Regex-Find | Firefox addon .

by mortalis13 JavaScript Version: 1.2.0 License: No License

X-Ray Key Features Code Snippets Community Discussions(6)Vulnerabilities Install Support

kandi X-RAY | Regex-Find Summary

Regex-Find is a JavaScript library. Regex-Find has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

The addon offers basic regex search functionality with these limitations:.

Support

Quality

Security

License

Reuse

Support

Regex-Find has a low active ecosystem.

It has 31 star(s) with 4 fork(s). There are 7 watchers for this library.

It had no major release in the last 12 months.

There are 10 open issues and 4 have been closed. On average issues are closed in 290 days. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of Regex-Find is 1.2.0

Quality

Regex-Find has 0 bugs and 0 code smells.

Security

Regex-Find has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

Regex-Find code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

Regex-Find does not have a standard license declared.

Check the repository for any license declaration and review the terms closely.

Without a license, all rights are reserved, and you cannot use the library in your applications.

Reuse

Regex-Find releases are available to install and integrate.

Top functions reviewed by kandi - BETA

kandi has reviewed Regex-Find and discovered the below as its top functions. This is intended to give you an instant insight into Regex-Find implemented functionality, and help decide if they suit your requirements.

Find a regular expression .
get the last selection
Returns an array of lines for the given node .
Updates the selection .
Normalizes the pattern output
Performs regular expression on the current search field .
Clears the selection .
Sum each node in the text node .
Updates the UI and updates the UI state .
Get the results from a single line node

Get all kandi verified functions for this library.

Regex-Find Key Features

No Key Features are available at this moment for Regex-Find.

Regex-Find Examples and Code Snippets

No Code Snippets are available at this moment for Regex-Find.

Community Discussions

Trending Discussions on Regex-Find

Retrieving data from map returns null

Javascript Regex: find & REPLACE letters that repeat LESS THAN a certain number of times

Kotlin: Find the first line of a file that matches a regex, and return captured values

Regex to match every line with a 5 character or more string but that doesn't have printf in line

Replace Comma Outside Double Quote - Python - Regex

Remove characters after last occurrence of delimiter - but keep characters when delimiter occurs once at the beginning

QUESTION

Retrieving data from map returns null

Asked 2022-Feb-18 at 20:17

I'm trying to retrieve info from a map.

The map looks like this:

$VideoIDs:

...

ANSWER

Answered 2022-Feb-18 at 20:17

This goes about filtering objects in an array in PowerShell, a good documentation to have a good concept on this is probably Where-Object even though there are many ways of accomplishing this some more efficient than others.

Given the array of pscustomobject you currently have:

Source https://stackoverflow.com/questions/71179154

QUESTION

Javascript Regex: find & REPLACE letters that repeat LESS THAN a certain number of times

Asked 2021-Jul-08 at 02:06

This question is a derivative from another one here:

Say, for the string "lllrrrrrrrruuddddr", how to replace those letters that repeat less than 4 times with "-", thus resulting in "---rrrrrrrr--dddd-".

...

ANSWER

Answered 2021-Jul-08 at 02:06

The easiest way is the simplest way.

[a-zA-Z] matches a single ASCII letter
([a-zA-Z]) is a capturing group
\1 is a backreference that tells us to match again exactly what was matched by capturing group #1 again
\1* tells us to match that backreference zero or more times

Then you just need this:

Source https://stackoverflow.com/questions/68294470

QUESTION

Kotlin: Find the first line of a file that matches a regex, and return captured values

Asked 2021-Mar-16 at 12:34

i want get text from a file by using regEx and want save the file with a new name (using the results of the regEx-Find).

My Problem is that i cant get/return the correct genearated (in this example xyz maur) out of the function readFileLineByLineUsingForEachLine(fileName: String) the new newFileName which was generated (sucessfully as expected) in the function.

Line 1 of Source:

start {"Name":"xyz","Civ":"maur","Team":0}

My Prototype:

...

ANSWER

Answered 2021-Mar-16 at 12:29

Because you want to stop processing as soon as you find a match, I don't think forEachLine is the best choice. Instead you can use useLines, and combine it with first to stop processing once you get a match:

Source https://stackoverflow.com/questions/66647626

QUESTION

Regex to match every line with a 5 character or more string but that doesn't have printf in line

Asked 2020-Sep-16 at 03:45

I'm trying to find every string in a program longer than N characters (5 in this test) but only on lines that don't contain the word "printf" (or maybe "printf\s*(")

These all fail

...

ANSWER

Answered 2020-Sep-16 at 02:29

Try this: (?


Test on regex101.com

Source https://stackoverflow.com/questions/63894812

QUESTION

Replace Comma Outside Double Quote - Python - Regex

Asked 2020-Jul-18 at 17:13

I want to open a CSV file, using open(). I read it per line. For some reason, I'm not using Pandas.

I want to replace comma , with _XXX_, but I want to avoid replacing commas inside double quotes " because that comma is not a separation tag, so I can't use:

...

ANSWER

Answered 2020-May-31 at 12:33

You may use a re.sub with a simple "[^"]*" regex (or (?s)"[^"\\]*(?:\\.[^"\\]*)*" if you need to handle escaped sequences in between double quotes, too) to match strings between double quotes, capture this pattern into Group 1, and then match a comma in all other contexts. Then, pass the match object to a callable used as the replacement argument where you may further manipulate the match.

Source https://stackoverflow.com/questions/62110671

QUESTION

Remove characters after last occurrence of delimiter - but keep characters when delimiter occurs once at the beginning

Asked 2020-May-28 at 13:02

Sorry for the awkward title - very open for suggestions how to better phrase it...

This is very similar to Question 1, Question 2 and question 3. All those questions have a solution that would remove after "every last" occurrence of the delimiter (most often the underscore), including when it occurs at the beginning of the string.

I need to keep those strings where the delimiter occurs only once, at the beginning of the string.

In the example, for x[3] and x[5], I'd like to keep "-3" and "-5". My first attempt keeps -5, but not -3...

...

ANSWER

Answered 2020-May-27 at 14:21

Using str_match :

Source https://stackoverflow.com/questions/62045224

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install Regex-Find

You can download it from GitHub.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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