NetworkView | Dynamics CRM 2015 managed solution
kandi X-RAY | NetworkView Summary
kandi X-RAY | NetworkView Summary
A Dynamics CRM 2015 managed solution that allows exploring of your Contact/Account networks in a fun and visual way. Take a look - I'll be pushing the code soon.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of NetworkView
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QUESTION
using System.Collections;
using System.Collections.Generic;
using UnityEngine;
[AddComponentMenu("Camera-Control/Mouse Look")]
public class MouseLook : MonoBehaviour
{
public enum RotationAxes { MouseXAndY = 0, MouseX = 1, MouseY = 2 }
public RotationAxes axes = RotationAxes.MouseXAndY;
public float sensitivityX = 15F;
public float sensitivityY = 15F;
public float minimumX = -360F;
public float maximumX = 360F;
public float minimumY = -60F;
public float maximumY = 60F;
float rotationY = 0F;
void Update()
{
if (axes == RotationAxes.MouseXAndY)
{
float rotationX = transform.localEulerAngles.y + Input.GetAxis("Mouse X") * sensitivityX;
rotationY += Input.GetAxis("Mouse Y") * sensitivityY;
rotationY = Mathf.Clamp(rotationY, minimumY, maximumY);
transform.localEulerAngles = new Vector3(-rotationY, rotationX, 0);
}
else if (axes == RotationAxes.MouseX)
{
transform.Rotate(0, Input.GetAxis("Mouse X") * sensitivityX, 0);
}
else
{
rotationY += Input.GetAxis("Mouse Y") * sensitivityY;
rotationY = Mathf.Clamp(rotationY, minimumY, maximumY);
transform.localEulerAngles = new Vector3(-rotationY, transform.localEulerAngles.y, 0);
}
}
void Start()
{
//if(!networkView.isMine)
//enabled = false;
// Make the rigid body not change rotation
//if (rigidbody)
//rigidbody.freezeRotation = true;
}
}
...ANSWER
Answered 2019-May-19 at 17:18Get the first Touch
, then use touch.deltaPosition
to find how much the touch has moved since the last update. Then, you can scale with screen size and sensitivity.
QUESTION
Here is something similar to what is happening in my code : https://codepen.io/anon/pen/zJmvXa?editors=1010
Press the Update button to see the issue.
The problem in this codePen, is its only redrawing the first element (Myriel).
I think it must be around the enter,exit or the merge, but I don't fully grasp what's going on.
I thought the merge was to merge existing data with new, and the only data that should go into the enter should be the new data. And the exit is for removing redundant data?
As this graph has both circles and text, should the merge be made on the 'g' element that contains these ?
Perhaps it's to do with the data function :
...ANSWER
Answered 2018-Sep-17 at 12:51The problem here is that you'er merging the update and enter selections...
QUESTION
Say you have
Using "new" Unity networking, you must have (as far as I know) a NetworkManager
somewhere. It will spawn the ridiculous "player" object.
The ridiculous "player" object must have a class which inherits from NetworkBehaviour
.
Most teams call that class something like "Comms" or "AbstractPlayer" or "Junction".
...ANSWER
Answered 2018-Jul-23 at 06:37The short answer to your question is No. Simply because using the [Command]
keyword in a MonoBehavior
will immediately result in an error in your editor, since the code can't be compiled.
UNetWeaver error: Script XXXXXX uses [Command] YYYYY but is not a NetworkBehaviour.
However there are other possibilities that get very close to what you want to achieve.
- As discussed in the comments, you could use Events and Delegates to subscribe your
[Command]
function to another function from a class that inherits fromMonoBehavior
. - Another very clever possibility that I have just attempted and had success with is using Interfaces.
I have just made a simple interface that does not implement any other interfaces, it just declares a command. It looks like this:
QUESTION
i have file of API model which contains api call and i am getting different responses on api call and then i am parsing the call and comparing the parsing keys in code and show the alert. I do not want to show alert in api model class, i want to show alert in that other class of LoginVC which contains IBAction of Loginpressed. Please see the following code.
...ANSWER
Answered 2018-Jun-25 at 15:40Do you want to display a custom error message?
if so add an error string to your completion closure
func loginApiCall(email : String,password : String, completion:@escaping (_ isSuccesfull :Bool, _ errorMessage :String?) ->())
then when login fails in your API class change failure to
QUESTION
I have a simple D3 Graph but I am struggling but for some reason the nodes won't stay within the bounds of the svg. I have given them a height and width and when the nodes render they spill outwidth said height and width and are therefore invisble.
...ANSWER
Answered 2017-Nov-09 at 23:20There is a conceptual misunderstanding here. size()
will not restrain your nodes. According to the API, it will simply:
...set the available layout size to the specified two-element array of numbers representing x and y [...] The size affects two aspects of the force-directed layout: the gravitational center, and the initial random position.
A possible solution is using this simple math:
QUESTION
I have a JSlider in my program. Program does something when the value of slider is changed. What I want to do is to increase the value of slider until its max value and I need to wait every time slider value is increased for the things that I do in the ChangeListener class.
Here is my related codes (svPlay is like a play button):
...ANSWER
Answered 2017-Oct-21 at 17:35This is what I understand from your question: you have long calculations going on in Slider change listener. You want to perform calculations for a range of values, and reflect that on the slider.
If the above premise is correct, you don't want to sleep n seconds while calculations are going on -- you want to wait for them to finish and proceed asap. One way to do it, is using wait and notify commands on a lock (note, that recent Java comes with java.util.concurrent package, which contains higher level multithreading control and I think would be better to use, however I'm not familiar with it myself)
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