dicio | Dicionário de português no terminal

by portujs JavaScript Version: Current License: MIT

X-Ray Key Features Code Snippets Community Discussions(1)Vulnerabilities Install Support

kandi X-RAY | dicio Summary

dicio is a JavaScript library. dicio has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Dicionário de português via linha de comando. Obs.: É necessário estar conectado à internet para usá-lo. Todos os dados apresentados são extraídos do site dicio.com.br.

Support

Quality

Security

License

Reuse

Support

dicio has a low active ecosystem.

It has 49 star(s) with 8 fork(s). There are 5 watchers for this library.

It had no major release in the last 6 months.

There are 4 open issues and 4 have been closed. On average issues are closed in 9 days. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of dicio is current.

Quality

dicio has 0 bugs and 0 code smells.

Security

dicio has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

dicio code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

dicio is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

dicio releases are not available. You will need to build from source code and install.

Installation instructions are not available. Examples and code snippets are available.

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dicio Key Features

No Key Features are available at this moment for dicio.

dicio Examples and Code Snippets

No Code Snippets are available at this moment for dicio.

Community Discussions

Trending Discussions on dicio

Segmentation Fault while implementing a C program for sorting

QUESTION

Segmentation Fault while implementing a C program for sorting

Asked 2019-Oct-31 at 18:25

I'm developing a program to sort an XML file that contains an open dictionary. I'm trying to do this using flex to recognize words, tags and etc and linked lists in C to sort them. By now I have a linked list to sort every word alphabetically and I tried to do the same to sort those words inside the usage that each word corresponds. I'm having the segmentation problem, probably because the list is getting a NULL I think from the InsertUsageWord() function, where did I go wrong? Thanks in advance.

C code

...

ANSWER

Answered 2019-Oct-31 at 01:15

You're calling

use = InsertUsageWord(use, word);

but you never initialized word to anything

Source https://stackoverflow.com/questions/58634611

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install dicio

You can download it from GitHub.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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