dictionaries | Hunspell dictionaries in UTF-8
kandi X-RAY | dictionaries Summary
kandi X-RAY | dictionaries Summary
Collection of normalized and easily installable hunspell dictionaries. Useful with nodehun, nspell, and others.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of dictionaries
dictionaries Key Features
dictionaries Examples and Code Snippets
Lines of Code : 9
License : No License
Copydef pluck(lst, key):
return [x.get(key) for x in lst]
simpsons = [
{ 'name': 'lisa', 'age': 8 },
{ 'name': 'homer', 'age': 36 },
{ 'name': 'marge', 'age': 34 },
{ 'name': 'bart', 'age': 10 }
]
pluck(simpsons, 'age') # [8, 36, 34, 10]
def merge(self, x=None, y=None, ildj_map=None, kwargs=None, mapping=None):
"""Returns new _Mapping with args merged with self.
Args:
x: `Tensor`. Forward.
y: `Tensor`. Inverse.
ildj_map: `Dictionary`. This is a mapping from def _pyval_find_struct_keys_and_depth(pyval, keys):
"""Finds the keys & depth of nested dictionaries in `pyval`.
Args:
pyval: A nested structure of lists, tuples, and dictionaries.
keys: (output parameter) A set, which will be update def _convert_decode_csv(pfor_input):
lines = pfor_input.stacked_input(0)
record_defaults = [
pfor_input.unstacked_input(i) for i in range(1, pfor_input.num_inputs)
]
field_delim = pfor_input.get_attr("field_delim")
use_quote_delim = p Community Discussions
Trending Discussions on dictionaries
QUESTION
I have a dictionary of deeply nested dictionaries and I am trying to remove all k-v pairs that are None or "". The below dictionary d is an example of the input.
ANSWER
Answered 2021-Jan-28 at 20:48You can use recursion with a dictionary comprehension:
QUESTION
I was looking for 'Network access: Allow anonymous SID/Name translation' in XML output and it isn't in the file but it exists in HTML version. Is there a work around?
...ANSWER
Answered 2021-Jun-14 at 23:19You'll find 'Network access: Allow anonymous SID/Name translation' named as LSAAnonymousNameLookup, so try
QUESTION
I have multiple dictionaries in one variable results. How to return only 1st dictionary value from that?
...ANSWER
Answered 2021-Jun-14 at 14:20If you have a list or a tuple of dictionaries, you can use indexing:
QUESTION
I have a couple of arcs dataframes with a very similar structure to these:
Ah: i j 0 1 1 1 1 2 2 2 1 3 2 2 K: Ok Dk 0 3 4 1 1 2 2 2 1I need to find a way to create a new dataframe that merges both, following this structure:
Route: Ok i j Dk 0 3 1 1 4 1 3 1 2 4 2 3 2 1 4 3 3 2 2 4 4 1 1 1 2 5 1 1 2 2 6 1 2 1 2 7 1 2 2 2 8 2 1 1 1 9 2 1 2 1 10 2 2 1 1 11 2 2 2 1or this structure:
Route: i j k 0 1 1 0 1 1 2 0 2 2 1 0 3 2 2 0 4 1 1 1 5 1 2 1 6 2 1 1 7 2 2 1 8 1 1 2 9 1 2 2 10 2 1 2 11 2 2 2Currently I have a piece of code that can do something similar to that but instead of a pandas dataframe (which is what I want to use) I'm using dictionaries (the reason behind that is that each "route" has different caracteristics that makes them unique from each other so a dictionary is useful and at the time I was just learning Python) but the issue is that it takes too much time and uses a lot of memory so I'm trying to find a way to make it a little bit quicker, avoiding 'for' loops and trying to apply Pandas to create the merged dataframe.
This is an extract of the structure of my current piece of code, for this example, consider the 'A' dataframe as the one that holds every combination possible of arcs so the 'if' condition makes sure that a connection exists before creating the route.
...ANSWER
Answered 2021-Jun-14 at 14:22I think you can use pandas Concat function to merge your dictionaries the way you want to. https://pandas.pydata.org/pandas-docs/stable/user_guide/merging.html
It's kind of hard to see how you want it to be laid out, but I think you want to use .merge
QUESTION
I have a dataframe, something like:
...ANSWER
Answered 2021-Jun-14 at 10:09You can try the following:
QUESTION
Similar questions to this have been asked many times, but surprisingly few of the answers seem to address what I believe my problem to be.
I have csv files with one or more columns that contain a dictionary in each cell. After read_csv step, I have tried ast.literal_eval on these columns in order to convert the str format dicts into dict type objects. However, I keep getting the malformed node or string error.
Here is a typical example of the dicts in question: {1: 3681.45, 0: 3693.3333333333335}. And another, with a nan value: {1: 4959.95652173913, 0: nan}. Edit: It was only this nan value causing the error, in fact (see Rakesh's solution below).
Looking through previous answers, one reason for this error may be because most of the values of the dicts in these columns are floating point numbers, and apparently literal_eval can't handle floats or nans, even if they're contained within dictionaries (although, this is me inferring from a question about tuples).
I had to read a lot of questions and answers even to get this much information, so thought it could be useful to start a new topic with the keywords str, dict, but also nan in the title.
Any help much appreciated!
...ANSWER
Answered 2021-Jun-13 at 17:41Use eval on json that has nan
Ex:
QUESTION
So, I have a fun issue. I have some data that have a fun nested dictionary that I need to manipulate, but am having trouble. I can do it in pure python, but wanted to do the entire solution in Pandas so as to keep the code a little cleaner and not have to re-open the same files elsewhere.
Dataframe:
...ANSWER
Answered 2021-Jun-13 at 17:17One way:
- Create another
list of dictviato_dict('records'). zipanditerateover both thelist of dict.Updatethe 1st one with the other to get the desiredJSON.
QUESTION
This is perfect for what I need an no one seems to be answering it:
So, I have a fun issue. I have some data that have a fun nested dictionary that I need to manipulate, but am having trouble. I can do it in pure python, but wanted to do the entire solution in Pandas so as to keep the code a little cleaner and not have to re-open the same files elsewhere.
I have the following Dataframe:
...ANSWER
Answered 2021-Jun-13 at 18:14Have you tried the pd.to_dict() options? You can pass in different ways of presenting your data. orient=records or orient=index might help you. Docs are here https://pandas.pydata.org/pandas-docs/stable/reference/api/pandas.DataFrame.to_dict.html.
QUESTION
I want to store basketball player information, and the things I want to store are Player name and Player height. Also, I want to be able to iterate using loops through that list, so therefore I made a list of dictionaries to achieve that? I am not sure if everything is correct?
The code:
...ANSWER
Answered 2021-Jun-13 at 15:15check the code in your first for loop, you append data inconsistantly.
QUESTION
As the title says I'm trying to sort a list of nested dictionaries without knowing its keys.
If possible I'd like to use one of the 2 following functions to solve my problem:
I want it to be sorted by occurrences OR tf-idf (same shit)
I've currently tried both with lambdas but nothing worked.
Sample of my data:
...ANSWER
Answered 2021-Jun-12 at 14:07You can pass lambda to sorted function as key:
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
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Install dictionaries
I’ve only tested this on macOS, but there you at least need to install:. Note that the GNU replacements should be setup in PATH to overwrite macOS defaults.
wget: brew install wget (crawling)
hunspell: brew install hunspell (many dictionaries)
coreutils: brew install coreutils (many dictionaries)
ispell: brew install ispell (German)
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