opz | MIDI parser for OP-Z sequencer by teenage engineering | Audio Utils library

 by   nbw JavaScript Version: v1.0.1 License: MIT

kandi X-RAY | opz Summary

kandi X-RAY | opz Summary

opz is a JavaScript library typically used in Audio, Audio Utils applications. opz has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can install using 'npm i opzjs' or download it from GitHub, npm.

Parser for midi received from teenage engineering's OP-Z sequencer. Decodes events from the Web MIDI API. Also refer to Mozilla's documentation.
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              opz has a low active ecosystem.
              It has 36 star(s) with 3 fork(s). There are 1 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 0 open issues and 1 have been closed. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of opz is v1.0.1

            kandi-Quality Quality

              opz has no bugs reported.

            kandi-Security Security

              opz has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              opz is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              opz releases are available to install and integrate.
              Deployable package is available in npm.
              Installation instructions, examples and code snippets are available.

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            opz Key Features

            No Key Features are available at this moment for opz.

            opz Examples and Code Snippets

            No Code Snippets are available at this moment for opz.

            Community Discussions

            QUESTION

            Exception being thrown from function that is not being executed
            Asked 2021-Apr-02 at 12:01

            I do not understand why an exception is constantly thrown when, during line-by-line debugging, it does not even enter the function.

            My code:

            ...

            ANSWER

            Answered 2021-Apr-02 at 10:42

            [...] it does not even enter the function.

            That's true, because num2 = -2, the string "Your base num less than zero" is thrown but it's not caught, throwing strings around is not something one would recommend. I suggest you wrap it in an actual exception and throw it instead.

            The conditions will be as follows:

            Source https://stackoverflow.com/questions/66917169

            QUESTION

            Golfing a script that extract citations from a LaTeX document
            Asked 2019-Oct-02 at 22:34

            I was trying to extract all the citations from a LaTeX file, that is, being able to extract everything in between the two curly braces following \cite (ie, \cite{bla,blo} would give me bla and blo). There are a few corner cases: \cite{} may contain one or more citations separated by comma (and there is no comma if there is only one citation) and the \cite{} command may span over multiple lines.

            So far, I came up with the following one liner which works well:

            ...

            ANSWER

            Answered 2019-Oct-02 at 15:51

            Could you please try following(since I am on mobile couldn't test it, should work but).

            awk -v RS="" '{while(match($0,/\\cite{[^}]*/)){val=substr($0,RSTART+6,RLENGTH-6);array[val]++;$0=substr($0,RSTART+RLENGTH)}} END{for(i in array){if(array[i]==1){gsub(/,/,ORS,i);print i}}}' Input_File

            Edit:

            Source https://stackoverflow.com/questions/58197580

            QUESTION

            the call to a function does not correspond to any overload of
            Asked 2019-Mar-28 at 08:25

            I'm developing a java library to manage different kinds of barcode in Crystal Report. Crystal Report offers a sdk for Eclipse and inside a new project there are library to develop the integration between a ERP and CR. One of this library manage barcodes, but is a poor library because I can manage just a kind of barcode. I found a document to implement UFL. The document offers a simple example and thanks of that I wrote some class to manage three kinds of barcode, but there are some Crystal report function with two paramaters, and the example doesn't show how to get right implementation. I tried to develop new classes to manage that kind of function but Always I get this message of error:"the call to a function does not correspond to any overload of 'name of function'".

            For this function I tried to pass only a parameter and the application runs well. I did an overload of the method, passing two parameters, but always I've got the same message of error.

            this is a part of my code

            ...

            ANSWER

            Answered 2019-Mar-26 at 07:32

            This is the complete code

            Source https://stackoverflow.com/questions/55336424

            QUESTION

            Tkinter image not showing
            Asked 2019-Jan-05 at 17:47

            I made this piece of code:

            ...

            ANSWER

            Answered 2019-Jan-05 at 17:47

            From tkinter docs on PhotoImage:

            You must keep a reference to the image object in your Python program, either by storing it in a global variable, or by attaching it to another object.

            The reason to do so is :

            When a PhotoImage object is garbage-collected by Python (e.g. when you return from a function which stored an image in a local variable), the image is cleared even if it’s being displayed by a Tkinter widget.

            To avoid this, the program must keep an extra reference to the image object. A simple way to do this is to assign the image to a widget attribute.

            Hence for your program:

            Source https://stackoverflow.com/questions/53681939

            QUESTION

            grep -oPz (GNU grep 3.1) does not match \n after positive lookahead
            Asked 2018-Oct-05 at 07:28

            As a simplified example I have printf "abc\ndef\nghi\n" | grep -oPz '\w{2}(?=c|f|i)\n' and that does not match anything, however grep -oPz '\w{2}(?=(c|f|i)\n)' does. Why is that? I need the newline in the output.

            Desired output is to match the rows and output them without the lookahead part eg. ab\n

            ...

            ANSWER

            Answered 2018-Oct-05 at 05:27

            ab means a followed by b, and continue matching after the b.

            a(?=b) means a followed by b, and continue matching after the a.

            So, for (?=c|f|i)\n to match, there must be a position that matches both c and \n, both f and \n, or by both i and \n. That's impossible.

            Source https://stackoverflow.com/questions/52657524

            QUESTION

            Bash - numbers of multiple lines matching regex (possible oneliner?)
            Asked 2018-Jul-04 at 18:52

            I'm not very fluent in bash but actively trying to improve, so I'd like to ask some experts here for a little suggestion :)

            Let's say I've got a following text file:

            ...

            ANSWER

            Answered 2018-Jul-04 at 18:31

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install opz

            Option 1: Download opz.js from dist folder. Option 2: Build distribution. Note: run Make install if you're missing js-yaml.
            Clone repo
            npm run build
            Copy new file saved in dist
            Plug OP-Z into computer
            Ensure "MIDI OUT ENABLE" is ON (use the app or refer to teenage engineering docs)

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            https://github.com/nbw/opz.git

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            gh repo clone nbw/opz

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            git@github.com:nbw/opz.git

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