words | humble yet ambitious attempt to build a WYSIWYG editor | Editor library

 by   yabwe JavaScript Version: Current License: Non-SPDX

kandi X-RAY | words Summary

kandi X-RAY | words Summary

words is a JavaScript library typically used in Editor applications. words has no bugs, it has no vulnerabilities and it has low support. However words has a Non-SPDX License. You can download it from GitHub.

A humble yet ambitious attempt to build a WYSIWYG editor, backed by JSON, without relying on document.execCommand.
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            kandi-support Support

              words has a low active ecosystem.
              It has 18 star(s) with 3 fork(s). There are 11 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 4 open issues and 1 have been closed. On average issues are closed in 9 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of words is current.

            kandi-Quality Quality

              words has 0 bugs and 0 code smells.

            kandi-Security Security

              words has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              words code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              words has a Non-SPDX License.
              Non-SPDX licenses can be open source with a non SPDX compliant license, or non open source licenses, and you need to review them closely before use.

            kandi-Reuse Reuse

              words releases are not available. You will need to build from source code and install.
              Installation instructions, examples and code snippets are available.

            Top functions reviewed by kandi - BETA

            kandi has reviewed words and discovered the below as its top functions. This is intended to give you an instant insight into words implemented functionality, and help decide if they suit your requirements.
            • init data structure
            • Append a stroke to a stroke
            • design tree
            • Change the root node
            • design tree
            • Constructor for a canvas context
            • A helper method for calculating the arc of two points .
            • Process a CSS style string
            • Computes the computed style for a given element .
            • Nodes to selected nodes
            Get all kandi verified functions for this library.

            words Key Features

            No Key Features are available at this moment for words.

            words Examples and Code Snippets

            No Code Snippets are available at this moment for words.

            Community Discussions

            QUESTION

            Do I have to use the Composition API in Vue 3, or can I still do things the "Vue 2" way?
            Asked 2022-Mar-07 at 03:01

            Is it possible to install Vue 3, but still do things the "Vue 2" way? In other words, I see that Vue 3 has the new Composition API, but is that optional or the required way of doing things in Vue 3?

            For some reason, I was thinking that Vue 3 still allowed you to do things the Vue-2 way, using the Options API instead. Is that not the case? Thanks.

            ...

            ANSWER

            Answered 2022-Mar-07 at 03:01

            Vue 3 does not require using the Composition API. The Options API is still available and will not be removed, as explained by two Vue core team members:

            Thorsten Lünborg in Vue 3: Data down, Events up (19-MAY-2020):

            IMPORTANT: The composition API is additive, it’s a new feature, but it doesn’t and will not replace the good ole “Options API” you know and love from Vue 1 and 2. Just consider this new API as another tool in your toolbox that may come in handy in certain situations that feel a little clumsy to solve with the Options API.

            Ben Hong in Enjoy the Vue #48: "New in Vue 3: The Composition API" (19-JAN-2021):

            [00:01:03] T: Yeah. Well, the first thing I remember hearing was that it was replacing the options API.

            [00:01:08] BH: Big disclaimer. That isn’t happening. Big disclaimer.

            ...

            [00:09:10] BH: [...] this is not something you need to go and rewrite your app in. [...] the composition API is not like, drop the options do composition. It's an additive thing that when you have a problem that it can solve, it's really great for that.

            An early RFC for the Composition API had only considered deprecating the Options API:

            A previous draft of this RFC indicated that there is the possibility of deprecating a number of 2.x options in a future major release, which has been redacted based on user feedback.

            The Vue docs also confirm this:

            Will Options API be deprecated?

            No, we do not have any plan to do so. Options API is an integral part of Vue and the reason many developers love it. We also realize that many of the benefits of Composition API only manifest in larger-scale projects, and Options API remains a solid choice for many low-to-medium-complexity scenarios.

            Source https://stackoverflow.com/questions/68611657

            QUESTION

            Is there an identity index value in JavaScript?
            Asked 2022-Feb-13 at 18:48

            In JavaScript, values of objects and arrays can be indexed like the following: objOrArray[index]. Is there an identity "index" value?

            In other words:

            Is there a value of x that makes the following always true?

            ...

            ANSWER

            Answered 2021-Oct-05 at 01:31

            The indexing operation doesn't have an identity element. The domain and range of indexing is not necessarily the same -- the domain is arrays and objects, but the range is any type of object, since array elements and object properties can hold any type. If you have an array of integers, the domain is Array, while the range is Integer, so it's not possible for there to be an identity. a[x] will always be an integer, which can never be equal to the array itself.

            And even if you have an array of arrays, there's no reason to expect any of the elements to be a reference to the array itself. It's possible to create self-referential arrays like this, but most are not. And even if it is, the self-reference could be in any index, so there's no unique identity value.

