Listn | App can be | Music Player library
kandi X-RAY | Listn Summary
kandi X-RAY | Listn Summary
App can be downloaded from here. Simple music player app built on top of the Soundcloud API. The app is built with Uncle Bob's Clean Architecture, loosely inspired by this project. The audio player is inspired by this project. App requires a Soundcloud API key to use properly. Design by Anton Andersson Andrejić.
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QUESTION
I've had trouble printing the values of the key "uuid". The "uuid" key shows up multiple times throughout the file whilst other keys that are only present in the file once have no trouble being printed. So I'm wondering is it possible to do what I want it to do? The error I'm getting is a KeyError: 'uuid' for your information.
...ANSWER
Answered 2021-Jun-11 at 00:31Given that you haven't given us the full json but rather a messed up one
QUESTION
I'm doing an exercise in which given a number I should find all the combinations of digits of the number, given an M length.
For example if N = 1234, M = 3, Combinations = [[1,2,3], [1,2,4], [1,3,4], [2,3,4]].
I don't understand how to obtain the combinations, maybe using a findall (in this case i don't understand how)?
This is the code that I have wrote to find the number (and combinations, but it print only [1,1,1])
...ANSWER
Answered 2021-May-25 at 18:47To generate combinations, you can use the following code:
QUESTION
I need to find all numbers in range (45 000 000, 50 000 000 +1), which have five odd dividers only. The number of even dividers has no limit. Here my code is too slow
...ANSWER
Answered 2021-Mar-17 at 18:32Take an odd number n
. If this odd number n
has an odd divisor m
, then n/m
is also an odd number. But that means that odd divisors come in pairs, m
and n/m
. The only way the number n
can have 5 odd divisors is if some pair actually has the same numbers, i.e. m = n/m
. But that means that n = m*m
, i.e. n
must be a square of an odd number. So, you don't need to check all odd numbers in the range, just check odd numbers which are squares of an odd number.
Now consider an even number n
. Let's divide this number by 2 until we get an odd number m
(for example, from n=40
we get 40 -> 20 -> 10 -> 5
, so m = 5
). Any odd divisor of m
will be also an odd divisor of n
and vice versa. So, n
and m
have the same number of odd divisors. So, as we see above, number m
must be a square of an odd number. It means, that n
must be a square of an odd number multiplied by some power of two. It means that you don't need to check every even number in your range, check only those, which are squares of an odd number multiplied by some power of 2.
UPDATE
Below are sample implementations:
QUESTION
I just integrated Razorpay payment gateway in my django project and i am new to this payment gateway. When i am initiate the payment razorpay show me an payment interface(like this image) and there is options for writing customer contact and email. Here is my question how can i get this two fields back contact and email when customer click on proceed button.
Here is my code: Template file
...ANSWER
Answered 2021-Feb-09 at 17:21You should be getting an id
in the response json. As per the docs here RazorpayAPI Reference and you can then get the details of the order with that ID. Then you create a payment with that order ID and then once payment is made you get a payment ID. There are methods to Fetch Payments with a Payment ID
which should have these details if the user has filled it.
For your Reference, these are python method guidelines for Razorpay: Payment Reference Python Razorpay
Here's a pseudo-code for the changes:
QUESTION
I created following express API
...ANSWER
Answered 2021-Jan-25 at 12:43You are trying to serve several endpoints in the same Cloud Functions. I saw some hack on Stack overflow where folks bend the framework to achieve this. It's not my recommendation.
Cloud Run is a very similar platform. The same underlying infrastructure, and feature very close (I wrote an article on this). But you serve a containerize webserver, more suitable for your use case.
You can easily have a try on it.
- Uncomment your "starting app express" part
- Test locally if it works.
Then run this command
QUESTION
I am trying to import a list from a file in python , and i don't know the name of the list or the file .
