rubidium | : hourglass : A small unique job scheduler

 by   qubyte JavaScript Version: 4.0.0 License: MIT

kandi X-RAY | rubidium Summary

kandi X-RAY | rubidium Summary

rubidium is a JavaScript library. rubidium has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can install using 'npm i rubidium' or download it from GitHub, npm.

Rubidium is a one-time task emitter, inspired by the unix at utility. This module is a minimal implementation. It exports a constructor. Instances of the constructor are event emitters, with methods to add and remove job specifications. A job consists of a due time and a message. Rubidium is built upon the use of setTimeout, so the usual warnings apply. That said, Rubidium creates a fresh timeout after each job is emitted, so it is self-correcting to within the resolution of a timer. Rubidium is built on vetebrate-event-emitter, which makes it robust against memory leaks. It has been bundled for you with its dependencies, so Rubidium has no dependencies in production. Both UMD (for your CommonJS, AMD, and browser global needs) and ES2015 flavour modules have been provided, so you can use this module easily with all major module systems.
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              rubidium has a low active ecosystem.
              It has 6 star(s) with 13 fork(s). There are 1 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 0 open issues and 5 have been closed. On average issues are closed in 43 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of rubidium is 4.0.0

            kandi-Quality Quality

              rubidium has no bugs reported.

            kandi-Security Security

              rubidium has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              rubidium is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              rubidium releases are available to install and integrate.
              Deployable package is available in npm.
              Installation instructions are not available. Examples and code snippets are available.

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            rubidium Key Features

            No Key Features are available at this moment for rubidium.

            rubidium Examples and Code Snippets

            No Code Snippets are available at this moment for rubidium.

            Community Discussions

            QUESTION

            Is it possible to put in a atoomnumber and out a atoomname in javascript?
            Asked 2020-Feb-28 at 16:55

            Here is the code i already attempted but it didnt work out:

            This code is made by a 14 year old boy (me) so dont worry about the maintenance.

            HTML:

            ...

            ANSWER

            Answered 2020-Feb-28 at 16:55

            I made a plunker with a working solution: https://plnkr.co/edit/QyAglTqoVx8k5RhZbenV?p=preview

            Yeah, it needs put NaamOfAtoom(AtoomNum) inside that berekenen() function to fill that Atoomnaam variable, and change the switch.

            Basically, when you did that switch, the cases are numbers, but AtoomNum is a string (you can type letter also), so it didn't entered any case options. So was equivalent to 12 === '12' returning false. switch is strict comparing === instead of only ==.

            Adding a parseInt(number) solved switch part.

            Source https://stackoverflow.com/questions/60455202

            QUESTION

            Why lambda function fetches data from dict.items() and a list of tuples differently?
            Asked 2019-Aug-30 at 19:43
            atomicNumber = {'Rubidium(Rb)':37, 'Lithium(Li)': 2, 'Argon(Ar)': 18 ,'Sodium(Na)': 11, 'Potassium(K)':19, 'Hydrogen(H)': 1,}
            sort_atomicNumber = dict(sorted(atomicNumber.items(), key = lambda x: x[0]))
            print(sort_atomicNumber)
            
            ...

            ANSWER

            Answered 2019-Aug-30 at 19:26

            atomicNumber.items() generates tuples, so for example, in the first iteration, the tuple generated is ('Rubidium(Rb)', 37) (referenced by x), so, x[0] would be the key, and x[1] would be the value.

            When you tried to imitate it, you passed the dict_items as an argument to the lambda function, while in the sorted function, the tuples that are inside the dict_items are the ones being passed to the lambda function. So, the correct imitation would be something like:

            Source https://stackoverflow.com/questions/57732190

            QUESTION

            How to save images in specific file directories using Python PIL (Pillow) without getting a KeyError due to: save_handler = SAVE[format.upper()]
            Asked 2018-Jul-10 at 15:06

            I am trying to crop specific elements out of a larger image of the periodic table, then saving them in a specific file directory, this file directory is inside an additional folder, and this folder is in the same file directory as the program that I am trying to do this with.

            I have looked at another answered question on stack overflow that has similarities to my problem: How can I save an image with PIL? , however this user used 'numpy'. I have only previously learnt python basics in school and am using my free time to learn 'tkinter' and now 'PIL' (Pillow), I am new to these modules for python and am struggling to grasp the confusing documentation for both, and I also don't know what 'numpy' is or how to use it.

            This the code I am trying to run:

            ...

            ANSWER

            Answered 2018-Jul-10 at 15:06

            You are passing the name of the file as the second parameter to Image.save.

            However, the second parameter is the (optional) file format - if specified it must match a registered file format, e.g. GIF, BMP, PNG, ...

            What you probably wanted to do is to concatenate the path and the image name - no need to specify the format.

            Source https://stackoverflow.com/questions/51268436

            QUESTION

            How to read from a file into a dynamically allocated linked list of pointers to struct?
            Asked 2018-May-09 at 06:25

            So I've been working on this program for a while and I have gotten it to a point where it compiles just fine but when I run it I get a Segmentation Fault. I've backtraced the fault via gdb to the function below but cannot for the life of me see where the problem is, and I am not versed enough with gdb to determine any more details on the origin of the fault. Like the question says I'm trying to read from a file into a dynamically allocated linked list where each node of the list has a pointer to a struct called Element. Then I need to convert that linked list to an array of pointers to struct Element. I hope that a fresh pair of eyes can see some mistake I've made that I have been blind to.

            UPDATE: Added rest of source files. Added gdb backtrace snippet.

            Element.h

            ...

            ANSWER

            Answered 2018-May-09 at 06:25

            The good news is you were really, really close. The bad news is the "really really close" part -- it only takes one subtle error to torpedo your code.

            First the general discussion. While there is nothing wrong with using a pointer-to-pointer-to-Element, you are missing the benefits of using C++ and the automatic memory handling offered by . That said, it is good to know how to handle both.

            Your error is:

            Source https://stackoverflow.com/questions/50245215

            QUESTION

            Why does the output not change depending on the input from user?
            Asked 2017-Dec-08 at 22:39

            So I was doing my school work and one of the programming challenges I need to do is a periodic table challenge. I didn't think it would be that hard to program, but I encountered a problem that I am not able to resolve. It is not a syntax error and I have already spend hours on the internet going through guide on whether I am using the if statements correctly, but I was unable to identify the mistake. My code reads:

            ...

            ANSWER

            Answered 2017-Dec-08 at 22:39

            The problem is caused by the lines like userchoice == "Helium" or "helium" when separated by or, python tries to read two completely different conditions. In your later case, the condition is just helium which always returns true. So change all lines to userchoice == "Helium" or userchoice == "helium". Or just use userchoice.lower().

            Source https://stackoverflow.com/questions/47723103

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install rubidium

            You can install using 'npm i rubidium' or download it from GitHub, npm.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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            Install
          • npm

            npm i rubidium

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          • HTTPS

            https://github.com/qubyte/rubidium.git

          • CLI

            gh repo clone qubyte/rubidium

          • sshUrl

            git@github.com:qubyte/rubidium.git

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