jump | 低配版 “ 跳一跳 ” ,基于Three.js - 低配版 “ 跳一跳 ” | Graphics library

 by   xmoyKing JavaScript Version: Current License: No License

kandi X-RAY | jump Summary

kandi X-RAY | jump Summary

jump is a JavaScript library typically used in User Interface, Graphics, Three.js, WebGL applications. jump has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

低配版“跳一跳”,基于Three.js
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            kandi-support Support

              jump has a low active ecosystem.
              It has 31 star(s) with 8 fork(s). There are 2 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 1 open issues and 0 have been closed. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of jump is current.

            kandi-Quality Quality

              jump has 0 bugs and 0 code smells.

            kandi-Security Security

              jump has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              jump code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              jump does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
              OutlinedDot
              Without a license, all rights are reserved, and you cannot use the library in your applications.

            kandi-Reuse Reuse

              jump releases are not available. You will need to build from source code and install.
              jump saves you 42 person hours of effort in developing the same functionality from scratch.
              It has 112 lines of code, 0 functions and 6 files.
              It has low code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

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            Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of jump
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            jump Key Features

            No Key Features are available at this moment for jump.

            jump Examples and Code Snippets

            No Code Snippets are available at this moment for jump.

            Community Discussions

            QUESTION

            Minimum Jump Array Recursive Time Complexity should be O(n^n) or O(n!)
            Asked 2021-Jun-15 at 09:21

            I was checking "minimum number of jumps to reach the end" problem in GeekforGeeks https://www.geeksforgeeks.org/minimum-number-of-jumps-to-reach-end-of-a-given-array/ . I got confused about the time complexity mentioned there which is O(n^n).

            ...

            ANSWER

            Answered 2021-Jun-15 at 07:34

            I can see the recurse relation as T(n) = T(n-1) + T(n-2) + T(n-3) + T(n-4) + ... + T(0), since the loop is from l to h (ignore the if condition for now). So for an interval [l,h] every value in that interval will be called in the worst case that is minJumps(l+1, h), minJumps(l+2, h) ... minJumps(h, h) and it can be noticed that the above recurse relation holds here.

            Now, solving the relation, we can write it as T(n) = T(n-1) + T(n-1) as T(n-1) = T(n-2) + T(n-3) + T(n-4) + ... + T(0). Hence T(n) = 2 * T(n-1) which boils down to O(2^n).

            The time complexity of the mentioned algorithm should be O(2^n).

            Source https://stackoverflow.com/questions/67980936

            QUESTION

            join unordered pairs of connected edges using numpy only
            Asked 2021-Jun-15 at 08:27

            I have a concave hull (not convex) that I have the points for eg: A,B,C,D,E. I've gotten the pairs of points that make up the outer edges. [A,B],[A,E],[C,D],[B,C],[E,D]. (This is a very simplified version)

            I want to get the connected points in order (CW or CCW doesn't matter) so I can use them as a contour.

            But the pairs are not ordered, you can see A goes to B, then A goes to E, etc. The only solution I had was searching for each point and its next pair sequentially in a loop

            Is there a way to solve this using numpy only in a vectorized manner so that its fast for a large array of edges? I know shapely exists but I have trouble installing it and I'd prefer no external dependancies

            this is my code:

            ...

            ANSWER

            Answered 2021-Jun-15 at 08:27

            You can do this efficiently with a dictionary:

            Source https://stackoverflow.com/questions/67975951

            QUESTION

            Polygonization of disjoint segments
            Asked 2021-Jun-15 at 06:36

            The problem is the following: I got a png file : example.png

            • that I filter using chan vese of skimage.segmentation.chan_vese

              • It's return a png file in black and white.
            • i detect segments around my new png file with cv2.ximgproc.createFastLineDetector()

              • it's return a list a segment

            But the list of segments represent disjoint segments.

            I use two naive methods to polygonize this list of segment:

            -It's seems that cv2.ximgproc.createFastLineDetector() create a almost continuous list so I just join by creating new segments:

            ...

            ANSWER

            Answered 2021-Jun-15 at 06:36

            So I use another library to solve this problem: OpenCV-python

            We got have also the detection of segments( which are not disjoint) but with a hierarchy with the function findContours. The hierarchy is useful since the function detects different polygons. This implies no problems of connections we could have with the other method like explain in the post

            Source https://stackoverflow.com/questions/67932354

            QUESTION

            How can I create a double array in MIPS assembly language?
            Asked 2021-Jun-14 at 17:49

            I am new to MIPS assembly. I am trying to convert a java code to MIPS code but I can't figure it out that how can I load and store double values in MIPS. I get this error "address not aligned on doubleword boundary 0x10010001". Here is the java code:

            ...

            ANSWER

            Answered 2021-Jun-14 at 17:49

            Use syscall function code 3 to print doubles (not function code 2 — that's for single float).

            Use mov.d to copy one register to another, e.g. into $f12 for sycalls (then no need to load 0.0 into $f0).

            (Also, use l.d instead of ldc1.)

            The loop: loop isn't a loop (there is no backward branch for it).

            As @Peter says, your scaling/offsets are not properly accounting for the size of double, which is 8.  Scaling needs to multiply by 8 (shift by 3, not 2), and offsets need to be multiples of 8.

