togetherness | JS dice-rolling , card-playing table simulator

by sjbrown JavaScript Version: Current License: AGPL-3.0

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kandi X-RAY | togetherness Summary

togetherness is a JavaScript library typically used in Telecommunications, Media, Media, Entertainment applications. togetherness has no bugs, it has no vulnerabilities, it has a Strong Copyleft License and it has low support. You can download it from GitHub.

Tabletop RPGs are no longer just played in physical spaces. More and more, this kind of game is being played online, and players are discovering online dice rollers, communal game maps, virtual tabletops, and digital character keepers. But too often these tools are walled gardens whose owners see players as products, not human beings. Togetherness Table is a web-based virtual tabletop whose chief aim is the empowerment of players as free human beings participating voluntarily in a community. There are no "owners", just equal participants enjoying a gamut of activities including "creation", "play" and "hosting". Togetherness Table aims to be Local-First Software.

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Quality

Security

License

Reuse

Support

togetherness has a low active ecosystem.

It has 18 star(s) with 2 fork(s). There are 3 watchers for this library.

It had no major release in the last 6 months.

There are 9 open issues and 4 have been closed. On average issues are closed in 190 days. There are 1 open pull requests and 0 closed requests.

It has a neutral sentiment in the developer community.

The latest version of togetherness is current.

Quality

togetherness has no bugs reported.

Security

togetherness has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

togetherness is licensed under the AGPL-3.0 License. This license is Strong Copyleft.

Strong Copyleft licenses enforce sharing, and you can use them when creating open source projects.

Reuse

togetherness releases are not available. You will need to build from source code and install.

Installation instructions, examples and code snippets are available.

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togetherness Key Features

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togetherness Examples and Code Snippets

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Community Discussions

Trending Discussions on togetherness

Unique together involving multiple foreign keys & a many to many field

Check if two sets of points are in different hemispheres from a source point

Trying to validate that at least one checkbox is checked angularJS

QUESTION

Unique together involving multiple foreign keys & a many to many field

Asked 2019-Jul-27 at 15:31

Our business' pricing is dependent on multiple parameters, and now we want to introduce another possible M2M parameter to the existing setup in Django.

For this, we have an existing table for pricing, which has a unique_together constraint on all fields except the price_field. Apologies for the generic / letter-based naming in the example.

...

ANSWER

Answered 2019-Jul-22 at 15:01

Premises

In Sql and so in Django ORM you can't set a unique constraints on a many to many fields because it involves two different tables.

SQL Solution:

You can try to reproduce this solution on django.

But in order to do this you have to manually create the tab_constr and insert the trigger logic inside the save method or with the signals

Django solution

I do not recommend you to follow that solution because it is difficult to reproduce in django, in fact you have to manually reproduce the m2m reference with two external key and one extra table.

Simply put your check on on_save method there is no other way.

P.S.

Don't use the override of save method to add check on your object because this method is not called if you change a QuerySet of objects. Instead use the signal like this:

Source https://stackoverflow.com/questions/57093466

QUESTION

Check if two sets of points are in different hemispheres from a source point

Asked 2018-Sep-20 at 19:52

I have a 2D plan with integer coordinates.

On this plan, there are many points, separated in three categories.

The "Source". There is only a single point that is the source.
The Nice Group, containing an unknown (but reasonable) number of points
The Evil Group, containing an unknown (but reasonable) number of points

What I am trying to do first of all is to figure out (yes/no) if the two groups are in separated hemispheres.

If you could draw a line through the Source (Blue in the images) so that all nice are on one side, and all evil are on the other, then they are considered in different hemispheres. If so much as one of either group can't be put on the same side as the rest, it's false.

The second step is to figure out the angle of this hemisphere. In the first example (below), I've drawn a 180 degrees angle (straight line), but I would like to calculate the most unbalanced angle (close to 0) that would allow separating the groups perfectly. The line then would be two half-lines starting at the source going to infinity. I want to know the smallest angle (so, logically, the biggest angle if you measure the other side) that keeps the first test as true

Examples:

Right now I am able, through code, to calculate the angle between every individual point and the source. I am stuck at figuring out how to test the "togetherness" of the groups, and most importantly, the absence of a member of the other group in between.

I am working in C#, but this question is really more about the algorithm (I can't think of a working one), so I will accept any answer that solves the problem in any (readable) language, including pseudo-code or straight up text explanation.

All of the points are, in context, complex objects that include a X and a Y coordinate. The other attributes are irrelevant to the question as they are already separated in the required groups (origin is alone and there are two lists for the rest).

...

ANSWER

Answered 2018-Sep-20 at 19:52

You can sort and scan. Let's introduce polar coordinate system with its origin at the Origin and arbitrary axis.

Compute azimuth for each point (either nice or evil)
Order points by their azimuth, e.g.
Scan the sorted collection; if you have 2 or less transistion between nice to evil or evil to nice; return true, otherwise false

E.g. (let azimuthes be in degrees)

Source https://stackoverflow.com/questions/52426207

QUESTION

Trying to validate that at least one checkbox is checked angularJS

Asked 2017-Mar-07 at 18:43

Trying to figure out the best way to stay on the same page alerting the user if they have failed to check at least one checkbox.

HTML:

...

ANSWER

Answered 2017-Mar-07 at 17:51

simply just check the valueStatus length is equal to 0 or not

Source https://stackoverflow.com/questions/42654683

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install togetherness

Then open your browser to localhost:8000.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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