heartfelt | Cocos Creator 2.0 Material example

 by   pandamicro JavaScript Version: Current License: MIT

kandi X-RAY | heartfelt Summary

kandi X-RAY | heartfelt Summary

heartfelt is a JavaScript library. heartfelt has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Cocos Creator 2.0 Material example based on on shadertoy.com
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              heartfelt has a low active ecosystem.
              It has 47 star(s) with 26 fork(s). There are 3 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 2 open issues and 0 have been closed. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of heartfelt is current.

            kandi-Quality Quality

              heartfelt has 0 bugs and 0 code smells.

            kandi-Security Security

              heartfelt has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              heartfelt code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              heartfelt is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              heartfelt releases are not available. You will need to build from source code and install.

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            heartfelt Key Features

            No Key Features are available at this moment for heartfelt.

            heartfelt Examples and Code Snippets

            No Code Snippets are available at this moment for heartfelt.

            Community Discussions

            QUESTION

            How to insert the date in dd-mm-yyy format in spring boot
            Asked 2021-Jun-01 at 11:49

            I have a problem entering the date; I have a form consisting of prodcode, name and date (where the latter has been saved as a String). I try to test it with Postman by inserting the following example fields: { "prodcode": "PC001", "name": "Personal Computer", "date": "11/23/2020" }

            and when I go to save it in the db I get the following error:

            Data truncation: Incorrect datetime value: '23 -11-2020 'for column' data 'at row 1

            This is the code of interest:

            Product.java

            ...

            ANSWER

            Answered 2021-Jun-01 at 11:49

            Try to use date instead of string for the date. and use @DateTimeFormat

            Source https://stackoverflow.com/questions/67788042

            QUESTION

            how to place two submit of two different forms side by side on the same line
            Asked 2021-Feb-25 at 11:19

            Guys I'm trying to put two buttons from two different forms on the same line. I tried to put an id on both buttons so that I can manage them in css. In particular, what I want to do is put the "delete" button next to the "update" button. This is what I tried to do but it doesn't work because the "delete" button stays under the "update" button.

            ...

            ANSWER

            Answered 2021-Feb-24 at 12:45

            I may be talking bollocks, but I'm pretty sure form.submit() is part of the HTTP standardized API and as such it's supposed to trigger a single GET/POST/WHATEVER http protocol step.

            https://tools.ietf.org/html/rfc2068#section-9.5

            Source https://stackoverflow.com/questions/66351081

            QUESTION

            What is the most efficient way to move through a PHP array a number of times in one direction or another?
            Asked 2020-Nov-08 at 15:24

            Easy example: Taking as a reference the English abecedary (range A-Z). If I'm given a letter - let's say 'a' - and a number - let's say '2' - I would need to find out what's the letter 2 positions onwards. Answer would be 'c' ('a'--> 1 move:'b' --> 2 moves:'c')

            Of course, you could be given a number larger than the size of the abecedary letters, which is 26. Since the rule is that after letter z comes letter a again, this means that if in the previous example number 26 was passed the letter we would need to find would be 'a'.

            One last case scenario for the problem is that you may receive a negative number. So if letter 'a' is provided with number '-3', the answer would be 'x' ('a'--> 1 move:'z' --> 2 moves:'y' --> 3 moves:'x').

            This is the code I have so far:

            ...

            ANSWER

            Answered 2020-Nov-08 at 13:58

            Taking a modulo 26 is a correct idea.

            This is because, offset of 1 is the same as offset of 27. Offset of 0 is the same as offset 26,52 etc and so on and so forth.

            Taking modulo 26 for negative numbers also applies the same logic as rotation for -27 is the same as rotation for -1.

            So, the code is straightforward.

            • Apply modulo 26 to the number.
            • Take ascii value of current char and add "number" to it.
            • If the new ascii value is within the range of 65 and 90, return the char value.
            • If new ascii value exceeds 90, consume the offset till 90 and return chr() of it + 64. Same applies vice versa if value goes below 65.

            Snippet:

            Source https://stackoverflow.com/questions/64738237

            QUESTION

            MongoDB - Sum of a nested array with group_by
            Asked 2020-Oct-14 at 14:50

            I have a collection in MongoDB of bands that have multiple albuns and genres. Here is a simplified example of collection:

            ...

            ANSWER

            Answered 2020-Oct-14 at 14:50

            You can use below aggregation:

            Source https://stackoverflow.com/questions/64355599

            QUESTION

            How to execute a Command from a different project in WPF?
            Asked 2019-Nov-27 at 09:58

            I am a newbie to WPF and am trying to create a simple test app, while maintaining an MVVM architecture. So I split the application into two distinct projects: Tomato.UI (which contains the xaml files) and Tomato.ViewModels (which contains the classes to manage the interaction with the view).

            For now I only have two files for one window: MainWindow.xaml and MainWindowViewModel.cs

            In addition I added a reference to Tomato.ViewModels from Tomato.UI

            So this is the MainWindow.xaml, where I've created a reference to the ViewModels namespace and where a Button is bound to a function on the MainWindowViewModel.cs file:

            ...

            ANSWER

            Answered 2019-Nov-27 at 05:09

            You only have to make a binding Command="{Binding ButtonStartClick}"

            Click is an eventhandler, not command.

