oz | Web Authorization Protocol | Networking library

by outmoded JavaScript Version: v5.0.3 License: Non-SPDX

X-Ray Key Features Code Snippets Community Discussions(10)Vulnerabilities Install Support

kandi X-RAY | oz Summary

oz is a JavaScript library typically used in Networking applications. oz has no bugs, it has no vulnerabilities and it has medium support. However oz has a Non-SPDX License. You can download it from GitHub.

Oz is a web authorization protocol based on industry best practices. Oz combines the Hawk authentication protocol with the Iron encryption protocol to provide a simple to use and secure solution for granting and authenticating third-party access to an API on behalf of a user or an application. Protocol version: 5.0.0 (Same as v1.0.0 but moved the expired ticket indicator from a header attribute to the error payload).

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Quality

Security

License

Reuse

Support

oz has a medium active ecosystem.

It has 1536 star(s) with 61 fork(s). There are 121 watchers for this library.

It had no major release in the last 6 months.

There are 0 open issues and 53 have been closed. On average issues are closed in 168 days. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of oz is v5.0.3

Quality

oz has 0 bugs and 0 code smells.

Security

oz has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

oz code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

oz has a Non-SPDX License.

Non-SPDX licenses can be open source with a non SPDX compliant license, or non open source licenses, and you need to review them closely before use.

Reuse

oz releases are not available. You will need to build from source code and install.

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oz Key Features

No Key Features are available at this moment for oz.

oz Examples and Code Snippets

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Community Discussions

Trending Discussions on oz

How to maintain order of levels after factorizing column in R

Using contenteditable user input to mutiply table values

python dual for loops does not provide the expected results

How do I properly write a CSV file within a for loop in python?

Transferring JavaScript objects to HTML table

Taking an object's element and turning it into a button's innerHTML

changing a letter to another letter from another language - python

How to rename a deeply nested key in list of dictionaries (Python 3)?

Why aren't all the backslashes being replaced as per replace() statement?

mongodb agregate and filter data

QUESTION

How to maintain order of levels after factorizing column in R

Asked 2021-Jun-15 at 16:45

I have a permutation of different electrodes (25x25=625) from frontal to parietal.

...

ANSWER

Answered 2021-Jun-15 at 16:45

We can use unique in the levels argument of factor as unique returns the unique values from the first occurrence of that element, thus it maintains the same order of occurrence as in the original data

Source https://stackoverflow.com/questions/67990315

QUESTION

Using contenteditable user input to mutiply table values

Asked 2021-Jun-14 at 20:12

I'd like to dynamically update one column value in a table based on the user input in a different column. The user-editable column is quantity, and I'd like to multiply that by a price value (id = 'pmvalue') to display total price (id 'totalpmvalue') as an output.

I don't understand what javascript to use here - I've tried searching for solutions online, but haven't been able to find something that exactly corresponds to my use case (and I'm not experienced enough to understand how to adapt solutions for slightly different use cases). Any tips are greatly appreciated!

Here's my code:

...

ANSWER

Answered 2021-Jun-14 at 20:12

If you are going to have multiple rows, you should be using class, not id, the id attribute needs to be unique in a document.

Once you fix that, you can create a listener:

Source https://stackoverflow.com/questions/67976111

QUESTION

python dual for loops does not provide the expected results

Asked 2021-Jun-06 at 22:20

I am new to python . i am trying to run the below code but the results are not as expected:

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ANSWER

Answered 2021-Jun-06 at 21:17

There is no need for the nested loop.

Source https://stackoverflow.com/questions/67862765

QUESTION

How do I properly write a CSV file within a for loop in python?

Asked 2021-Jun-06 at 14:59

I am using the following code to scrape content from a webpage with the end goal of writing to a CSV. On the first iteration I had this portion working, but now that my data is formatted differently it writes the data in a way that gets mangled when I try to view it in excel.

If I use the code below the "heading.text" data is correctly put into one cell when viewed in excel. Where as the contents of "child.text" is packed into one cell rather then being split based on the commas. You will see I have attempted to clean up the content of "child.text" in an effort to see if that was my issue.

If I remove "heading.text" from "z" and try again, it writes in a way that has excel showing one letter per cell. In the end I would like each value that is seperated by commas to display in one cell when viewed in excel, I believe I am doing something (many things?) incorrectly in structuring "z" and or when I write the row.

