quid | Collaborative user interface design application | Socket library

for simple text you can split in this way:

Try this

Use the submit event instead of click event

If you have validation (selects MUST have empty option and required to be validated) you will not see the console.logs until the form is valid

Your query does not match your rules. Your rule absolutely requires that the user must only query for specific documents where their UID matches quid field of the document. However, your query doesn't put any requirements on the quid field. It's important to know that Firestore security rules are not filters, and they will not allow a query where there is any possibility of matching a document that does not satisfy the rules as written.

In order to get your query to work, it must specify a filter on the quid field that matches the requirements of the rule.

Does this answer:

basically i have changed list to Map and adding qid as key. when you are printing you will get key and value. from the key which is qid you can get the question details and from value you will have as answers.

Here is list of relevant issues based on your question and comments:

• Usually if the summation is over i, then everything without an i subscript is constant for that sum. (Mathematically these constant terms can just be brought out of the sum; so the first equation is a bit odd where the N_7 could be moved out of the sum but I think they're keeping it in to show the symmetry with the other equations which all have an r*N term).

• The capitol sigma symbol (Σ) means you need to do a sum, which you can do in a loop, but both Python list and numpy have a sum function. Numpy has the additional advantage that multiplication is interpreted as multiplication of the individual elements, making the expression easier. So for a[0]*[b0] + a[1]*b[1] + a[2]*b[2] and numpy arrays is simply sum(a*b) and for Python lists it's sum([a[i]*b[i] for in range(len(a))]

Therefore using numpy, the setup and your third equation would look like:

By default, a stack view's arranged subviews are constrained via the edges of the stack view... not the margins.

You can fix that by setting the stack view's .isLayoutMarginsRelativeArrangement property to true:

You can try this:

This is what I would do (not seeing the full code it is hard to write a full solution (also this will eat up a lot of memory, but again - in order to optimize this I would need to see the code; what I write has a benefit of being simple to implement and not require locking).

So the recommendation is:

1. create cr2_vec = [copy(cr1) for i in 0:499]
2. in outer loop write cr2 = cr2_vec[k]
3. Then do all the processing on cr2
4. after the @threads loop finishes take cr2_vec, which will have updated data frames and from each data frame of this vector take the columns that are needed and add it to your original cr1 data frame.

A more advanced solution would be not to use a vector of data frames, but just a single data frame, as you do, but after the computing is done use a lock and within a lock update the global cr1 with only the computed columns (you need to use lock to avoid race condition).

EDIT

An example of a more efficient implementation: