Cnode | This is a website programme that imitate cnode club
kandi X-RAY | Cnode Summary
kandi X-RAY | Cnode Summary
It`s a programme for mobile terminal. I have done some functions (Not perfect).
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QUESTION
I have an abstract base class defined like this:
...ANSWER
Answered 2021-Apr-03 at 21:19Yes, it would work. But storing raw pointers inside a vector is not a good idea, use smart pointers or boost pointer container if that’s not an overkill.
QUESTION
Good Day! I'm currently trying to create a database that needs me to create two ADT. One of them has a private struct linkedlist created in this example
The problem is I can't seem to access or at least print out the values inside my struct in a function from another class
here is a sample code I derived from my original
...ANSWER
Answered 2021-Apr-02 at 15:36First of all attribute c
in class B is private. There is nowhere in the B class to put that value. So I added a constructor that takes a reference to an instance of A.
What you were doing wrong: c were always having a null pointer. Now something about raw references and pointers. Always check against nullptr. Else, you''ll get undefined behaviour such as nothing displaying.
QUESTION
I have to create a service availability using info from this 2 query.
First Query.
...ANSWER
Answered 2020-Dec-19 at 17:19You can use conditional aggregation:
QUESTION
Thanks for looking into this, I was trying to make a visual simulation of Depth first search algorithm, using graphics.h in C++, Each of my graph nodes have 3 attributes, x_coordinate
y_coordinate
and a nodeId
, also I have a separate Class for Graph Object which has the adjacentcy list graph, So As the following code was executed It gave The results as incomplete, one of the five edges in input ( Input given below ) edge ( 0 - 3 ) was not displayed See snap shot here , can you help me with this?
ANSWER
Answered 2020-Dec-04 at 16:41the (0-3) line never gets drawn because when you hit the condition if( not vis[nb->nodeId]){
node 3 was already visited through line (0-2-3-4)
QUESTION
So basically my code iterates through the list and the original method is supposed to return the linked list however it doesn't seem to be adding the nodes that I link in the recursive method and I'm confused as to why. Can anyone help me?
...ANSWER
Answered 2020-Oct-27 at 19:36Okay, your code needs some work. Let's look at your first method. I'm going to rewrite it.
QUESTION
I created a generic linked list in C to store data of any type. That involves, of course, using the void
pointer. I know the code is working generally, but my problem is probably due to memory management surrounding the void
pointer to store an array of chars (ie C strings). Probably due to my lack of deep understanding of void
pointers in C?
It is best to show my problem using code examples below for testing purposes.
slist.h header file
...ANSWER
Answered 2020-Jul-08 at 08:39In main you do:
QUESTION
I am writing a university project, where I take two algorithms and compare their performance, the main algorithms are Dijkstra and A*, however I am not very experienced with either Vue.js, JS in general and algorithms, and my first iteration of Dijkstra is SUPER slow. I am using a 2D grid of X by Y, with a start point node and an end point node, and running the algorithm. Any grid above 10x10 is completely too slow.
I am at a loss on what to do, I don't see any errors when running the code, it executes, but executes entirely too slow. I am not very experienced, so I don't know where to start to look and what the issue could be. Maybe there's someone with experience that could help out and tell me what I'm doing wrong?
...ANSWER
Answered 2020-May-05 at 14:17Although you seem to suggest that your algorithm works, but too slow, it actually has at least one blocking error:
for (let node in toChecknext)
: this will iterate the indexes of the array, not the values. Yet you treat those values as nodes, which will lead to undesired behaviour. Change to:
QUESTION
I have a table with column cDate
.
I want to calculate the time difference between two consecutive record with the same cRt
value.
E.g.:
...ANSWER
Answered 2020-Apr-26 at 17:36There is no performant way to do this without window functions in MySql versions prior to 8.0.
One way is for every row to get the max cDate before the current cDate for the same cRt:
QUESTION
Take a look at following code and output:
...ANSWER
Answered 2020-Apr-19 at 08:06In order to experiment, I just changed your example to
display the addresses of the strings.
You can see that we cannot make any assumption about the way
each of these strings is stored relative to each other.
On my system (Linux 64-bit) I obtain:
QUESTION
I am pretty new to delphi development, I have a custom CheckTreeList component inherited from cxTreeList Devexpress component. When i check some nodes in a list, Those values are stored to a string in a format as shown below String Format for selected nodes as image The issue is I am not able to check the nodes of the checktreelist by looping through the nodes and values in the string. I have tried the below code for saving and loading the checked and unchecked nodes. Saving the checked node key values to string is working, But Loading the nodes and checking them is not working. The below is the component source code
...ANSWER
Answered 2020-Mar-29 at 20:54Update I've updated this answer to provide a complete & self-contained example of saving the check marks of the TcxTreeList to a string (or TStringList) and then re-load them, both using the string format in the Q's screenshot. I've ignored the code in the Q and written it all from scratch, because that was easier than trying to guess what exactly you are intending to do in your code - if I was doing this myself, I wouldn't use the Q's method but instead save the tree nodes' states to a TClientDataSet or the Devex equivalent.
The example requires only a few utility routines to do its job and these all take a TcxTreeList or TcxTreeListNode as an input parameter so these could be moved to another unit and re-used by other forms.
These routines are as follows:
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