Any guidance would be greatly appreciated. Thank you.

...

ANSWER

Answered 2021-May-05 at 06:03

csv.writerow() takes an iterable, each element of which is separated by the writer's delimiter i.e. made a different cell.

First let’s see what’s been happening with you till now:

(heading.text, child.text) has two elements i.e. two cells, heading.text and child.text
(child.text) is simply child.text (would be a tuple if it was (child.text**,**)) and a string's elements are each letter. Hence each letter made its own cell.

To get different cells in a row we need separate elements in our iterable so we want an iterable like [header.text, child.text line 1, child.text line 2, ...]. You were right in splitting the text into lines but the lines weren’t being added to it correctly. Tuples being immutable I’ll use a list instead:

We know heading.text is to take a single cell so we can write the following to start with

Source https://stackoverflow.com/questions/67394298

QUESTION

Transferring JavaScript objects to HTML table

Asked 2021-May-31 at 07:11

The object within an object contains variables such as "name", "amount", "amountType", and "cal". The strings on those variables should be transferred through loop as several row in the given HTML table. Each variable should be on its own cell.

I already made one row and made 4 cell for the name, amount, amount type, and calorie columns. Then, I tried to transfer the objects elements inside the cell using the index of the object.

...

ANSWER

Answered 2021-May-31 at 07:11

You're treating the mealObj as an array while it's an object and also you're not looping, so your code only runs once.

Below you can find a code that works for the first Menu (Steak). You might need to account for multiple meals by creating multiple tables.

Source https://stackoverflow.com/questions/67768563

QUESTION

Taking an object's element and turning it into a button's innerHTML

Asked 2021-May-31 at 04:03

On the function "createIngrList", it should take all the ingredient names, such as "Butter", "Beef", "Onion", etc., and turn it into buttons. So each button should have a text with the name of an ingredient written on it. As of now, there is just 4 buttons with "undefined" written on it. If possible, all the repeating ingredients such as "Onion" should not be made into button twice. Once is enough.

...

ANSWER

Answered 2021-May-31 at 00:33

I think this may be what you are looking for... Though you mention not parsing ingredients that are listed twice, though each food, only has an ingredient listed in your object once. Correct me if I am wrong I will refine answer.

You can use for/in loops to get the nested ingredients and their foods. Then use the obj.name to get the name. Through the first for/in loop the key -> i will be the name of the food, then use the second key along witht he first to get the actual .name => obj[i][k].name this will give you the ingredient name.

I also created a couple of divs to palce the food and its buttons wrapped in divs for styling, etc...

You can use conditionals to filter by food if you want to only show a certain type of foods ingredients as buttons.

NOTE: your obj key for the first value is uppercase, this will cause issues when parsing obj[index][key].name, likely that is just a typo...

Source https://stackoverflow.com/questions/67766627

QUESTION

changing a letter to another letter from another language - python

Asked 2021-May-19 at 19:07

Hi Sorry if you didn't understand what I want to achieve in the Question title but what I want to do is split a word into letters then changing the letter from English to Arabic for example

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ANSWER

Answered 2021-May-19 at 19:07

You could keep it as dictionary

Source https://stackoverflow.com/questions/67593510

QUESTION

How to rename a deeply nested key in list of dictionaries (Python 3)?

Asked 2021-May-13 at 15:48

Given the following dict (part of very long list of dicts):

...

ANSWER

Answered 2021-May-13 at 15:09

here you go

Source https://stackoverflow.com/questions/67521531

QUESTION

Why aren't all the backslashes being replaced as per replace() statement?

Asked 2021-May-07 at 20:54

I'm trying to replace backslashes (from this polyline) with double backslashes.

My Script:

...

ANSWER

Answered 2021-May-07 at 20:54

The basic problem is that there are no backslashes in your string. Your source code has backslashes, but they are all escape signals. If you want to retain the backslashes in "WYSIWYG" style, use raw string mode:

Source https://stackoverflow.com/questions/67441399

QUESTION

mongodb agregate and filter data

Asked 2021-May-05 at 07:04

I try to filter some results data from mongodb with mongoose in javascript.

This is my json structure:

...

ANSWER

Answered 2021-May-04 at 15:55

Here's a quick way of how to achieve this using $map

Source https://stackoverflow.com/questions/67387498

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install oz

You can download it from GitHub.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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