fathom | Fathom.js - Present JavaScript in its native environment

 by   markdalgleish JavaScript Version: Current License: MIT

kandi X-RAY | fathom Summary

kandi X-RAY | fathom Summary

fathom is a JavaScript library. fathom has no vulnerabilities, it has a Permissive License and it has low support. However fathom has 5 bugs. You can download it from GitHub.

If you want to contribute in a way that changes the API, please file an issue before submitting a pull request so we can dicuss how to appropriately integrate your ideas.
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              fathom has a low active ecosystem.
              It has 530 star(s) with 59 fork(s). There are 22 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 5 open issues and 9 have been closed. On average issues are closed in 235 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of fathom is current.

            kandi-Quality Quality

              fathom has 5 bugs (0 blocker, 0 critical, 5 major, 0 minor) and 0 code smells.

            kandi-Security Security

              fathom has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              fathom code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              fathom is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              fathom releases are not available. You will need to build from source code and install.
              Installation instructions, examples and code snippets are available.
              fathom saves you 129 person hours of effort in developing the same functionality from scratch.
              It has 324 lines of code, 0 functions and 7 files.
              It has low code complexity. Code complexity directly impacts maintainability of the code.

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            fathom Key Features

            No Key Features are available at this moment for fathom.

            fathom Examples and Code Snippets

            No Code Snippets are available at this moment for fathom.

            Community Discussions

            QUESTION

            Different output depending on whether or not I print the return value
            Asked 2021-Jun-01 at 20:08

            So I have a simple snippet of C++ code which is SUPPOSED to insert a node into a binary search tree. It returns true if the value is successfully inserted and false if the value is already in the tree.

            ...

            ANSWER

            Answered 2021-Jun-01 at 20:08

            You invoke undefined behaviour right there:

            Source https://stackoverflow.com/questions/67794928

            QUESTION

            Loopback 3 updateAll filter is not working
            Asked 2021-Jun-01 at 15:53

            I have the following model in Loopback 3:

            ...

            ANSWER

            Answered 2021-Jun-01 at 15:53

            So the problem was that my function was receiving testId directly from the object test, as test.id.

            This id, even if it's displayed as a string in the console.log, internally it's an object, so nothing was comparing correctly because of this.

            When I changed test.id with "${test.id}" everything worked.

            I'll proceed to kill myself now, thank you.

            Source https://stackoverflow.com/questions/67726163

            QUESTION

            Django site suddenly requiring users to clear their cookies to get a CSRF token
            Asked 2021-May-18 at 11:58

            I run a Django site that hasn't undergone any updates in the last few months, yet all of a sudden I'm receiving a bunch of emails from users saying they're getting the following error:

            ...

            ANSWER

            Answered 2021-May-18 at 11:58

            Thanks for your comments and suggestions! I ended up figuring out what was going on.

            So for some reason, Django won't create a new CSRF cookie (even if it has been expired/deleted) if the session cookie is still valid. This seems like a bug, but maybe there's a security reason for it.

            In my case, I had extended SESSION_COOKIE_AGE to 60 * 60 * 24 * 365 * 10, or 10 years. It turns out the default value for CSRF_COOKIE_AGE is 1 year. As such, everyone that had been logged in for a year no longer had a valid CSRF cookie, and Django wouldn't issue them a new one because their session was still valid for another 9 years.

            Source https://stackoverflow.com/questions/67504249

            QUESTION

            How do you write redux reducers for wide data types?
            Asked 2021-May-11 at 17:27

            I'm currently working on a project that implements something similar to MS Project - A task management app with very wide task properties.

            A super simple definition of a task might be like:

            ...

            ANSWER

            Answered 2021-May-11 at 17:19

            Assuming you have tasks like:

            Source https://stackoverflow.com/questions/67491341

            QUESTION

            Input order and scoring
            Asked 2021-May-07 at 13:35

            Hello fellow OptaPlanner enthusiasts,

            At my company we are trying to build a product based on OptaPlanner but we are running into a maddening situation. We have about 15 constraints, with various penalties and weightings.

            Our main problem is, it seems that sometimes, especially in blindingly obvious situations, OP does not move the entities into positions that will satisfy our scoring system. We examine each case manually, and we always ask ourselves: "Why can't it put entity X here???".

            In each problematic case, all constraints would be satisfied, and the score would be 0/0/0 or better, if OP would just move certain entities into the right place. It seems that it decides early on, in its planning, that certain entities can never move to, or move back, to certain positions.

            Another complicating factor is that sometimes if we change the input order, the problem will be solved.

            Overall, it seems that there is a magic under the hood that OP uses that we can't fathom. Could anyone offer some comments before I start dumping code into this question?

            Thank-you so much, JO

            ...

            ANSWER

            Answered 2021-May-07 at 13:35

            This question is very vague, therefore so is the answer.

            The most important point: there is no way to guarantee that OptaPlanner will find any particular solution, good or bad. If we knew how to reach into the search space and pull out a solution, we would not need OptaPlanner in the first place.

            That "magic" under the hood that you mention is randomness. Unless you use REPRODUCIBLE environment mode (or the assert modes when not in production), OptaPlanner will never take the same path through the myriad possible solutions. OptaPlanner has no way of knowing if a better solution is just around the corner. It will simply try a random change, and see what happens. And it will use some smart heuristics to guess which is the best way to go from there.

            OptaPlanner's way through the search space will be largely random, only guided by the constraints. And you need to take care and design your constraints very carefully. Most important in my opinion is to make sure you do not introduce score traps. A score trap is a situation where two vastly different solutions result in the same score. If the scores are the same, then the solutions are considered to be of equivalent quality. If you, as a human, can see that two solutions are qualitatively different yet their scores are the same, I suggest you figure out how to convert your insight into a constraint.