            Source https://stackoverflow.com/questions/69443928

            QUESTION

            In Haskell, Can Kinds Be Anything Other Than a Sequence of Stars?
            Asked 2022-Feb-13 at 00:42

            Please forgive me if this question is dumb.

            While reading about Haskell kinds, I notice a theme:

            ...

            ANSWER

            Answered 2022-Feb-13 at 00:42

            The most basic form of the kind language contains only * (or Type in more modern Haskell; I suspect we'll eventually move away from *) and ->.

            But there are more things you can build with that language than you can express by just "counting the number of *s". It's not just the number of * or -> that matter, but how they are nested. For example * -> * -> * is the kind of things that take two type arguments to produce a type, but (* -> *) -> * is the kind of things that take a single argumemt to produce a type where that argument itself must be a thing that takes a type argument to produce a type. data ThreeStars a b = Cons a b makes a type constructor with kind * -> * -> *, while data AlsoThreeStars f = AlsoCons (f Integer) makes a type constructor with kind (* -> *) -> *.

            There are several language extensions that add more features to the kind language.

            PolyKinds adds kind variables that work exactly the same way type variables work. Now we can have kinds like forall k. (* -> k) -> k.

            ConstraintKinds makes constraints (the stuff to the left of the => in type signatures, like Eq a) become ordinary type-level entities in a new kind: Constraint. Rather than the stuff left of the => being special purpose syntax fairly disconnected from the rest of the language, now what is acceptable there is anything with kind Constraint. Classes like Eq become type constructors with kind * -> Constraint; you apply it to a type like Eq Bool to produce a Constraint. The advantage is now we can use all of the language features for manipulating type-level entities to manipulate constraints (including PolyKinds!).

            DataKinds adds the ability to create new user-defined kinds containing new type-level things, in exactly the same way that in vanilla Haskell we can create new user-defined types containing new term-level things. (Exactly the same way; the way DataKinds actually works is that it lets you use a data declaration as normal and then you can use the resulting type constructor at either the type or the kind level)

            There are also kinds used for unboxed/unlifted types, which must not be ever mixed with "normal" Haskell types because they have a different memory layout; they can't contain thunks to implement lazy evaluation, so the runtime has to know never to try to "enter" them as a code pointer, or look for additional header bits, etc. They need to be kept separate at the kind level so that ordinary type variables of kind * can't be instantiated with these unlifted/unboxed types (which would allow you to pass these types that need special handling to generic code that doesn't know to provide the special handling). I'm vaguely aware of this stuff but have never actually had to use it, so I won't add any more so I don't get anything wrong. (Anyone who knows what they're talking about enough to write a brief summary paragraph here, please feel free to edit the answer)

            There are probably some others I'm forgetting. But certainly the kind language is richer than the OP is imagining just with the basic Haskell features, and there is much more to it once you turn on a few (quite widely used) extensions.

            Source https://stackoverflow.com/questions/71090577

            QUESTION

            Is enum { a } e = 1; valid?
            Asked 2022-Feb-09 at 18:46

            A simple question: is enum { a } e = 1; valid?

            In other words: does assigning a value, which isn't present in the set of values of enumeration constants, lead to well-defined behavior?

            Demo:

            ...

            ANSWER

            Answered 2022-Feb-05 at 14:09

            From the C18 standard in 6.7.2.2:

            Each enumerated type shall be compatible with char, a signed integer type, or an unsigned integer type. The choice of type is implementation-defined, but shall be capable of representing the values of all the members of the enumeration.

            So yes enum { a } e = 1; is valid. e is a 'integer' type so it can take the value 1. The fact that 1 is not present as an enumeration value is no issue. The enumeration members only give handy identifiers for some of possible values.

            Source https://stackoverflow.com/questions/70988698

            QUESTION

            What is the proper evaluation order when assigning a value in a map?
            Asked 2022-Feb-02 at 09:25

            I know that compiler is usually the last thing to blame for bugs in a code, but I do not see any other explanation for the following behaviour of the following C++ code (distilled down from an actual project):

            ...

            ANSWER

            Answered 2022-Feb-01 at 15:49

            The evaluation order of A = B was not specified before c++17, after c++17 B is guaranteed to be evaluated before A, see https://en.cppreference.com/w/cpp/language/eval_order rule 20.

            The behaviour of valMap[val] = valMap.size(); is therefore unspecified in c++14, you should use:

            Source https://stackoverflow.com/questions/70943170

            QUESTION

            Replace wildcards in a binary string avoiding three identical consecutive letters
            Asked 2022-Jan-14 at 10:48

            Given a string S of length N, return a string that is the result of replacing each '?' in the string S with an 'a' or a 'b' character and does not contain three identical consecutive letters (in other words, neither 'aaa' not 'bbb' may occur in the processed string).

