git-number | Use numbers for dealing with files in git | Version Control System library
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Use numbers for dealing with files in git
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QUESTION
I've made a simple calculator, but it doesn't work properly. So i've a graphical part with a screen, that is where i append number. Then The logical part work basically with to variable, the x that is the previous number before a mathematical sign, and the y that is the number after the sign; that is also a checker that check what is the last sign that the user have chose, and based on that, it sum or divide etc. the x and y in the result function. In the result function is also parsed the x and y, and after that it is calculated. Here comes the problem, when i try to do 1 +1 = 12 and 11 + 11 = 122, in the y there are no problem, but in the x is added "1" more than requested. (i've done an if that permit to concat string to write multi-digit-number like 11).
Thanks to all in advice :)
(for now i've applied that process only for the number 1 uguale is the egual function)
...ANSWER
Answered 2021-May-28 at 10:20You missed the second if condition. It is an else if, not an if.
In fact, you add a one to the x var with the first if if (x == "" && y == "")
.
Then, the x value is "1", but you enter in the else if (x !== "" && y == "" && checker == undefined)
condition.
QUESTION
Can someone please help me understand the logic of following Dynamic Programmming question Found this one at geeksforgeeks.com. I am unable to understand even after going through the answer provided.
Question:
Count of N-digit numbers with absolute difference of adjacent digits not exceeding K | Set 2
Given two integers N and K, the task is to find the count of N-digit numbers such that the absolute difference of adjacent digits in the number is not greater than K.
Examples:
Input: N = 2, K = 1
Output: 26
Explanation: The numbers are 10, 11, 12, 21, 22, 23, 32, 33, 34, 43, 44, 45, 54, 55, 56, 65, 66, 67, 76, 77, 78, 87, 88, 89, 98, 99
Input: N = 3, K = 2
Output: 188
Python3 solution:
...ANSWER
Answered 2021-Apr-13 at 15:31N=2
so we are dealing with strictly 2 digit numbers
K=1
so each digit in the current number shall be no more than 1 digit greater or less than its neighbors
While the answer is 26
(the count of such numbers), lets take a look at why the answer includes 10
, 11
, and 12
but not 13
10
is good as the absolute value of 1
- 0
(the digits of 10
) is less than or equal to 1
(the value of K
)
13
is bad as the absolute value of 1
- 3
is 2
and 2
is greater than K
Note that as N
increases, the number of pairwise digit comparisons required will also increase.
I'll skip parsing someone else's code with meaningless variable names. Here is how I might attempt to solve this:
QUESTION
I am trying to add in PHP the string "0" to a one-digit-number, which is a string as well e.g."1" if it is less then ten in order to always have two digits.
I then want to get the string "01" for example in a new variable.
Defining all three variables with either strval() or (string) just returns the result variable as an int again nevertheless.
Any ideas?
That is the code I tried:
ANSWER
Answered 2021-Feb-05 at 21:17Use sprintf().
QUESTION
I have the problem that I can't get the proper RegExp
together.
My Goal is to allow up to 3 digits before the comma, and ONLY IF there is a decimal, then 1 digit after the comma. Which RegExp
or Regexes do I have to use for this behavior?
Wanted allowed outcomes: 000.0, 00.0, 0.0, 000, 00, 0
thats the current code, but the problem is that here also 4 digits can be placed without a decimal:
...ANSWER
Answered 2020-Nov-22 at 11:54RegExp(r'^\d{0,3}(\.\d{1})?$')
QUESTION
The formula in question is =IF (ISBLANK(H2),"", ARRAY_CONSTRAIN(ARRAYFORMULA(IF( (MOD(SUM(INT(MID(REPT("0",20-LEN(H2))&H2,ROW($1:$31),1)*(MOD(ROW($1:$31),2)+1)/10)+MOD(MID(REPT("0",20-LEN(H2))&H2,ROW($1:$31),1)*(MOD(ROW($1:$31),2)+1),10)),10)=0), "✔", "❌")), 1, 1))
In English it checks if H2 contains a valid credit card (passing Luhn's algorithm, discussion / sample data here). The expected output is valid = ✔; invalid = ❌; if blank then nothing.
