typify | Runtime type checking for JavaScript

by phadej JavaScript Version: 0.2.10 License: Non-SPDX

X-Ray Key Features Code Snippets Community Discussions(3)Vulnerabilities Install Support

kandi X-RAY | typify Summary

typify is a JavaScript library. typify has no bugs, it has no vulnerabilities and it has low support. However typify has a Non-SPDX License. You can install using 'npm i typify' or download it from GitHub, npm.

Runtime type checking for JavaScript

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Quality

Security

License

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Support

typify has a low active ecosystem.

It has 79 star(s) with 6 fork(s). There are 2 watchers for this library.

It had no major release in the last 12 months.

There are 5 open issues and 6 have been closed. On average issues are closed in 53 days. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of typify is 0.2.10

Quality

typify has 0 bugs and 0 code smells.

Security

typify has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

typify code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

typify has a Non-SPDX License.

Non-SPDX licenses can be open source with a non SPDX compliant license, or non open source licenses, and you need to review them closely before use.

Reuse

typify releases are available to install and integrate.

Deployable package is available in npm.

Installation instructions, examples and code snippets are available.

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typify Key Features

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typify Examples and Code Snippets

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Community Discussions

Trending Discussions on typify

get methods return undefined in Typescript

`(<*>)` definition for the Applicative functor?

Did I break Java's local variable type inference?

QUESTION

get methods return undefined in Typescript

Asked 2021-Apr-23 at 10:19

I don't undertand what's my code error when defining the get and set methods for a private field.

...

ANSWER

Answered 2021-Apr-23 at 10:19

That code should work. Playground

Why didn't your example work out?

When you parse item from local storage user variable becomes something like this: { userName: "John", token: 30 }

But you accessing user.UserName which does not exists so you have to mimic object from localStorage like so user.userName.

Ways to fix it:

Create new instance of the User class

Source https://stackoverflow.com/questions/67227097

QUESTION

`(<*>)` definition for the Applicative functor?

Asked 2018-Dec-19 at 16:26

Some Haskell source code (see ref):

...

ANSWER

Answered 2018-Dec-19 at 16:26

1) (<*>) is defined in terms of liftA2, where liftA2 is defined in terms of (<*>). How does it work? I see no obvious "recursion-break" case...

It's not recursion. In your instance of Applicative you can either define both of them or just one. If you define just (<*>) then liftA2 is defined from (<*>), and vice versa.

2) id is an a -> a function. Why is it passed into liftA2 as an (a -> b -> c) function?

Unification works as follows,

Source https://stackoverflow.com/questions/53763376

QUESTION

Did I break Java's local variable type inference?

Asked 2018-Dec-12 at 16:01

I wrote a method which "typifies" a String, and tries to infer the type of data held within it. (A slightly modified version of this gist). The method returns the inferred Class and the original String (possibly slightly modified -- surrounding whitespace trimmed, etc.) in a Map.Entry. For instance, typify("3f") returns , typify(" c ") returns and so on.

My next step was to write a second method which "decodes" these returned Map.Entry objects so they can be directly assigned to an object of the inferred type. For instance:

...

ANSWER

Answered 2018-Dec-12 at 15:53

You haven't broken anything. You can't assign null directly, but it's perfectly fine to assign it indirectly via a method call.

The reason for this is that by just assigning null the compiler has no information to know what type you want. The only inference that can be made is for the most generic type available, Object, and if that's the correct inference then just declare it as that explicitly! It's 3 extra characters.

When the compiler has a method call to use, it can use the return type of the method to make the type inference.

Source https://stackoverflow.com/questions/53746305

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install typify

Install the module with: npm install typify.

Support

In lieu of a formal styleguide, take care to maintain the existing coding style. Add unit tests for any new or changed functionality. Lint and test your code using npm test command.

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