forward-ref | A Higher Order Component for React.forwardRef | Frontend Utils library

 by   wowlusitong JavaScript Version: 1.0.0 License: MIT

kandi X-RAY | forward-ref Summary

kandi X-RAY | forward-ref Summary

forward-ref is a JavaScript library typically used in User Interface, Frontend Utils, React applications. forward-ref has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can install using 'npm i forward-ref' or download it from GitHub, npm.

A Higher Order Component for React.forwardRef
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            kandi-support Support

              forward-ref has a low active ecosystem.
              It has 4 star(s) with 0 fork(s). There are 1 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              forward-ref has no issues reported. There are 22 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of forward-ref is 1.0.0

            kandi-Quality Quality

              forward-ref has no bugs reported.

            kandi-Security Security

              forward-ref has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              forward-ref is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              forward-ref releases are not available. You will need to build from source code and install.
              Deployable package is available in npm.
              Installation instructions are not available. Examples and code snippets are available.

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            forward-ref Key Features

            No Key Features are available at this moment for forward-ref.

            forward-ref Examples and Code Snippets

            No Code Snippets are available at this moment for forward-ref.

            Community Discussions

            QUESTION

            VSCode python refactoring: Rename symbol not working with attributes in class operator implementation
            Asked 2021-Apr-16 at 16:06
            class MyClass:
                def __init__(self, my_attribute):
                    self.my_attribute = my_attribute
                
                def __eq__(self, other):
                    return self.my_attribute == other.my_attribute
            
            ...

            ANSWER

            Answered 2021-Apr-16 at 16:06

            This is no usage fault and seems to be a bug, according to jonrsharpe's comment an bug report is useful now, so I now opened an issue on github https://github.com/microsoft/vscode-python/issues/15922 .

            Edit: The problem seems to be specific to python's language server jedi, which is currently the standard on vscode python. Changing the language server (python.languageServer) to "microsoft" resolves the problem when using one of the type hint variants.

            Edit2: I also tested pylance and it renames on all cases.

            I got an answer of the maintainer of jedi (see, i bolded the important parts):

            This is something that's simply not fixable. How would Jedi know that other is a MyClass? This is simply a heuristic. I know that we could theoretically assume this, but I'm not sure that's a great idea. I will definitely keep it in mind for the Rust version that I'm writing, but this will not happen in Jedi. Sorry. There are a lot of cases where Python's dynamic nature is kind of a problem. And I chose to not use heuristics for all of these (because it makes Jedi also slower).

            Later he wrote (bolding done by me):

            I understand. Would it be possible to handle this like pycharm does? Inquiring the user on such a case, to let him/her choose what to do or do things like LSP not support such inquiring?

            AFAIK the LSP protocol does not support this (I have read it quite thoroughly). IMO that's the correct approach with such names. However it's still unlikely that Jedi will support this, because the Jedi's API is probably not made for this. However I will keep it in mind for the next autocompletion project that I'm doing :).

            I think that makes it pretty clear.

            Source https://stackoverflow.com/questions/67047309

            QUESTION

            Convert Pine-Script version 2.0 to version 4.0
            Asked 2021-Mar-19 at 13:31

            I need to convert this PineScript Study from v2.0 to v4.0

            ...

            ANSWER

            Answered 2021-Mar-19 at 13:07
            //@version=4
            study("trendFilter", "TF", overlay=true)
            
            //
            Pd=input(200)
            Factor=input(0.9)
            //
            
            var float   Tsl         = na
            var float   t           = na
            var float   TrendUp     = na
            var float   TrendDown   = na
            var float   Trend       = na
            
            P = pow(Pd,2)
            a = 2/(P+1)
            d = abs(close - nz(Tsl[0],hl2))
            t := a*d+(1-a)*nz(t[1],d)
            src = Factor*nz(Tsl[0],hl2) + (1-Factor)*close
            Up=nz(Tsl[0],hl2)-t
            Dn=nz(Tsl[0],hl2)+t
            //
            TrendUp := src[1]>TrendUp[1]? max(Up,TrendUp[1]) : Up
            TrendDown := src[1] TrendDown[1] ? 1: src< TrendUp[1]? -1: nz(Trend[1],1)
            Tsl := Trend==1? TrendDown : TrendUp
            css = Tsl > Tsl[1] ? #0080FF : Tsl < Tsl[1] ? #FF0040 : na
            plot(Tsl,color=fixnan(css),transp=0)
            

            Source https://stackoverflow.com/questions/66708625

            QUESTION

            Nested class "does not name a type"
            Asked 2020-May-26 at 21:54

            I'm getting the following error:

            ...

            ANSWER

            Answered 2020-May-26 at 21:54

            From a comment to the question

            Also - I have no problem calling member function f in member function q where f is defined after q. Can you explain why the latter example is different than the situation described in this question?

            According to the C++ 20 Standard (11.4 Class members)

            6 A complete-class context of a class is a

            > (6.1) — function body (9.5.1),

            (6.2) — default argument (9.3.3.6),

            (6.3) — noexcept-specifier (14.5), or

            (6.4) — default member initializer

            within the member-specification of the class

            So inside the complete class context the name of the function f is visible within the body of the function q.

            However the inner class is declared outside the complete class context. So according to the C++ 20 Standard (6.5.1 Unqualified name lookup)

            7 A name used in the definition of a class X23 outside of a complete-class context (11.4) of X shall be declared in one of the following ways:

            > (7.1) — before its use in class X or be a member of a base class of X (11.8), or ...