            Once your constraints describe your problem as best as can be, the next goal is performance of the scoring function. OptaPlanner will find good solutions, assuming it has enough time to search. One way is to give it hours or days. Another way is to speed up the scoring function. This is a major topic on its own, and it is not really possible to give advice here without knowing the specifics of the problem. One general guideline: if your average score calculation count is on the order of hundreds or lower thousands per second, you have some work to do to help OptaPlanner help you. The more random changes you can process per second, the bigger your chance is of finding a good solution given the same amount of computation time.

            And lastly, I am going to touch on your point of the input order. Yes, every time you change the input order, OptaPlanner will give different results. Even if you choose the REPRODUCIBLE environment mode - because your problem is suddenly different due to the input order. To avoid that, you should either make your order consistent, or you should look into planning entity difficulty and planning value strength to do the same for you.

            EDIT: It is a downside of OptaPlanner that, on small data sets, we can (due to the nature of randomness) miss seemingly obvious good solutions, and a human would spot that. On these small data sets, using brute force is an obvious way to go - see branch and bound for example. But as the data sets grow larger, this will not scale and OptaPlanner's local search will significantly outperform anything any human can do. That is where OptaPlanner shines, and that is where it should be used.

            Source https://stackoverflow.com/questions/67425108

            QUESTION

            How do I hide a button using Swift5 when an 'if' condition is true?
            Asked 2021-Apr-16 at 20:21

            I am trying to hide a button called "itemOneDelete" when a label ("itemOneLabel") on my View Controller is empty, by using an 'if' loop to change the visibility of the button to "alpha = 0" by using the following code:

            ...

            ANSWER

            Answered 2021-Apr-16 at 20:20

            You're trying to call .alpha on the function itemOneDelete. What you probably want instead is:

            Source https://stackoverflow.com/questions/67131699

            QUESTION

            Filling missing data using a custom condition in a Pandas time series dataframe
            Asked 2021-Apr-16 at 17:57

            Below is a portion of mydataframe which has many missing values.

            ...

            ANSWER

            Answered 2021-Apr-16 at 17:52

            Here is a completely vectorized way to do this. It is very efficient and fast: 130 ms on a 1000 x 1000 matrix. This is a good opportunity to expose some interesting techniques using numpy.

            First, let's dig a bit into the requirements, specifically what exactly the value for each cell needs to be.

            The example given is [nan, nan, nan, nan, 4.0] --> [.66, .72, .79, .87, .96], which is explained to be a "progressively increasing value of 10%" (in such a way that the total is the "value to spread": 4.0).

            This is a geometric series with rate r = 1 + 0.1: [r^1, r^2, r^3, ...] and then normalized to sum to 1. For example:

            Source https://stackoverflow.com/questions/67123272

            QUESTION

            Target value with torch.nn.MultiLabelSoftMarginLoss should be 0 or -1?
            Asked 2021-Apr-07 at 06:54

            I have a multi-label classification problem (A single sample can be classified as several classes at the same time).

            I want to use torch.nn.MultiLabelSoftMarginLoss but I got confused with the documentation where the ground truth are written like this :

            ...

            ANSWER

            Answered 2021-Apr-07 at 06:54

            Look closer at the doc:

            The targets are expected to be {0, 1} and not -1.
            I'm not sure what this -1 is doing, it might be for "ignore", but you are correct that the doc there is not very clear.

            There is an open issue on pytorch's github about this. Feel free to contribute.

            Source https://stackoverflow.com/questions/66979824

            QUESTION

            Laravel: Cannot declare class App\Models\Customer, because the name is already in use
            Asked 2021-Apr-02 at 22:38

            I'm a bit perplexed. I have a simple method on my User (actually "Customer") model to return a user's subscription renewal date:

            ...

            ANSWER

            Answered 2021-Mar-19 at 17:51

            Are you update your relations in database ? Maybe you should refresh your migrations on production server.

            If you're using a model other than Laravel's supplied App\Models\User model, you'll need to publish and alter the Cashier migrations provided to match your alternative model's table name.

            Another possible problem is that you have not set up a proper model for the auth.

            Source https://stackoverflow.com/questions/66643550

            QUESTION

            selecting all rows after a condition, multple times, on filtered/groupby dataframe
            Asked 2021-Mar-27 at 10:10
            import pandas as pd
            import numpy as np
            df = pd.DataFrame({'game': [20101,20101,20101,20101,20101,20101,20101,60734,60734,60734,60734,60734,60734,60734],
                               'hit': ['n','n','n','y','n','y','n','n','n','n','y','n','n','n'],
                               'score':[2,1,0,2,1,0,2,0,3,4,2,3,3,1]
                               },)
            
                game    hit score
            0   20101   n   2
            1   20101   n   1
            2   20101   n   0
            3   20101   y   2
            4   20101   n   1
            5   20101   y   0
            6   20101   n   2
            7   60734   n   0
            8   60734   n   3
            9   60734   n   4
            10  60734   y   2
            11  60734   n   3
            12  60734   n   3
            13  60734   n   1
            
            ...

            ANSWER

            Answered 2021-Mar-27 at 10:10
            x = df.groupby("game")[["hit", "score"]].apply(
                lambda x: x.loc[(x["hit"] == "y").cumsum() > 0, "score"].sum()
            )
            print(x)
            

            Source https://stackoverflow.com/questions/66829895

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install fathom

            The code is minified using UglifyJS using the following command:.

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