rfc | Pretty RFC indexes and reformats RFC documents
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kandi X-RAY | rfc Summary
Pretty RFC indexes and reformats RFC documents for easier discovery and viewing.
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rfc Key Features
rfc Examples and Code Snippets
def decode_csv(records,
record_defaults,
field_delim=",",
use_quote_delim=True,
name=None,
na_value="",
select_cols=None):
"""Convert CSV records to tensors.
def rfc_2822_format(date_str):
"""Convert yyyy-mm-dd date string to RFC 2822 format date string."""
d = datetime.datetime.strptime(date_str, '%Y-%m-%d')
return d.strftime('%a, %d %b %Y %H:%M:%S +0000')
Community Discussions
Trending Discussions on rfc
QUESTION
I have getting Swift_RfcComplianceException error while sending the mail
My code is like
...ANSWER
Answered 2021-Jun-11 at 11:55It look like passed variable $fromEmail
,$toEmilId
,$fromName
, are empty.
Also make sure to trim $fromEmail
,$toEmilId
.Even if your email contain space begining or at the end also you get error.
For example i have given space in $fromEmail
then i get following error
QUESTION
I am trying to redirect my browser to a local html file via a SpringBoot app controller. When I attempt to do this, I received the following error:
...ANSWER
Answered 2021-Jun-07 at 12:32You probably have to encode the string, otherwise there are characters that are not allowed in a URL (for example
-> %20
), so please try with this URL
QUESTION
Am using https://spatie.be/docs/laravel-backup/v7/introduction for backup and I tried to backup database using php artisan backup:run
but i got these errors:
ANSWER
Answered 2021-Jun-06 at 15:29Laravel doesn't have official command to take db backup which you mentioned
You must use following package
https://spatie.be/docs/laravel-backup/v7/installation-and-setup
To know laravel default php artisan commands .You can run following command to defualt commands available in php artisan.
QUESTION
I receive the following payload from an external system. I need to return only the value of the "Cert Hash(sha256)" e.g. 267c797962b5ee69afd7fed3edc3fb41359a08a107fd801ddd5c5fd5925c09bb. This will change for each payload. I'm not great at regex so any help would be apprecitaed.
...ANSWER
Answered 2021-Jun-05 at 05:05You don't really need regex to find the string, you can try:
QUESTION
I have the following ASN1 ASN.1 dump
...ANSWER
Answered 2021-May-27 at 07:03The document hash is not calculated from the original PDF you want to sign. That PDF first is prepared for signing by applying certain changes, and then the hash is calculated from this prepared PDF except a placeholder gap in it prepared to later house the signature container.
In DetailTo create an integrated PDF signature, certain changes have to be applied to the PDF:
- The holder of the to-be-integrated signature is an AcroForm form field in the PDF. If the PDF does not contain an empty, unused signature field (or no existing field shall be used), a new signature field has to be added to the PDF.
- A signature form field may have a visualization, a widget annotation, which represents the signature on some page of the document itself. If such a visualization is desired, a matching annotation has to be added to the PDF.
- Information describing the mode and other details of signing have to be added to the PDF. Thus, the value of the chosen signature field has to be set to a new dictionary object in the PDF with these signature details; there are two special entries here, the ByteRange and the Contents. Both are set to blank values of appropriate size for starters.
- A marker is added to the PDF root AcroForm object indicating that the PDF is signed.
With these additions the PDF is stored. Thereafter the position of the Contents value in the file is fixed and the blank value of the ByteRange value is patched to an array of four integers, the start offset and size of the file segment before the Contents value and the start offset and size of the file segment thereafter.
Then the bytes of these segments of the file are hashed and a CMS signature container signing this document hash is generated which in turn is injected into the Contents value.
In your case the hash you find in the to-be-signed attributes,
QUESTION
I try to connect with an FTP server with apache-commons-net-3.7.2 (implicit TLS, double factor authentication with client cert + login/password).
I can authenticate myself, enter in passive mode, but the client doesn't succeed in connecting to the server in order to get data by the data socket.
