gavatar | Web app to generate avatars for GitHub
kandi X-RAY | gavatar Summary
kandi X-RAY | gavatar Summary
Web app to generate avatars for GitHub.
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- Download a file to the download .
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QUESTION
I'm using NodeJS for a a complex query in Mysql. Firstly I need to grab tagid1
, tagid2
and tagid3
from the entitytag
table. Then I need to use those fetched tagids to get the tagname to each tagid in the tags
table. Here is a query that produces an error which tells me that "tagid1 is not defined".
ANSWER
Answered 2021-Jul-24 at 13:38I am suggesting a rewrite of your query after a few observations. I noticed a few similarities throughout your code and also observed that you stated that you are trying to retrieve tagid1-3
first.
As such, I have rewritten the query to utilize LEFT JOIN
s as this will include the details if available and aliases for simplification.
Now the query retrieves the entitytag
record based on the et.audioid = ap.audioid
as shown in your original query but does not need the tagId as a query paramter i.e. here [tagid1, tagid2, tagid3, audioid ]
since the objective, garnered from your select/projection is to retrieve the tagId and tagname of tagid1-3
.
Now that we would match the entitytag
record if it exists, we may continue by retrieving the related tag information from the tag table. I have done this using 3 additional LEFT JOINs to the same table but with differentiating aliases eg LEFT JOIN tags t{num} ON et.tagid1 = t{num}.tagid
where num
represented the 1-3
for each tag. If these details are available they are retrieved as non-null values in the projection using
QUESTION
I've got this NodeJS endpoint which should fetch all replies to post number 201 from a MySQL database.
...ANSWER
Answered 2021-May-13 at 11:02 Audiopost.findByOpId = (repliesId, result) => {
sql.query(`
SELECT
ap.audioname,
ap.userid,
ap.audioid,
ap.title,
ap.likes,
ap.opid,
u.gavatar,
u.name,
u.email,
(
SELECT GROUP_CONCAT(t.tagname)
FROM entitytag et
LEFT JOIN tags t on t.tagid = et.tagid
WHERE et.audioid = ap.audioid
) tagname,
(
select count(*) from audioposts AS apost WHERE apost.opid = ap.audioid
) as replycount
FROM audioposts ap
LEFT JOIN users u ON u.id = ap.userid
WHERE ap.opid = ${repliesId}
`, (err, res) => {
if (err) {
console.log("error: ", err);
result(err, null);
return;
}
if (res.length) {
result(null, res);
return;
}
result({ kind: "not_found" }, null);
});
};
QUESTION
Currently, my code returns a message which says 'Registration successful'. How can I return the id of the row I just created in MySQL instead?
...ANSWER
Answered 2021-Apr-29 at 08:10based on your updated code your .register
function is actually returning nothing. What you should do is update that function making it return the new created ID, or the already existing ID (if you need it).
QUESTION
Here's a simple MySQL query I'm using in NodeJS which works just fine;
...ANSWER
Answered 2021-Apr-26 at 20:03Newlines aren't allowed in single- and double-quoted strings in javascript. You'll need to either replace all the line breaks with \n
or use backticks instead of quotes to define your string. Backticks (`) create a template literal, which allows newlines.
QUESTION
Can anybody see why I'm getting this error on the first child: Column? I'm using a stack in my build. and tried wrapping each widget in a Flexible widget but can't figure out where the code is overflowing. The screen flashes the telltale yellow/black renderflex lines for just a second but then seems to render just fine. The messages in the console are annoying though as is the little yellow/black flash at the beginning.
...ANSWER
Answered 2020-Jul-29 at 19:41you can wrap your whole body content as a child of SingleChildScrollView SinglechildScrollView widget which may help you to overcome from this issue,or you can also make use of listview which can arrange list of widgets properly ListView
QUESTION
Would it be possible to join the following two queries so that the tags for each audioid are included in the returned array?
...ANSWER
Answered 2020-Aug-01 at 15:09It looks like you just want more left join
s:
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