simplify-js | High-performance JavaScript polyline simplification library
kandi X-RAY | simplify-js Summary
kandi X-RAY | simplify-js Summary
Simplify.js is a high-performance JavaScript polyline simplification library by Vladimir Agafonkin, extracted from Leaflet. Checkout the demo with docs:
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Top functions reviewed by kandi - BETA
- square distance from point to a segment
- simplification logic for simplification
- Steps through the step algorithm .
- simplification algorithm
- simplification using Douglas - Peucker algorithm
- square distance between two points
simplify-js Key Features
simplify-js Examples and Code Snippets
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QUESTION
i have got array of points (x,y) and i need to reduce points of polygons. i would like use Simplify.js (It uses a combination of Douglas-Peucker). But i have got problem:
...ANSWER
Answered 2018-Oct-22 at 09:13At first remove last point of test to convert your polygon to polyline, then balance your tolerance
. If your points are cordinate on the earth, 1 means at least 50 mi (80 km)!!!
Try 0.001 for tolerance
QUESTION
I am trying to make free hand drawing sketchpad in threeJS. Most of the part has been done and able to draw the shapes. Now my next step is to use the simplify-JS for simplifying the points in my polygon. The concern is that I am passing my array as buffer geometry and using Line Mesh to draw on screen. I am creating array like [x,y,z,x,y,z,x,y,z... and so on] till MAX_POINTS which is 10000 in my case. Example
...ANSWER
Answered 2018-Jun-20 at 04:15You can use a simple for loop to traverse the array and push objects in a new array.
QUESTION
I am trying to understand this code.
What I understand is that the code tries to refine the geometry based on a tolerance. Basically it checks if the distance between two points is less than the tolerance or not, and retains/removes the points accordingly.
I have a query though. Points are in lat-long format. The code simply calculates a square of the Euclidean distance(simple square formula we all know). Isn't this a wrong approach as lat-long based distance is different from Euclidean distance?
Second, what is the unit of tolerance? In this test, the tolerance value of 5 is used. How does this value fit in here?
...ANSWER
Answered 2018-Apr-08 at 09:19What I understand is that code tries to refine the geometry based on tolerance. Basically it checks if distance between two points is less than tolerance or not, and retains/removes the points accrdingly.
Yes, that's a first step, in the second step it tries to find consecutive lines that are (basically) in line and merges them.
I have a query though. Points are in lat-long format. Code simply calculates square of the Euclidean distance(simple square formula we all know). Isn't this a wrong approach as lat-long based distance are different from Euclidean distance?
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