            Source https://stackoverflow.com/questions/59063214

            QUESTION

            Count keywords and word stems in tweets
            Asked 2019-Nov-06 at 09:37

            I have a large dataframe consisting of tweets, and keyword dictionaries loaded as values that have words associated with morality (kw_Moral) and emotion (kw_Emo). In the past I have used the keyword dictionaries to subset a dataframe to get only the tweets that have one or more of the keywords present.

            For example, to create a subset with only those tweets that have emotional keywords, I loaded in my keyword dictionary...

            ...

            ANSWER

            Answered 2018-Dec-12 at 14:02

            Your requirement would seem to lend itself to a matrix type output, where, for example, the tweets are rows, and each term is a column, with the cell value being the number of occurrences. Here is a base R solution using gsub:

            Source https://stackoverflow.com/questions/53744358

            QUESTION

            Elastic Search word suggestion
            Asked 2019-Jan-25 at 08:30

            We want elastic search to suggest words found within the index. We are using version: 5.6.4.

            if I type "head" it should suggest "headquarters", a word found in the index. Preferably it should sort the suggestions by occurrence.

            I have tried several tutorials, but they all return the entire content item instead of the word itself. The closest I came up with using the documentation is the following:

            ...

            ANSWER

            Answered 2019-Jan-25 at 08:30

            I ended up by using aggregations to solve this issue:

            Source https://stackoverflow.com/questions/54307057

            QUESTION

            Counting words and word stems in a large dataframe (RStudio)
            Asked 2019-Jan-09 at 11:12

            I have a large dataframe consisting of tweets, and a keyword dictionary loaded as a list that has words and word stems associated with emotion (kw_Emo). I need to find a way to count how many times any given word/word stem from kw_Emo is present each tweet. In kw_Emo, word stems are marked with an asterisk ( * ). For example, one word stem is ador*, meaning that I need to account for the presence of adorable, adore, adoring, or any pattern of letters that starts with ador….

            From a previous Stack Overflow discussion (see previous question on my profile), I was greatly helped with the following solution, but it only counts exact character matches (Ex. only ador, not adorable):

            1. Load relevant package.

              library(stringr)

            2. Identify and remove the * from word stems in kw_Emo.

              for (x in 1:length(kw_Emo)) { if (grepl("[*]", kw_Emo[x]) == TRUE) { kw_Emo[x] <- substr(kw_Emo[x],1,nchar(kw_Emo[x])-1) } }

            3. Create new columns, one for each word/word stem from kw_Emo, with default value 0.

              for (x in 1:length(keywords)) { dataframe[, keywords[x]] <- 0}

            4. Split each Tweet to a vector of words, see if the keyword is equal to any, add +1 to the appropriate word/word stems' column.

              for (x in 1:nrow(dataframe)) { partials <- data.frame(str_split(dataframe[x,2], " "), stringsAsFactors=FALSE) partials <- partials[partials[] != ""] for(y in 1:length(partials)) { for (z in 1:length(keywords)) { if (keywords[z] == partials[y]) { dataframe[x, keywords[z]] <- dataframe[x, keywords[z]] + 1 } } } }

            Is there a way to alter this solution to account for word stems? I'm wondering if it's possible to first use a stringr pattern to replace occurrences of a word stem with the exact characters, and then use this exact match solution. For instance, something like stringr::str_replace_all(x, "ador[a-z]+", "ador"). But I'm unsure how to do this with my large dictionary and numerous word stems. Maybe the loop removing [*], which essentially identifies all word stems, can be adapted somehow?

            Here is a reproducible sample of my dataframe, called TestTweets with the text to be analysed in a column called clean_text:

            dput(droplevels(head(TestTweets, 20)))

            ...

            ANSWER

            Answered 2019-Jan-08 at 12:17

            So first of all I would get rid of some of the for loops:

            Source https://stackoverflow.com/questions/54089957

            QUESTION

            Spring mvc filter doesn't take effect
            Asked 2018-Jun-05 at 04:42

            I'm learning SpringMVC. The version I use is 4.2.5.RELEASE. The filter I configure in web.xml doesn't seem to work

            Server: Tomcat 7

            Problem : When I use the GET method to pass in Chinese parameters, even if I configure the filter for UTF-8 encoding conversion, but the string I get is still garbled

            web.xml:

            ...

            ANSWER

            Answered 2018-Jun-05 at 04:42

            Have you tried configuring Tomcat's server.xml? Try setting URIEncoding="UTF-8" attribute to a Connector component:

            Source https://stackoverflow.com/questions/50691920

            QUESTION

            Regex Notepad ++ delete all except japanese character words
            Asked 2017-Oct-11 at 08:53

            I've been searching for a while now but still can't figure it out. I found expressions like ([一-龯])|([ぁ-んァ-ン]) but have no idea how to delete all except these.

            What I like to do is something like this:

            ...

            ANSWER

            Answered 2017-Oct-11 at 08:53

            UPDATE as per the op's comment pointed out by Gurman and KenY-N:

            Search By:

            Source https://stackoverflow.com/questions/46680106

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            You can download it from GitHub.

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