I am asking them in the code , and when I get them , i am trying to import the list ,
...ANSWER
Answered 2020-Oct-27 at 19:06Try import_module()
with getattr()
instead:
QUESTION
protocol UDPListener {
func handleResponse(_ client: UDPConnection, data: Data)
}
class UDPConnection{
var connection: NWConnection?
var listner: NWListener?
var delegate: UDPListener?
let parameters = NWParameters.udp
// for connect with device
func connect(withHost: NWEndpoint.Host, port: NWEndpoint.Port) {
parameters.allowLocalEndpointReuse = true
self.connection = NWConnection(host: withHost, port: port, using: parameters)
self.connection?.stateUpdateHandler = { (newState) in
switch (newState) {
case .ready:
print("connection ready")
case .setup:
print("connectionsetup")
case .cancelled:
print("connectioncancelled")
case .preparing:
print("connection Preparing")
default:
print("connection waiting or failed")
}
}
self.connection?.start(queue: .global())
}
// for sending UDP string
func sendUDP(_ content: String) {
let contentToSendUDP = content.data(using: String.Encoding.utf8)
self.connection?.send(content: contentToSendUDP, completion: NWConnection.SendCompletion.contentProcessed(({ (NWError) in
if (NWError == nil) {
print("Data was sent to UDP")
} else {
print("ERROR SEND! Error when data (Type: Data) sending. NWError: \n \(NWError!)")
}
})))
}
//for sending UDP data
func sendUDP(_ content: Data) {
self.connection?.send(content: content, completion: NWConnection.SendCompletion.contentProcessed(({ (NWError) in
if (NWError == nil) {
print("Data was sent to UDP")
} else {
print("ERROR Send! Error when data (Type: Data) sending. NWError: \n \(NWError!)")
}
})))
}
//////////////// UDP LISTNER /////////////////////
func listenUDP(port: NWEndpoint.Port) {
do {
parameters.allowLocalEndpointReuse = true
self.listner = try NWListener(using: parameters, on: port)
self.listner?.stateUpdateHandler = {(newState) in
switch newState {
case .ready:
print("Listner ready")
case .failed:
print("Listner failed")
case .cancelled:
print("Listner cancelled")
default:
break
}
}
self.listner?.newConnectionHandler = {(newConnection) in
newConnection.stateUpdateHandler = {newState in
switch newState {
case .ready:
print("new connection establish")
self.receive(on: newConnection)
case .failed:
print("new connection failed")
case .cancelled:
print("new connection cancelled")
default:
break
}
}
newConnection.start(queue: DispatchQueue(label: "new client"))
}
} catch {
print("unable to create listener")
}
self.listner?.start(queue: .global())
}
func receive(on connection: NWConnection) {
connection.receiveMessage { (data, context, isComplete, error) in
if !isComplete {
print("Not Complete")
}
if let error = error {
print("Error in REceive: - ",error)
return
}
if let data = data, !data.isEmpty {
// let backToString = String(decoding: data, as: UTF8.self)
// print("Received Data: ",backToString)
guard self.delegate != nil else {
print("Error Receive: UDPClient response handler is nil")
return
}
print("Data receive in UDPConenction;")
self.delegate?.handleResponse(self, data: data)
}
}
}
}
...ANSWER
Answered 2020-Oct-14 at 20:29In your function receive
you are using the NWConnection.receiveMessage
if you check the documentation here:
https://developer.apple.com/documentation/network/nwconnection/3020638-receivemessage
You'll see that it schedules a single receive completion handler. That means that you'll have to do something to trigger it again. What I normally do is have a function like:
QUESTION
So I have a set of lists with no set quantity on how many lists I have.
...ANSWER
Answered 2020-Aug-18 at 19:16You can use Linq
methods here as shown in below code.
QUESTION
This is my express code:
...ANSWER
Answered 2020-Jun-16 at 00:03The signup route is missing a forward slash.
This should resolve the issue:
QUESTION
I want to get a list of protobuf message objects from the Spring boot app.
I did manage to get a single protobuf message object from the app but getting a list of them throws exception.
ANSWER
Answered 2020-Jan-28 at 21:53Workaround
I couldn't find a solution to the problem so came up with a workaround.
Instead of returning generated protobuf message objects I returned wrappers for those objects. Using Lombok annotation it could be done:
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