p2p | This is a WebRTC / P2P primitive based on Useless
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kandi X-RAY | p2p Summary
This is a WebRTC / P2P primitive based on Useless.
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QUESTION
I want to download this file and print its contents to the console using an in-browser IPFS node. The following html file should do the job:
...ANSWER
Answered 2021-May-29 at 17:51You don't have any bootstrap nodes, so it can't find the CID. If you add my node for example, it works fine:
QUESTION
I want to consume Business Central Web service so I can add it to an existing web application.
I have tried:
- Testing with Postman using Authorization header (works)
- Testing SoapUI (works)
But I am getting this error:
...ANSWER
Answered 2021-May-20 at 12:35You need to make sure that the user you are trying to authenticate with has a Web Services Access Key.
Then you must use the Web Services Access Key as the password when authenticating.
It does also appear that you are missing a space
after Basic
in this line of code:
QUESTION
now in client app.config:
...ANSWER
Answered 2021-May-24 at 07:16 private NetTcpBinding binding = new NetTcpBinding();
private EndpointAddress endPoint;
private void initial_binding()
{
binding.Security.Mode = SecurityMode.None;
binding.HostNameComparisonMode = HostNameComparisonMode.WeakWildcard;
binding.ReliableSession.Enabled = false;
}
initial_binding();
endPoint= new EndpointAddress(@"net.tcp://" + 191.14.3.11+ @":4000/FileServer");
var IAChannelFactory = new ChannelFactory(binding,
endpoint);
IFileService Client = new FileService();
try
{
client.anyFunction();
}
catch (Exception ex)
{
Logger.Log.Error(ex.Message);
}
QUESTION
I am working through the course "Build a Blockchain and Cryptocurrency From Scratch from Udemy. I have no prior experience with NodeJS I have been following along with the instructor's code, but recently hit a snag that I cannot resolve. When trying to build the project to run test scripts via npm run dev
, I get the following error:
ANSWER
Answered 2021-May-03 at 13:54The problem is at the export of the P2pServer class should be like this (exports and not export):
QUESTION
public string prospect(List prospectRequest, String primaryClientId) {
if(p2p(primaryClientId)=="Success") {
for(ProspectRequest prospect : prospectRequest) {
p2p(prospect.getId());
}
// rest of code i would like to continue
}
}
public string p2p(String id){
crmApi.getProspectId(id);//this is external client api
String message = "Success";
return message;
}
...ANSWER
Answered 2021-May-17 at 08:16Seems like you just need to use a try catch finally block
QUESTION
I've been learning flask-socketio. The aim is to make a p2p-like (should not be correctly saying) chat app using socket-io which works in a LAN. All the users have static IP address which everyone knows. There are 4 devices in LAN. Each going to install the flask-app in their own system. This is the app.py and chat.html(client in JS)
This is the app.py
ANSWER
Answered 2021-May-14 at 14:37yes, you can. you just have to put them in different variables.
QUESTION
I'm working on filtering a website's data and looking for keywords. The website uses a long JSON body and I only need to parse everything before a base64-encoded image. I cannot parse the JSON object regularly as the structure changes often and sometimes it's cut off.
Here is a snippet of code I'm parsing:
...ANSWER
Answered 2021-May-12 at 19:09Regular expression should work here. Try matching with the following regular expression. It matches the desired sections, when I try it in https://regexr.com/. Also, regexr helps you understand the regular expression, in case you are new to it.
QUESTION
I'm building a personal project that makes a one-to-many connection with other users, this what my plan looks right now:
- User Initiates a P2P connection with the C++ Server
- The C++ Server Initiates a P2P Connection with other clients and forwards the stream of the broadcaster
I'm planning to use the WebRTC C++ API available on Google Code Repo. Firstly, is this possible, and secondly is this approach reasonable(and possible) excluding the resource usage factor?
Thanks,
-- Nav
...ANSWER
Answered 2021-May-06 at 23:24"Firstly, is this possible?"
Yes
"secondly is this approach reasonable?"
Yes
That's exactly what media servers do.
QUESTION
I am currently doing this tutorial. And on the same machine it worked as expected: The nodes are connecting and are creating and finalizing blocks. But now I want to do the same over the internet. So I have a server (Ubuntu 16.04 xenial) with open port 30333 on which I am running this command:
...ANSWER
Answered 2021-Mar-27 at 19:10I did reclone and recompile both nodes and somehow it's working now. I did not change anything in the command except the --no-mdns flag.
QUESTION
I have a virtual network for testing built with VMWare Workstation 15. Everything works fine with the virtual network but I have an issue I can't fix.
From what I've understood the Virtual Network in VMWare (the one called VMnetx where x is a number) works as virtual switches. You create a virtual network with a subnet in the virtual network manager. Once you want to connect a machine into the virtual network, you select that network on your interface and everything works great.
The problem is if I want a P2P connection (basically a virtual cable connected as a bridge between two machines in the same subnet).
I tried to create another virtual network with the same subnet so I can attach the two network adapter only to this newly created virtual network (which should have the same subnet) but VMWare won't let me create another virtual network with the same subnet.
Is there a way to connect two machines point2point on the same subnet of a virtual network already created without having to use the virtual switch?
PS all my machines run Linux server 20.04.2 LTS
...ANSWER
Answered 2021-Apr-06 at 12:32Unfortunately, there's no way to do that. A solution would be to create a USB virtual dongle to connect both machines.
The best solution remains to use a network interface connected to the virtual network and set Machine 2 to use Machine 1 as Default Gateway (you will no more need the 10.1.0.5 interface)
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