forward-ref | A Higher Order Component for React.forwardRef | Frontend Utils library
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kandi X-RAY | forward-ref Summary
A Higher Order Component for React.forwardRef
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QUESTION
class MyClass:
def __init__(self, my_attribute):
self.my_attribute = my_attribute
def __eq__(self, other):
return self.my_attribute == other.my_attribute
...ANSWER
Answered 2021-Apr-16 at 16:06This is no usage fault and seems to be a bug, according to jonrsharpe's comment an bug report is useful now, so I now opened an issue on github https://github.com/microsoft/vscode-python/issues/15922 .
Edit: The problem seems to be specific to python's language server jedi, which is currently the standard on vscode python. Changing the language server (python.languageServer) to "microsoft" resolves the problem when using one of the type hint variants.
Edit2: I also tested pylance and it renames on all cases.
I got an answer of the maintainer of jedi (see, i bolded the important parts):
This is something that's simply not fixable. How would Jedi know that other is a MyClass? This is simply a heuristic. I know that we could theoretically assume this, but I'm not sure that's a great idea. I will definitely keep it in mind for the Rust version that I'm writing, but this will not happen in Jedi. Sorry. There are a lot of cases where Python's dynamic nature is kind of a problem. And I chose to not use heuristics for all of these (because it makes Jedi also slower).
Later he wrote (bolding done by me):
I understand. Would it be possible to handle this like pycharm does? Inquiring the user on such a case, to let him/her choose what to do or do things like LSP not support such inquiring?
AFAIK the LSP protocol does not support this (I have read it quite thoroughly). IMO that's the correct approach with such names. However it's still unlikely that Jedi will support this, because the Jedi's API is probably not made for this. However I will keep it in mind for the next autocompletion project that I'm doing :).
I think that makes it pretty clear.
QUESTION
I need to convert this PineScript Study from v2.0 to v4.0
...ANSWER
Answered 2021-Mar-19 at 13:07//@version=4
study("trendFilter", "TF", overlay=true)
//
Pd=input(200)
Factor=input(0.9)
//
var float Tsl = na
var float t = na
var float TrendUp = na
var float TrendDown = na
var float Trend = na
P = pow(Pd,2)
a = 2/(P+1)
d = abs(close - nz(Tsl[0],hl2))
t := a*d+(1-a)*nz(t[1],d)
src = Factor*nz(Tsl[0],hl2) + (1-Factor)*close
Up=nz(Tsl[0],hl2)-t
Dn=nz(Tsl[0],hl2)+t
//
TrendUp := src[1]>TrendUp[1]? max(Up,TrendUp[1]) : Up
TrendDown := src[1] TrendDown[1] ? 1: src< TrendUp[1]? -1: nz(Trend[1],1)
Tsl := Trend==1? TrendDown : TrendUp
css = Tsl > Tsl[1] ? #0080FF : Tsl < Tsl[1] ? #FF0040 : na
plot(Tsl,color=fixnan(css),transp=0)
QUESTION
I'm getting the following error:
...ANSWER
Answered 2020-May-26 at 21:54From a comment to the question
Also - I have no problem calling member function f in member function q where f is defined after q. Can you explain why the latter example is different than the situation described in this question?
According to the C++ 20 Standard (11.4 Class members)
6 A complete-class context of a class is a
> (6.1) — function body (9.5.1),
(6.2) — default argument (9.3.3.6),
(6.3) — noexcept-specifier (14.5), or
(6.4) — default member initializer
within the member-specification of the class
So inside the complete class context the name of the function f
is visible within the body of the function q
.
However the inner class is declared outside the complete class context. So according to the C++ 20 Standard (6.5.1 Unqualified name lookup)
7 A name used in the definition of a class X23 outside of a complete-class context (11.4) of X shall be declared in one of the following ways:
> (7.1) — before its use in class X or be a member of a base class of X (11.8), or ...
So the name of the inner class Iterator
must be declared before its using as a return type of a member function.
Instead of the name Iterator you could use for example the place holder auto
as the return type.
QUESTION
I'm trying to update an old project to the latest version of Angular and I discovered that this line
...ANSWER
Answered 2017-Jun-20 at 11:53It sounds like you have a circular dependency in your injection setup. forwardRef
is there to resolve some of these types of issues as classes aren't hoisted and this can cause some type instance resolution errors. You are getting the tslint
error because the style guide suggests that you restructure your app to not have dependency resolution issues rather than rely on forwardRef
.
If someone has added forwardRef
earlier in your code, then it is probably for a reason - so removing it will possibly give you a different error.
I would try to hoist the MapComponent in the code and then remove the forwardRef declaration - as I suspect some other issue is at the root of a stalled bootstrap in this instance
QUESTION
I have a task and a user entity, with a one-to-many relationship. So in english a user can have multiple tasks, and a task belongs to a single user
...ANSWER
Answered 2020-Mar-24 at 11:31You need to create and bind an object implementing ObjectIdResolver
with autowired EntityManager
. Jackson is clueless otherwise how to find the correct entity, since there is no relationship between the ORM implementation and de/serialization library in this case.
This resolver itself is:
Definition of API used for resolving actual Java object from Object Identifiers (as annotated using JsonIdentityInfo).
The key method is ObjectIdResolver::resolveId
where you get the item to be matched by its ID using the following method:
Sample code:
QUESTION
I am trying to create a generic component where a user can pass the a custom OptionType
to the component to get type checking all the way through. This component also required a React.forwardRef
.
I can get it to work without a forwardRef. Any ideas? Code below:
WithoutForwardRef.tsx
...ANSWER
Answered 2020-Feb-17 at 10:54Creating a generic component as output of React.forwardRef
is not directly possible1 (see bottom for further info). There are some alternatives though - let's simplify your example a bit for illustration:
QUESTION
const ref = useRef()
React.Children.map(this.props.children, (element) => {
React.cloneElement(element, {
innerRef: node => ref,
})
})
...ANSWER
Answered 2019-Nov-22 at 13:41Try changing innerRef
to ref
, you adding innerRef
property and expecting it to be valid at ref
:
QUESTION
I am working on an exercise on regex forward reference like the one asked here
The task is:
- string s consists of tic or tac
- tic should not be immediate neighbour of itself
- The first tic must occur only when tac has appeared at least twice before
I've used this regex
to solve it. But it doesn't use forward reference
so I really want to know how this can be solved using it.
ANSWER
Answered 2019-May-03 at 15:30If there should be at least 2 tics in the string, you might use a negative lookahead to assert that there is no tictic present and start by matching and least 2 times tic
QUESTION
I was looking at the PEP 484 section on Forward References and noticed the statement:
...that definition may be expressed as a string literal, to be resolved later.
And that got me wondering, when is "later" and by what? The interpreter doesn't try to resolve it as a literal later, so what does? Is it just if a third party tool is written to do that?
Small example to demonstrate the interpreter result:
...ANSWER
Answered 2019-Mar-25 at 18:35Consider the following code:
QUESTION
After spending another three hours, I thought I may got the solution.forward-references
if there isn't any better way to do this, I'll close this question later and post that solution
I'm doing reverse engineering on a program (and try to implement it using Python).
I got this problem
for example I have a class in ComponentOfCar.py, the code is as follows
...ANSWER
Answered 2018-Feb-28 at 17:30Hope this would help,
component.py
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