            So the name of the inner class Iterator must be declared before its using as a return type of a member function.

            Instead of the name Iterator you could use for example the place holder auto as the return type.

            Source https://stackoverflow.com/questions/62031661

            QUESTION

            Alternative to forwardRef in newer Angular versions?
            Asked 2020-May-19 at 22:31

            I'm trying to update an old project to the latest version of Angular and I discovered that this line

            ...

            ANSWER

            Answered 2017-Jun-20 at 11:53

            It sounds like you have a circular dependency in your injection setup. forwardRef is there to resolve some of these types of issues as classes aren't hoisted and this can cause some type instance resolution errors. You are getting the tslint error because the style guide suggests that you restructure your app to not have dependency resolution issues rather than rely on forwardRef.

            If someone has added forwardRef earlier in your code, then it is probably for a reason - so removing it will possibly give you a different error. I would try to hoist the MapComponent in the code and then remove the forwardRef declaration - as I suspect some other issue is at the root of a stalled bootstrap in this instance

            Source https://stackoverflow.com/questions/44651189

            QUESTION

            Spring unresolved forward reference in Many to One
            Asked 2020-Mar-24 at 12:26

            I have a task and a user entity, with a one-to-many relationship. So in english a user can have multiple tasks, and a task belongs to a single user

            ...

            ANSWER

            Answered 2020-Mar-24 at 11:31

            You need to create and bind an object implementing ObjectIdResolver with autowired EntityManager. Jackson is clueless otherwise how to find the correct entity, since there is no relationship between the ORM implementation and de/serialization library in this case.

            This resolver itself is:

            Definition of API used for resolving actual Java object from Object Identifiers (as annotated using JsonIdentityInfo).

            The key method is ObjectIdResolver::resolveId where you get the item to be matched by its ID using the following method:

            Sample code:

            Source https://stackoverflow.com/questions/60829974

            QUESTION

            React with Typescript -- Generics while using React.forwardRef
            Asked 2020-Feb-17 at 10:54

            I am trying to create a generic component where a user can pass the a custom OptionType to the component to get type checking all the way through. This component also required a React.forwardRef.

            I can get it to work without a forwardRef. Any ideas? Code below:

            WithoutForwardRef.tsx

            ...

            ANSWER

            Answered 2020-Feb-17 at 10:54

            Creating a generic component as output of React.forwardRef is not directly possible1 (see bottom for further info). There are some alternatives though - let's simplify your example a bit for illustration:

            Source https://stackoverflow.com/questions/58469229

            QUESTION

            pass forwardRef via cloneElement reactjs
            Asked 2019-Nov-22 at 13:41
            const ref = useRef()  
            
             React.Children.map(this.props.children, (element) => {
               React.cloneElement(element, { 
                 innerRef: node => ref,
               })
             })
            
            ...

            ANSWER

            Answered 2019-Nov-22 at 13:41

            Try changing innerRef to ref, you adding innerRef property and expecting it to be valid at ref:

            Source https://stackoverflow.com/questions/58803654

            QUESTION

            RegEx for matching forward reference exercise
            Asked 2019-May-03 at 20:02

            I am working on an exercise on regex forward reference like the one asked here

            The task is:

            • string s consists of tic or tac
            • tic should not be immediate neighbour of itself
            • The first tic must occur only when tac has appeared at least twice before

            I've used this regex to solve it. But it doesn't use forward reference so I really want to know how this can be solved using it.

            ...

            ANSWER

            Answered 2019-May-03 at 15:30

            If there should be at least 2 tics in the string, you might use a negative lookahead to assert that there is no tictic present and start by matching and least 2 times tic

            Source https://stackoverflow.com/questions/55972259

            QUESTION

            Does Python evaluate type hinting of a forward reference?
            Asked 2019-Mar-25 at 18:35

            I was looking at the PEP 484 section on Forward References and noticed the statement:

            ...that definition may be expressed as a string literal, to be resolved later.

            And that got me wondering, when is "later" and by what? The interpreter doesn't try to resolve it as a literal later, so what does? Is it just if a third party tool is written to do that?

            Small example to demonstrate the interpreter result:

            ...

            ANSWER

            Answered 2019-Mar-25 at 18:35

            Consider the following code:

            Source https://stackoverflow.com/questions/55320236

            QUESTION

            about python recursive import in python3 when using type annotation
            Asked 2018-Mar-01 at 04:22

            After spending another three hours, I thought I may got the solution.forward-references

            if there isn't any better way to do this, I'll close this question later and post that solution

            I'm doing reverse engineering on a program (and try to implement it using Python).

            I got this problem

            for example I have a class in ComponentOfCar.py, the code is as follows

            ...

            ANSWER

            Answered 2018-Feb-28 at 17:30

            Hope this would help,

            component.py

            Source https://stackoverflow.com/questions/49023836

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install forward-ref

            You can install using 'npm i forward-ref' or download it from GitHub, npm.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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            Install
          • npm

            npm i forward-ref

          • CLONE
          • HTTPS

            https://github.com/wowlusitong/forward-ref.git

          • CLI

            gh repo clone wowlusitong/forward-ref

          • sshUrl

            git@github.com:wowlusitong/forward-ref.git

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