I can connect myself, on the same computer, with WinSCP (same settings). I have activated WinSCP logs to see protocol details, and I have adjusted my source code with the same options. I can verify that my protocol is ok with a ProtocolCommandListener
. I know that passive mode is required because WinSCP emits PASV
command.
I can see that WinSCP connects to the data socket on port 62564 (I have replaced FTP IP address with XXX)
...ANSWER
Answered 2021-Jun-01 at 06:26Your assumption is wrong. You do not set the port. The server tells you what port to connect to.
For WinSCP:
2021-01-06 10:25:35.575 227 Entering Passive Mode (192,168,4,122,244,100).
...
2021-01-06 10:25:35.575 Connexion à 83.XXX.XXX.XXX:62564...
Where 62564 = (244 << 8) + 100
See RFC 959, section 4.1.2. Transfer parameter commands, Page 28.
The parsing of the PASV
response fails, because you are using a wrong code. The _parseExtendedPassiveModeReply
is for EPSV
. For PASV
, use _parsePassiveModeReply
. There you will also see the implementation of the above formula:
QUESTION
I'm porting some code from IronPython to CPython (3.8) + Python.NET and I have a custom class that's broken in an odd way: it gives me an AttributeError
even though the member is present in __dict__
. This class derives from uuid.UUID
to add support to BLE short UUIDs:
ANSWER
Answered 2021-May-28 at 17:06Here's what I mean:
QUESTION
I'm calling ME_INFORECORD_MAINTAIN_MULTI
with an RFC. The purchase info records get a new number, but the changes aren't commited to the db.
The commit is supposed to be implicit after a RFC, but it isn't. I've tried adding an explicit COMMIT WORK
after the function call, but this didn't help.
The changes are commited properly if I use a regular function call (not remote), however performance is very slow.
Please help.
...ANSWER
Answered 2021-May-19 at 12:24I've solved this by making a wrapper function that ends with a commit, and calling the wrapper function instead of the standard function.
QUESTION
I want to implement my own SMTP server for learning and personal interest purposes, and have some concerns/questions about SMTP protocol
.
The SMTP protocol has it's initial RFC-821, but has been updated/extended several times over the years. As SMTP's wiki page says:
The ESMTP format was restated in RFC 2821 (superseding RFC 821) and updated to the latest definition in RFC 5321 in 2008
But when I check RFC 5321, I still see Updated by: 7504
. Why is that?
Is there one RFC about SMTP that covers it fully up to current date? And if not, what's the reading path/order I should follow to get familiar with SMTP and make sure I'm not missing anything?
...ANSWER
Answered 2021-May-18 at 21:50Start with RFC0821.
If there is an "Updated by:" link, open a new tab for that protocol extension/clarification document and proceed to follow these same steps for that document.
If there is an "Obsoleted by:" link, follow that to a newer version of the same spec.
Lather. Rinse. Repeat.
Until the latest version of all documents have been found and the latest versions of all updates to those specifications are found.
Then google search for more SMTP extensions and implement the ones you are interested in.
QUESTION
I am using Rfc2898DeriveBytes
to generate an AES
key and iv
. However, I heard that the iv
should not be dependent on the password. Here's how I'm doing it right now:
ANSWER
Answered 2021-May-17 at 18:11Many cryptographic algorithms are expressed as iterative algorithms. E.g., when encrypting a message with a block cipher in CBC mode, each message "block" is first XORed with the previous encrypted block, and the result of the XOR is then encrypted. The first block has no "previous block" hence we must supply a conventional alternate "zero-th block" which we call "initialization vector". Generally speaking, an IV is whatever piece of data is needed to begin running an algorithm, and is not secret (if it was secret, we would call it a "key", not an IV).
IV is an arbitrary constant so any value will work. Make sure your encryptor and decryptor uses the same value. For more info you can refer these links:
https://crypto.stackexchange.com/questions/732/why-use-an-initialization-vector-iv
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