equal | Deep equality comparison implementation for should.js

 by   shouldjs JavaScript Version: 2.0.0 License: MIT

kandi X-RAY | equal Summary

kandi X-RAY | equal Summary

equal is a JavaScript library. equal has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can install using 'npm i should-equal' or download it from GitHub, npm.

Deep equality comparison implementation for should.js. Not supported outside of should.js.
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              equal has a low active ecosystem.
              It has 11 star(s) with 4 fork(s). There are 4 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 1 open issues and 5 have been closed. On average issues are closed in 35 days. There are 1 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of equal is 2.0.0

            kandi-Quality Quality

              equal has no bugs reported.

            kandi-Security Security

              equal has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              equal is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              equal releases are available to install and integrate.
              Deployable package is available in npm.
              Installation instructions are not available. Examples and code snippets are available.

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            equal Key Features

            No Key Features are available at this moment for equal.

            equal Examples and Code Snippets

            No Code Snippets are available at this moment for equal.

            Community Discussions

            QUESTION

            repeat values of a column based on a condition
            Asked 2021-Jun-16 at 00:54

            I have a data frame including three columns named 'Altitude', 'Distance', 'Slope'. The column of 'Slope' is calculated using the two first columns 'Altitude', 'Distance'. @ the first step the purpose was to calculate 'Slope' using a condition explained below: A condition function was deployed to start from the top column of the "Distance" variable and add up (sum) values until the summation of them is greater or equal to 10 (>=10). If this condition corrects then calculate the "Slope" using the given formula: Slope=Average(Altitude)/(sum(Distance)). The summation of the 'Distance' was counting from the first value of that to the index that the 'Distance' has stopped there). The following code is for the above explanation (By Tim Roberts):

            ...

            ANSWER

            Answered 2021-May-19 at 13:38

            Use this code after you calculate s to get slope column with desired values:

            Source https://stackoverflow.com/questions/67602985

            QUESTION

            I need to strip all the symbols from a string in order to create an `IEqualityComparer` that ignores punctuation symbols
            Asked 2021-Jun-15 at 23:05

            In part of my application I have an option that displays a list of albums by the current artist that aren't in the music library. To get this I call a music API to get the list of all albums by that artist and then I remove the albums that are in the current library.

            To cope with the different casing of names and the possibility of missing (or extra punctuation) in the title I have written an IEqualityComparer to use in the .Except call:

            ...

            ANSWER

            Answered 2021-Jun-15 at 23:05

            If you're going to use the CompareOptions enum, I feel like you might as well use it with the CompareInfo class that it's documented as being designed for:

            Defines the string comparison options to use with CompareInfo.

            Then you can just use the GetHashCode(string, CompareOptions) method from that class (and even the Compare(string, string, CompareOptions) method if you like).

            Source https://stackoverflow.com/questions/67994184

            QUESTION

            Multi-dimensional Array; JavaScript; Algorithum
            Asked 2021-Jun-15 at 19:02

            Details
            I'm working on an algo dealing with a multi-dimensional array. If there is a zero, then the elements of the same column, but following arrays will also equal zero. I want to be able to sum the items that are not zeroed out.

            ...

            ANSWER

            Answered 2021-Jun-15 at 17:18

            QUESTION

            How can one check if an integer is equal to another in a 2D array?
            Asked 2021-Jun-15 at 19:00

            How can one check if an integer is equal to another in a 2D array?

            ...

            ANSWER

            Answered 2021-Jun-15 at 18:23

            Just to address your attempt, the correct syntax for that would be

            if (a == b || a == c || a == d || a == e || a == f || a == g || a == h || a == i) ....

            But depending on your use case, it's probably advisable to loop over the array instead.

            Source https://stackoverflow.com/questions/67991573

            QUESTION

            Compare two JSON Files and Return the Difference
            Asked 2021-Jun-15 at 18:14

            I have found some similar questions to this. The problem is that none of those solutions work for me and some are too advanced. I'm trying to read the two JSON files and return the difference between them.

            I want to be able to return the missing object from file2 and write it into file1.

            These are both the JSON files

            ...

            ANSWER

            Answered 2021-Jun-14 at 19:20
            with open("file1.json", "r") as f1:
                file1 = json.loads(f1.read())
            with open("file2.json", "r") as f2:
                file2 = json.loads(f2.read())
            
            for item in file2:
                if item not in file1:
                    print(f"Found difference: {item}")
                    file1.append(item)
            
            print(f"New file1: {file1}")
            

            Source https://stackoverflow.com/questions/67975713

            QUESTION

            Flask If Statement - Range for list index
            Asked 2021-Jun-15 at 17:32

            customer_data.json (loaded as customer_data)

            ...

            ANSWER

            Answered 2021-Jun-15 at 17:32

            I am trying to go through each of the books in holds using holds[0], holds[1] etc and test to see if the title is equal to a book title

            Translated almost literally to Python:

            Source https://stackoverflow.com/questions/67990789

            QUESTION

            Qt - trying to align two GroupBoxes in a layout
            Asked 2021-Jun-15 at 17:18

            A part of my form contains QGroupBox (Status Box) with 4 child QGroupBoxes arranged in a grid layout (2x2). Two bottom QGroupBoxes (Widget 1 Box and Widget 2 Box) contain widgets of fixed size (with set minimumSize and maximumSize) so they're non-resizable at all in both directions. Because of that rigid size constraints top row of QGroupBoxes (Summary Box and Helper Box) can only be resized in vertical direction.

