kandi X-RAY | archers Summary
kandi X-RAY | archers Summary
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QUESTION
class User:
def sign_in():
print('logged in')
class Wizard(User):
def __init__(self, name, power, damage):
self.name = name
self.power = power
self.damage = damage
def attack():
print(f'attacking with {self.power} inflicting {self.damage}')
class Archer(User):
def __init__(self, name, bow, damage, arrows_left):
self.name = name
self.bow = bow
self.damage = damage
self.arrows_left = arrows_left
def attack():
print(f'{self.name} attacking with {self.bow} inflicting {self.damage}, arrows left: {self.arrows_left}')
#self.arrows_left -= 1
#print (self.arrows_left)
archer1 = Archer('Robin', 'longbow', '50', 50)
archer1.attack()
...ANSWER
Answered 2021-Jan-19 at 19:26self
is not a keyword; it is the conventional name for the required first argument of an instance method.
QUESTION
I am using a function to create a 6 element Boolean Array. I am using the array.component1() function in an if statement to turn the color of a textView object Green. Seems to work great for calling .component 1 thru 5, but I get an error trying to call array.component6(), and I don't understand why.
...ANSWER
Answered 2021-Jan-17 at 18:04The componentN
functions are intended only for destructuring declarations, and arrays/collections only define them up to five components. It would be messy (poor code readability) to destructure more than that.
You're using these functions in an unintended way. You should use array access syntax (brackets []
) to get items out of an array by index.
QUESTION
This is more a plea for guidance rather than any hard coding example. I have set myself a problem to write an archery recording system using Django. I have got the recording system working well and the system can register users, record their scores, show their scores filtered by round, show the users scores who have shot a particular round etc. This issue I have got is when it comes to classifying the score. I will explain:
- In archery scores are recorded against the round you shoot. These vary so you have 60+ rounds to choose from each having different criteria and different maximum scores.
- Archers are grouped according to gender and age (10 sub groups)
- Archers shoot one of 3 different bowtypes
- The classification system works by taking the round shot and the sub-group that the archer falls into and the bowtype used and looking across a table of values. The classification gained is the one that the score falls into i.e.
- if you are male and over 18 you are grouped as a 'Gentleman'
- The round you shoot is called a 'York' with a recurve bow and you score 550
- The table you would consult would look like this
ANSWER
Answered 2021-Jan-13 at 12:49This is possible in Django. It seems as if you're asking for a good way to store these unique scoring tables to compare archers' scores with. Otherwise, with enough logic, you can certainly classify an archer and a score to a certain class.
Django models are representations of SQL fields. This is a fine way to store your scoring tables however you have many options when it comes to storing data.
QUESTION
I am trying to make sure my navigation bar and footer stays fixed I have set both positions to fixed and also tried setting top:0 for navbar and bottom:0 for footer but I still did not get desired result, I tried to manipulate and tweak the div arrangements to make the code cleaner and get it work and still did not get desired result.Please help me out.
HTML CODE
...ANSWER
Answered 2020-Apr-20 at 04:35Please use z-index, and overflow property with your fixed item.
Updated CSS
QUESTION
I am trying to create a web page where I have a margin of 50px fixed left and right where the page images have an index that makes it closer to the screen and the margin looks farther off.I also want to achieve a fixed footer like I have for the navigation bar.I tried setting margin left and right to 50px and setting them to a fixed position and tried using the wrapper class to add to the sections both did not yield desired result.
HTML CODE:
...ANSWER
Answered 2020-Apr-18 at 13:47You did not use the id selector to reference the footer section in your css page, probably you referenced #fixed in place of footer instead, at the bottom of your CSS file.
// use this instead
QUESTION
I asked a similar question recently about a different project. In that case (see Traverse multiple foreign keys in Django DetailView), I was able to follow the flow of Foreign Keys to make the needed connection when defining the view. In this case I need to traverse through a ManyToMany junction table, and I'm stymied. Here's an ER diagram of the relevant portion of my model.
...ANSWER
Answered 2020-Apr-01 at 13:52In general the method would be:
QUESTION
I have a JSON message, and I dont know How can I write out a part of json.
I tried:
...ANSWER
Answered 2020-Feb-19 at 16:47First you have to decode
your JSON-String
to a PHP-Array
and then you can access it easily
this way:
QUESTION
I'm new to coding. I wrote the below code in C++ and I am not allow to use array.
You will create a console C++ program that uses a nested loop to enter each archer's individual end scores and then displays the total score for each archer.
I am stuck at how to calculate the total end score:
...ANSWER
Answered 2020-Jan-29 at 20:40You need to shift tEndScore =+ endScore;
this line inside the second for loop as
QUESTION
I am trying to serialise a piece of XML that is being returned from a third party API. However when doing so i am only retrieving part of the object upon serialisation. And only some of the values seem to exist. I thought this could be a input type problem, however all the types seem to be correct. I think it may have something to do with how my model is constructed.After debugging the code i have narrowed it down to be a problem with the conversion of the xml into the object.
C# CODE:
...ANSWER
Answered 2019-Oct-31 at 09:24The code below works :
QUESTION
I have to check if some moves are legal on a chessboard.
The legal moves are:
- for P (pikeman) only one square up, down, left, and right
- for A (archer) the same as for P, plus one square in diagonal (up-left, up-right, down-left, down-right)
- for K (knight) the same as for P, A, plus two squares up, down, left, right, and every diagonal direction
The algorithm I am trying to write is:
...ANSWER
Answered 2019-Oct-28 at 10:32if selected_unit.kind is 'P' or 'A' or 'K':
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