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QUESTION
I have a project where I have to create and use a print linked list method. I am able to print using a basic for loop, but receive a error: linkedlist Name<> cannot be converted to Name[] when trying to use the print method. I used a similar approach an array and it worked fine.
...ANSWER
Answered 2021-Apr-14 at 13:28printLL takes an array of Name as a parameter. Why would you expect that to work if you passed it a linkedList.
Try:
QUESTION
I'm trying to write a program that will create a database made of entries (reg), the amount of which is set by the user at runtime.
My idea was to make a type struct dynamic array to store my entries but I'm having a hard time storing the values in the array, I've tried direct assignment but that didn't work, as soon as I type in the first value the program crashes, I looked into it and most people seem to use a dedicated function to insert elements into the array, but I'm having a hard time understanding how to go about it.
ANSWER
Answered 2021-Jan-30 at 23:38IMO better way :
QUESTION
I need help to create a table, from column [B] to column [I] if the emails from the managers of column [J] are the same:
Example_01 The yellow lines have the same manager in column [J]: "rafalmfei@gmail.com", so I need to set up a single email with a table, for the manager (Column [J2] and [J3]) with a copy for o Partner E-mail "rafaalmeida_feitoa@yahoo.com.br" (column k 2 and k 3) with lines 2 and 3.
Example_02 And an email with another separate table for the manager "rafaalmeida_feitoa@yahoo.com.br", (column [4] and column [5]) with a copy for Partner E-mail "rafalmfei@gmail.com" (column k [4] and k [5]) with lines 4 and 5.
Example_03 Currently, I have the email ready with the code below, but I receive the lines in separate emails, I need it to be in a single email in table format:
...ANSWER
Answered 2020-Jun-01 at 10:46You can do the following
- Retrieve all managers from the sheet
- Use
...new Set()to retrieve unique values of managers - For each distinct manager retrieve the relevant sheet values and push them into an html table
- Send an email after iterating through all rows and retrieving all data for particular manager
SAMPLE
QUESTION
I've recently started programming in C and I'm having trouble submitting a homework on a site called run.codes. My program works fine in my computer and in several online compilers, but run.codes is giving me a "Segmentation fault" error on every test case. I suspected it had something to do with the C version that the site is using, so I tried to make my program compatible with older standards (C99), but it still not working.
Of all the online compilers I've tested, only this one gave me the same error as run.codes. In all the others, my program worked as expected. Since the "segmentation fault" error usually indicates that an unallowed attempt to access memory has ocurred, I've tried using Valgrind to track possible errors. My program happens to have several, even though it compiles and works fine in most environments.
Below is my program. I apologize the over-commenting and for the use of portuguese. My professor demands it to be that way.
...ANSWER
Answered 2019-May-19 at 21:03With the help of a friend, I've managed to solve my problem! I'm posting the solution here in case someone runs into a similar problem in the future.
Most of the errors shown in Valgrind were caused by a stack overflow. My program was simply using too much memory. To solve that, I've changed the size of the products array to a reasonable one (I was using much more than what I actually needed!). Look below:
QUESTION
I have a python dictionary containing 3 dataframes and nothing else. I need to call each dataframe by dataframe name without using d['']; for example, with the dataframe loopdata1, I need to call it without doing d['loopdata1']. Here's the dictionary with the 3 dataframes loopdata1, loopdata2, and loopdata3:
...ANSWER
Answered 2019-Mar-22 at 21:10you could append incoming dataframes together instead of adding them to a dict.
first = True
for dfname in lst:
if first = True:
main_df = pd.read_excel(dfname + '.xlsx')
first = False
else:
appending_df = pd.read_excel(dfname + '.xlsx')
main.df = main_df.append(appending_df)
QUESTION
I am start to use scrapy. I write my code following the tutorial from documentation. When i run to output a json or a csv, the file outputed is empty. When I test my selector in the shell i got the data. I will post my code:
...ANSWER
Answered 2018-Jun-29 at 07:13First, livro.css('//*[@id="description"]/text()').extract_first(), should be livro.xpath('//*[@id="description"]/text()').extract_first(),. Using xpath inside a css selector will raise an exception that will kill the scraping process and that's probably the reason why you don't get anything on your output.
Second, line breaks like \r\n\t will be keeped on your json file and they will be rendered or not based on the software you use to inspect the json file. If you want to remove then you can use the strip() function:
QUESTION
I have to make a insert procedure that takes indefinite number of arguments so for example
...ANSWER
Answered 2018-Jun-03 at 18:27You could create a type as a table and pass a variable of that type. Like:
QUESTION
::UPDATED CODE::
I have dynamically generated buttons from an array. When a button is clicked, 10 still images of gifs append to the page from an API call. When clicking on one of the dynamically generated still images, I need the animated gif to display. Upon clicking again, I need the still image to show and the animated gif to hide.
...ANSWER
Answered 2017-Dec-13 at 18:49I think you need to set the gif url as a property of the img element you are creating with jQuery. Something like:
QUESTION
I am making a gif generator, the goal being to dynamically create clickable buttons that will then dynamically add 10 gifs from the search term to the page. On click is returning the console log, but will not add divs with gif images and rating to the page.
HTML
...ANSWER
Answered 2017-Dec-12 at 05:29response is an Object.
response.length is an undefined.
response.data is an Array.
If you want image also, Then you should append killerImg also.
QUESTION
I've come across several occasions where I've wanted to use blank nodes in a CONSTRUCT query, but I've needed to get the same blank node for all (or several) query solutions.
Let's say that we have in our dataset a list of authors and books they have written:
...ANSWER
Answered 2017-Sep-11 at 12:37After having pondered this for some time I came up with something that I think is a general solution. I haven't tried it on many SPARQL implementations yet though so please provide feedback if you find that it isn't working for you. Basically, after realizing that we can't do anything about how SPARQL processes the data in the result part of the query we naturally start thinking about binding the blank node to a variable instead. So, let's say we try something like:
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