I'm trying to adjust this to appear in every row, but can't seem to nail it down. (Using the trick like for a formula =LEFT(H2,4)&" "&MID(H2,5,6)
, if it's =arrayformula(LEFT(H2:H100,4)&" "&MID(H2:H100,5,6))
it appears in every row without having to manually refill it when a new row is inserted).
ANSWER
Answered 2020-Nov-05 at 01:07Try this:
QUESTION
I would like to read 3-digit-numbers with spaces inbetween from a file with the fgetc()-command and put them into an array, which is not currently working, as the resulting array has completely different objects in it. What am I doing wrong? (I used a file with "107 313 052 614" in it, resulting in the output "5435 5641 5380 5942")
My Code:
...ANSWER
Answered 2019-Nov-25 at 16:15The characters that are used to store digits in a "readable" file are not "numbers". The most popular encoding is ascii character encoding, ex. the 1
digit is represented with the number 49 in decimal.
Because the 0, 1, 2 ... 9 digits in ascii encoding are encoded in increasing order, you can just substract 48 (ie. '0'
character) to convert a digit character to it's machine format Just - '0'
.
Change you loop into:
QUESTION
Background
I have the following df which is a modification from blocking seven digit numbers in string pandas
...ANSWER
Answered 2019-Aug-25 at 22:04One possibility is to include the set of all characters that you would like to remove in a character class.
QUESTION
EDIT: I should have said, that as good or better than outputting all four-digit numbers would be a count function that counts the number of four-digit uninterrupted numbers.
And, whether a number output or count, I need to pull the formula downwards across a couple thousand rows. Thank you to everyone who replied so far, appreciate your help!
This formula finds the first four-digit number in a string--but I need to find either the second instance of a four-digit number, or the last, or generate all. Just not the first one. Useful formula in need of a tweak, thank you for your consideration: =MID(D2,FIND("----",SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(D2,"0","-"),"1","-"),"2","-"),"3","-"),"4","-"),"5","-"),"6","-"),"7","-"),"8","-"),"9","-")),4)
I already tried a formula adjusted from the top answer on this thread: Excel: How to extract only the 6 digit number present in a cell string?
For this text in a cell: "Test 1 military time 1982 2008 2009 203401"
This formula: =MID(D2,FIND("----",SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(D2,"0","-"),"1","-"),"2","-"),"3","-"),"4","-"),"5","-"),"6","-"),"7","-"),"8","-"),"9","-")),4)
Generates this: "1982"
I would like it to output 2008, or 1982,2008,2009,2034, or just one of the results after the first one, 1982.
...ANSWER
Answered 2019-Jul-13 at 04:04In D3 enter:
QUESTION
I want something like SELECT splitDigits(123456789) as digits
to return:
ANSWER
Answered 2019-May-28 at 08:31SELECT
SUBSTR(3987654321, idx, 1) AS SplitDigits,
3 * (SUBSTR(3987654321, idx, 1)) AS ConstTimesSplitDigits
-- SUM(SUBSTR(2050364496, idx, 1) * (SUBSTR(5432765432, idx, 1))) AS Result
FROM (SELECT @cnt := 0) A
-- cross join any table has rows greater than or equal to your liking
CROSS JOIN (SELECT (@cnt := @cnt + 1) idx FROM INFORMATION_SCHEMA.TABLES LIMIT 10) B
;
QUESTION
Suppose I have a text-file named barcodes.txt that looks like this:
...ANSWER
Answered 2019-Feb-10 at 23:42For me the solution was to first generate one file for each line:
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Install git-number
Add folder where 'git-number', 'git-list', 'git-id' are located to your $PATH variable and restart git console.
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