.com/questions/67137458


            IDictionary Value overwrite
            Asked 2021-Apr-04 at 02:53

            This is my first time when I need to do something with dictionaries. I can't overwrite the item.Value and i don't know how should I do that.

            Write a program that reads the name of one monkey per line from the lines of standard input to the end of file (EOF) and the number of bananas it collects in the following format:

            monkey_name; number of bananas

            The program writes the names of the monkeys and the number of bananas they have collected to the standard output in the form given in the example output, in lexicographically ascending order based on the names of the monkeys!




            Answered 2021-Apr-03 at 14:44
            class Program
                static void Main()
                    string input;
                    string[] row;
                    IDictionary majom = new SortedDictionary();
                    //int i;
                    //bool duplicate = false;
                    while ((input = Console.ReadLine()) != null && input != "")
                        //duplicate = false;
                        row = input.Split(';');
                        // Usually dictionaries have key and value
                        // hier are they extracted from the input
                        string key = row[0];
                        int value = int.Parse(row[1]);
                        // if the key dose not exists as next will be created/addded
                        if (!majom.ContainsKey(key))
                            majom[key] = 0;
                        // the value coresponding to the already existing key will be increased
                        majom[key] += value;
                        //foreach (var item in majom)
                        //    if (item.Key == row[0])
                        //    {
                        //        duplicate = true;
                        //        i = int.Parse(row[1]);
                        //        item.Value += i; I'm stuck at here. I dont know how am i able to modify the Value
                        //    }
                        //if (!duplicate)
                        //    i = int.Parse(row[1]);
                        //    majom.Add(row[0], i);
                    foreach (var item in majom)
                        Console.WriteLine(item.Key + ": " + item.Value);

            Source https://stackoverflow.com/questions/66932130


            Google BigQuery SQL: Extract data from JSON (list and array) into columns
            Asked 2021-Mar-14 at 18:54

            I have table with json string



            Answered 2021-Mar-14 at 18:54

            Below will work for you

            Source https://stackoverflow.com/questions/66624805


            undefined index 'value' in laravel
            Asked 2021-Jan-29 at 04:35

            im using laravel 7 and trying to get datas from api use http.

            when i use dd('$datas'),i got this



            Answered 2021-Jan-29 at 04:35

            If you look at the data you are getting back from the API, your data is actually nested inside objects that live under a manajemen_sdm property.

            Your loop should work correctly if you update it to loop over the manajemen_sdm key:

            Source https://stackoverflow.com/questions/65948736


            Printing different image for different list data
            Asked 2021-Jan-14 at 09:26

            so i made a list and i used tkinter for choosing a random data in list and showing that in a showinfo box. now i was just wondering if its possible to make a random image for random data. for eg i am making a app that generates a random anime name from the list but i want to add the anime picture also is there any way i can do that ? i haven't tried building it but here is what i have made so far.

            i have no error i just want to have different picture for different names from the list chose randomly



            Answered 2021-Jan-14 at 09:26

            Since you want the image to be corresponding to the anime titles I suggest you use a dictionary instead of a list. Also, use Toplevel widget to display the output.

            So here is an example code:

            Source https://stackoverflow.com/questions/65678411


            Web scraping from multiple pages with for loop part 2
            Asked 2020-Dec-21 at 23:03

            My original problem:

            "I have created web scraping tool for picking data from listed houses.

            I have problem when it comes to changing page. I did make for loop to go from 1 to some number.

            Problem is this: In this web pages last "page" can be different all the time. Now it is 70, but tomorrow it can be 68 or 72. And if I but range for example to (1-74) it will print last page many times, because if you go over the maximum the page always loads the last."

            Then I got help from Ricco D who wrote code that it will know when to stop:



            Answered 2020-Dec-21 at 18:44

            Finding your element with class name doesn't seem to be the best idea..because of this. Same class name for all the next elements.

            I don't know what you are looking for exactly because of the language. I suggest..you go to the website>press f12>press ctrl+f>type the xpath..See what elements you get.If you don't know about xpaths read this. https://blog.scrapinghub.com/2016/10/27/an-introduction-to-xpath-with-examples

            Source https://stackoverflow.com/questions/65398056


            Perl, how to make this scripter smaller, faster, better, stronger?
            Asked 2020-Sep-20 at 20:16

            I'm a newbie in perl, how I can make this better and faster? (SPOJ task)



            Answered 2020-Sep-20 at 20:16

            Something which is divisible by 5 and 3 is divisible by 15, so your logic is more straight forward as...

            • Divisible by 15
            • Divisible by 5
            • Divisible by 3
            • Not divisible by 5 nor 3

            I'd also take advantage of say.

            I'd also replace the awkward until with a for and not bother with $i.

            Avoid using $a and $b because these are special variables used by sort.

            Turn on strict and warnings.

            Strip the newline off $a. Technically not necessary if you're going to use it as a number, but if you don't printing it will have an extra newline.

            A non-number % anything is 0. Unless we validate the input, if you input nothing or "bananas" you'll get SPOKOKOKO. We can check if the input looks like something Perl considers a number with Scalar::Util::looks_like_number. If it isn't a number, throw an exception; it isn't the function's job to figure out what to do with a non-number. Perl doesn't really have exceptions, but we can get close with a die and eval.

            And put the logic inside a subroutine. This separates the details of the input and output from the logic. The logic can now be named, documented, tested, and reused. This also avoids the redundant say.

            Source https://stackoverflow.com/questions/63982876


            HTML: How to align left, center, and right footer phrases. Bootstrap
            Asked 2020-Aug-06 at 22:16

            I'm having issues aligning my footer text in a straight line. I'm a beginner here so I apologize if this question is redundant! See below:

            I need all three of those lines, to be in a straight line.

            My professor teaches a grid method, but that's not working for me at the moment. Any suggestions?

            Here is my code:



            Answered 2020-Aug-06 at 22:16


            Problem with a task of printing inward triangle with stars
            Asked 2020-Jul-12 at 15:25
            public class TulosteluaLikeABoss {
                public static void tulostaTahtia(int maara) {
                    // part 1
                    int i = 0;
                    while (maara >i) {
                public static void tulostaTyhjaa(int maara) {
                    // part 1.1
                    int i = 0;
                    while (maara > i) {
                        System.out.print(" ");
                //something is wrong below
                public static void tulostaKolmio(int koko) {
                    // part 2
                    int j = koko;
                    int k = 0;
                    while (koko >= k) {
                        j = j-1;
                // from here below is irrelevant
                public static void jouluKuusi(int korkeus) {
                    // part 3
                public static void main(String[] args) {
                    // Testit eivät katso main-metodia, voit muutella tätä vapaasti.


            Answered 2020-Jul-12 at 15:25

            tulostaKolmio(1) assigns koko the value of 1. The while loop in the method will run (koko + 1) number of times. During the first run in the loop tulostaTahita(0) gets called (since k=0 right now), altough it will not print any starts at this call it will print a new line because you have that outside the while loop in the tulostaTahita method.

            During the second run in the loop, k=1 and thus tulostaTahita(1) is called. This will print another line so in the end you are left with 2 lines (where the first one is empty).

            To solve this you want to add an if statement to make sure tulostaTahita only prints a new line when maara is greater than 0.

            Source https://stackoverflow.com/questions/62862722

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network


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            Install koko

            You can download it from GitHub.


            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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