            Examples:

            ...

            ANSWER

            Answered 2021-Sep-24 at 13:55

            I quickly tried out the solution I proposed in the comments:

            Source https://stackoverflow.com/questions/69315783

            QUESTION

            Unexpected result comparing strings with `==`
            Asked 2021-Dec-26 at 22:14

            I have two vectors:

            ...

            ANSWER

            Answered 2021-Dec-26 at 02:47

            The problem you've encountered here is due to recycling (not the eco-friendly kind). When applying an operation to two vectors that requires them to be the same length, R often automatically recycles, or repeats, the shorter one, until it is long enough to match the longer one. Your unexpected results are due to the fact that R recycles the vector c("p", "o") to be length 4 (length of the larger vector) and essentially converts it to c("p", "o", "p", "o"). If we compare c("p", "o", "p", "o") and c("p", "o", "l", "o") we can see we get the unexpected results of above:

            Source https://stackoverflow.com/questions/70483804

            QUESTION

            Haskell: Can I read integers directly into an array?
            Asked 2021-Dec-05 at 11:40

            In this programming problem, the input is an n×m integer matrix. Typically, n≈ 105 and m ≈ 10. The official solution (1606D, Tutorial) is quite imperative: it involves some matrix manipulation, precomputation and aggregation. For fun, I took it as an STUArray implementation exercise.

            Issue

            I have managed to implement it using STUArray, but still the program takes way more memory than permitted (256MB). Even when run locally, the maximum resident set size is >400 MB. On profiling, reading from stdin seems to be dominating the memory footprint:

            Functions readv and readv.readInt, responsible for parsing integers and saving them into a 2D list, are taking around 50-70 MB, as opposed to around 16 MB = (106 integers) × (8 bytes per integer + 8 bytes per link).

            Is there a hope I can get the total memory below 256 MB? I'm already using Text package for input. Maybe I should avoid lists altogether and directly read integers from stdin to the array. How can we do that? Or, is the issue elsewhere?

            Code ...

            ANSWER

            Answered 2021-Dec-05 at 11:40

            Contrary to common belief Haskell is quite friendly with respect to problems like that. The real issue is that the array library that comes with GHC is total garbage. Another big problem is that everyone is taught in Haskell to use lists where arrays should be used instead, which is usually one of the major sources of slow code and memory bloated programs. So, it is not surprising that GC takes a long time, it is because there is way too much stuff being allocation. Here is a run on the supplied input for the solution provided below:

            Source https://stackoverflow.com/questions/70143678

            QUESTION

            Visual studio 2022 changed my system font
            Asked 2021-Nov-08 at 20:14

            Recently I installed vs 2022 to test .net 6 and after installing it, I found the default font in vs 2022 is like a bolder font(seems to be Cascadia), it's not fits me well so I changed it in vs 2022 pre->tools->options->fonts and colors to change it to Consolas which is the same in vs 2019. Then vs 2022 seemed ok, but I found in stackover flow, text font in textarea also changed to this kind of "bolder font",

            I've ruled out the issue from chrome, as it's the same in Edge. But input box doesn't be influenced.

            Details in screenshot here, the font of the words in textarea and those formated in code has changed.

            Can anyone do me a favor? Thanks in advance :)

            ...

            ANSWER

            Answered 2021-Sep-17 at 02:13

            I'm not sure if it's the best solution but it's the only method with luck, just uninstall the font in win 10 system.

            Go to settings-> choose font setting-> find and click into Cascadia and Cascadia mono-> click uninstall , then it returned to normal for me.

            When I uninstalled Cascadia mono it appeared a pop-up and told me it's in use, so I closed my chrome and continued the uninstall action.

            Done here.

            Source https://stackoverflow.com/questions/69216858

            QUESTION

            Raku: Trouble Accessing Value of a Multidimensional Hash
            Asked 2021-Oct-24 at 22:54

            I am having issues accessing the value of a 2-dimensional hash. From what I can tell online, it should be something like: %myHash{"key1"}{"key2"} #Returns value

            However, I am getting the error: "Type Array does not support associative indexing."

            Here's a Minimal Reproducible Example.

            ...

            ANSWER

            Answered 2021-Oct-24 at 09:48

            After adding the second elements with push to the same part of the Hash, the elment is now an array. Best you can see this by print the Hash before the crash:

            Source https://stackoverflow.com/questions/69695107

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

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            Install words

            1) Pull down the repo. 2) Pull down the dependencies. 3) Start the server. 4) Load the page. 5) Dance, everybody dance.

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