frequency | Flashing HTML elements based on periodic events
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kandi X-RAY | frequency Summary
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QUESTION
looking for a quick solution to pick up the text following a numeric value that looks like this:
text to extract
...ANSWER
Answered 2021-Jun-04 at 07:28We can use re.findall
here as follows:
QUESTION
In the following histogram,
...ANSWER
Answered 2021-Jun-15 at 18:35You could loop through the bars and test whether it is completely to the right of the separation, completely to the left or crosses it. You change the bar's color correspondingly.
When a bar crosses the separator, the bar gets the color for the left area and its size is narrowed to touch the separator. A copy of the bar can be added, with the right-area color and its x-position moved.
QUESTION
Hi I am looking for help to study pre-existing models that are IoT based but has applications such as radio frequency identification, emergency related, and some form of access control, a paper in that area is ideal. Thanks in advance!
...ANSWER
Answered 2021-Jun-15 at 15:56Please try to have more details in your questions, an example of what the framework is, I have published previously a framework in IoT Emergency System that was based on a disaster. The Doc will help you research your topic better as it is based on a framework design, a prototype is developed using an RFID access control and a drone system. We also incorporate design specifications that minimize the risk of data and privacy breaches. DOI
QUESTION
I have a a few dataframes, a few thousand rows each that look similar to this :
...ANSWER
Answered 2021-Jun-15 at 15:54IIUC, if all unique id's can be sorted into contiguous blocks.
QUESTION
In R, I can take a df and get a list of frequency tables for each sample/group by doing the following:
...ANSWER
Answered 2021-Jun-15 at 02:03In pandas
you can do groupby
with pd.crosstab
QUESTION
I grouped a dataframe test_df2
by frequency 'B'
(by business day, so each name of the group is the date of that day at 00:00) and am now looping over the groups to calculate timestamp differences and save them in the dict grouped_bins
. The data in the original dataframe and the groups looks like this:
What I want is to calculate the difference between each row's timestamp
, for example of rows 7
and 0
, since they have the same externalId
.
What I did for that purpose is the following.
...ANSWER
Answered 2021-Jun-14 at 22:22To convert your timestamp strings to a datetime object:
QUESTION
I have a dataset of jobs for a gardening company with 50 or so columns.
...ANSWER
Answered 2021-Jun-14 at 16:32I suggest that you use Sheet.getRange(row, column, numRows, numColumns) and Range.getValues() to get the row values with multiple columns.
Sample:
QUESTION
I have a dataset of jobs for a gardening company.
...ANSWER
Answered 2021-Jun-14 at 15:05Your goal is possible by using a custom script. You can try creating a bound script in your spreadsheet file and copy/paste this sample script below:
[updated]
SCRIPT:
QUESTION
I am trying to get my robot to communicate with my PC via sockets by using local IP addresses on my own home network (not devices outside my network). The robot is acting as the server and my own PC is acting as the client/host. I don't really know what ports are open on my robot but I do definitely know that port 22 on the robot is open (which is the SSH port). The robot is a lego EV3 robot apart from it has had some ev3python software put onto it. When I run my program I am getting the following error on the server (my robot):
...ANSWER
Answered 2021-Jun-14 at 12:24hostIPAddress = "xx.xx.xx.xx" #the local IP address of my PC on my home network
backlog = 1
size = 1024
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.bind((hostIPAddress,22))#22 is the port number I am using. (THIS IS ALSO THE LINE WHERE THE ERROR IS COMING FROM)
s.listen(backlog)
QUESTION
I'm trying to find a duplicate value for each row in a specific column in the pandas dataframe.
...ANSWER
Answered 2021-Jun-14 at 12:01To get the common value among all lists per group use groupby aggregate
with a bit of set
logic:
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