            And here comes the troublesome part. Top-left QGroupBox (Summary Box) have grid layout 5x3 while top-right (Helper Box) have vertical layout with 6 rows. If I have naive widget placement as shown on picture 1 Qt is enlarging vertical size of both labels in top row to make height of both QGroupBoxes equal (see red arrows on picture 1).

            This is definitely that I don't want so I've added vertical spacer to the bottom of Summary Box and from the first glance it worked (picture 2). But only from the first glance... What you see is the minimum height of my whole form and the bottom side of spacer and last QCheckBox in the Helper Box seems to be aligned.

            If I'm expanding my form vertically this spacer grows a bit and that causes the increase of height of both top QGroupBoxes. As a result spacing between QCheckBoxes increases too and we can also see that top and bottom spacing are unequal for the top-right box (see red arrows on picture 3).

            I've tried to play with sizeType for my vertical spacer. If I set it to Minimum or MinimumExpanding then the spacer doesn't grow on resize (and doesn't shrink, too) but it appears to be expanded to the size as on picture 3 (corrupting spacings between QCheckBoxes too). If I set it to Maximum, Preferred or Expanding then I observe the same behavior as described above for picture 3.

            What is the proper way to achieve alignment for two QGroupBoxes in a row of grid without affecting spacing between elements (e. g. in that case make vertical spacer to fit only single row of grid layout and never expand/shrink)?

            ...

            ANSWER

            Answered 2021-Jun-15 at 17:18

            Items will be aligned if both QGroupBoxes have same count of children and each row have at least one child with Expanding vertical policy. Instead of spacer use QWidget

            I removed unrelated widgets and reduces number of rows to 4 for demonstration purposes (less xml).

            Source https://stackoverflow.com/questions/67987476

            QUESTION

            Deleting columns with specific conditions
            Asked 2021-Jun-15 at 16:53

            I have a dataframe output from the python script which gives following output

            Datetime High Low Time 546 2021-06-15 14:30:00 15891.049805 15868.049805 14:30:00 547 2021-06-15 14:45:00 15883.000000 15869.900391 14:45:00 548 2021-06-15 15:00:00 15881.500000 15866.500000 15:00:00 549 2021-06-15 15:15:00 15877.750000 15854.549805 15:15:00 550 2021-06-15 15:30:00 15869.250000 15869.250000 15:30:00

            i Want to remove all rows where time is equal to 15:30:00. tried different things but unable to do. Help please.

            ...

            ANSWER

            Answered 2021-Jun-15 at 15:55

            The way I did was the following,

            First we get the the time we want to remove from the dataset, that is 15:30:00 in this case.

            Since the Datetime column is in the datetime format, we cannot compare the time as strings. So we convert the given time in the datetime.time() format.

            rm_time = dt.time(15,30)

            With this, we can go about using the DataFrame.drop()

            df.drop(df[df.Datetime.dt.time == rm_time].index)

            Source https://stackoverflow.com/questions/67989337

            QUESTION

            Combine values from duplicated rows into one based on condition (in R)
            Asked 2021-Jun-15 at 16:51

            I have a dataset with the name of Danish ministers and their position from 1990 to 2020 (data comes from dataset called WhoGovern; https://politicscentre.nuffield.ox.ac.uk/whogov-dataset/). The dataset consists of the ministers name, the ministers position, the prestige of that position, and the year in which the minister had that given position.

            My problem is that some ministers are counted twice in the same year (i.e., the rows aren't unique in terms of name and year). See the example in the picture below, where "Bertel Haarder" was both Minister of Health and Minister of Interior Affairs in 2010 and 2021.

            I want to create a dataset, where all the rows are unique combinations of name and year. However, I do not want to remove any information from the dataset. Instead, I want to use the information in the prestige column to combine the duplicated rows into one. The observations with the highest prestige should be the main observations, where the other information should be added in a new column, e.g., position2 and prestige2. In the example with Bertel Haarder the data should look like this:

            (PS: Sorry for bad presenting of the tables, but didn't know how to create a nice looking table...)

            Here's the dataset for creating a reproducible example with observations from 2010-2020:

            ...

            ANSWER

            Answered 2021-Jun-08 at 14:04

            Reshape the data to wide format twice, once for position and the other for prestige_1, and join the two results.

            Source https://stackoverflow.com/questions/67888166

            QUESTION

            How to combine a for loop with condition?
            Asked 2021-Jun-15 at 15:29

            I'm new to python so let me know if I need more information, but here's what I have:

            ...

            ANSWER

            Answered 2021-Jun-15 at 13:56

            You can use math.ceil() for this, which rounds numbers up. First you have to import math

            Then in your for loop:

            Source https://stackoverflow.com/questions/67987532

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install equal

            You can install using 'npm i should-equal' or download it from GitHub, npm.

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