            Your first loop, when its done, should not EXIT the program but rather continue with the next statement (i.e. the printing loop).

            For this statement numbers[i+2] = numbers[i+1] + numbers[i]; there are two loads and one store as array references, whereas the assembly code is doing 3 loads and no store.

            You use $s5, but never put anything in it.

            The comparison of numbers[i+1] < 150 has to be done in (double) floating point, whereas the assembly code is attempting this in integer registers.

            Floating point comparison is done using c.eq.d, c.lt.d, or c.le.d.  Like with integer compares, constants need to be in registers before the compare instruction.  150.0 would best come directly from memory (as a double constant) before the loop and remain there for the loop duration (or you can move integer 150 into a floating point register and convert that to double (cvt.w.d)).

            Conditional branches on floating point compare conditions use either bc1t or bc1f (depending on the sense you want).

            The C-like pseudo code probably doesn't run properly.  The exit condition for the first loop is suspect — it will probably run off the end of the array (depending on its initial data values).

            Translating non-working C code into assembly is a recipe for frustration.  Suggest getting it working in C first; run it to make sure it works.

            Source https://stackoverflow.com/questions/67970597

            QUESTION

            STM32H743VI jumps randomly in a nonflashable state
            Asked 2021-Jun-14 at 11:54

            we are using a STM32H743VIT6 on a custom board with a JLink debugger. Out of the blue the processor jumps in a state where it isn't possible to flash the ECU anymore. The board is running but nether JMem nor our IDE (uVision) are able to access or detect the controller. Has anyone else encountered this behaviour so far? Google wasn't helpful either.

            ...

            ANSWER

            Answered 2021-May-30 at 19:21

            It is almost impossible to archive unless you enable RDP (which is very hard to archive if it was not the intention of the programmer).

            You probably have screw-up the board design. You should have pull-up resistors on the debug lines and NRST connected to the programmer.

            If you do not have NRST available simple solder the wire to the NRST, and when the programming probe connects to the uC, connect it to the GND.

            If the NRST line is connected to the programmer you need to select nn the configuration "Connect under Reset"

            Source https://stackoverflow.com/questions/67763793

            QUESTION

            GCC emits a label that's not jumped to by anything outside that label?
            Asked 2021-Jun-14 at 11:27

            Taking the following C code

            ...

            ANSWER

            Answered 2021-Jun-14 at 11:23

            If you read the assembler code from the top you will see that it reaches .L3, plus it also jumps to it with jne .L3, which is your for loop in C.

            Source https://stackoverflow.com/questions/67969134

            QUESTION

            Fix caret position on contenteditable div
            Asked 2021-Jun-14 at 08:11

            I have a div with contenteditable="true" and resize: both attributes which has centered text via flexbox

            ...

            ANSWER

            Answered 2021-Jun-11 at 13:28

            With JavaScript you can insert a space (' ') when you detect the contenteditable is empty. This pushes the caret position to the center.

            Source https://stackoverflow.com/questions/67937619

            QUESTION

            Unity Rigidbody
            Asked 2021-Jun-14 at 07:49

            I am new to unity and trying to make the player jump on start. I have the following code

            ...

            ANSWER

            Answered 2021-Jun-14 at 06:34

            You need an instance of class Rigidbody

            Source https://stackoverflow.com/questions/67965706

            QUESTION

            6502 assembly: carry result in 16bit subtraction
            Asked 2021-Jun-14 at 07:44

            I have recovered an old 6502 emulator I did years ago to implement some new features. During testing I discovered something wrong, surely due to an error in my implementation.
            I have to loop through a 16 bit subtraction until the result is negative: quite simple, no? Here is an example:

            ...

            ANSWER

            Answered 2021-May-25 at 12:22

            loop through a 16 bit subtraction until the result is negative

            "Branch" to Label if result is >0,

            Do you see that these descriptions contradict each other?
            The 1st one continues on 0, the 2nd one stops on 0.
            Only you can decide which one is correct!

            From a comment:

            This code is part of a Bin to Ascii conversion, made by power of ten subtraction. The bin value could be >$8000, so it is 'negative' but this does not matter. In the first iteration I sub 10000 each cycle until the result is 'below 0', then I restore the previous value and continue with the remainder. The problem is how to detect the 'below 0' condition as said in the post

            Do ... Loop While GE 0

            Next example subtracts 10000 ($2710) from the unsigned word stored at zero page address $90. The low byte is at $90, the high byte is at $91 (little endian).

            Source https://stackoverflow.com/questions/67663261

            QUESTION

            Why my POST login request in app.js always return 404?
            Asked 2021-Jun-14 at 03:52

            I try to finish a login function on my web application; however, when I enter the correct password and username already registered in my database, it always returns 404.

            I want to use sessions to identify each unique user. And what I also want to know how to jump to a new webpage after login in successfully.

            Here is my code in app.js:

            ...

            ANSWER

            Answered 2021-Jun-14 at 03:52

            Edit page2.html in both app.js post and html form action to page2

            Source https://stackoverflow.com/questions/67964072

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

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            You can download it from GitHub.

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