.files | Collection of various .files and or configuration files | FTP library
kandi X-RAY | .files Summary
kandi X-RAY | .files Summary
A collection of my files. 'Real Men don't make backups. They upload it via ftp and let the world mirror it.' Linus Torvalds.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of .files
.files Key Features
.files Examples and Code Snippets
def create_api_files(output_files,
packages,
packages_to_ignore,
root_init_template,
output_dir,
output_package,
api_name,
def list_source_files_against_dump(dump,
path_regex_allowlist=None,
node_name_regex_allowlist=None):
"""Generate a list of source files with information regarding ops and tensors
def _load_metadata_files(self):
"""Load and parse metadata files in the dump root.
Check that all metadata files have a common tfdbg_run_id, and raise
a ValueError if their tfdbg_run_ids differ.
Returns:
A list of metadata fil
Community Discussions
Trending Discussions on .files
QUESTION
I'm currently learning HTML, CSS, and JavaScipt. I'm trying to make a basic project, but I'm having problems with adding a new image on the new card. When I click on the 'add item' button, I create a new card with image. However, when I add another card for the second time, my image from the first card that I created will disappear. Can someone help me on how to fix this solution. Thank you.
...ANSWER
Answered 2021-Jun-15 at 19:05Rather than using two different function, one for adding card image and one for card content, try combining both of them.. here use the code for your reference.
QUESTION
Yet another question about the style and the good practices. The code, that I will show, works and do the functionality. But I'd like to know is it ok as solution or may be it's just too ugly?
As the question is a little bit obscure, I will give some points at the end.
So, the use case.
I have a site with the items. There is a functionality to add the item by user. Now I'd like a functionality to add several items via a csv-file.
How should it works?
- User go to special upload page.
- User choose a csv-file, click upload.
- Then he is redirected to the page that show the content of csv-file (as a table).
- If it's ok for user, he clicks "yes" (button with "confirm_items_upload" value) and the items from file are added to database (if they are ok).
I saw already examples for bulk upload for django, and they seem pretty clear. But I don't find an example with an intermediary "verify-confirm" page. So how I did it :
- in views.py : view for upload csv-file page
ANSWER
Answered 2021-May-28 at 09:27a) Even if obviously it could be better, is this solution is acceptable or not at all ?
I think it has some problems you want to address, but the general idea of using the filesystem and storing just filenames can be acceptable, depending on how many users you need to serve and what guarantees regarding data consistency and concurrent accesses you want to make.
I would consider the uploaded file temporary data that may be lost on system failure. If you want to provide any guarantees of not losing the data, you want to store it in a database instead of on the filesystem.
b) I pass 'uploaded_file' from one view to another using "request.session" is it a good practice? Is there another way to do it without using GET variables?
There are up- and downsides to using request.session.
- attackers can not change the filename and thus retrieve data of other users. This is also the reason why you should not use a GET parameter here: If you used one, attackers could simpy change that parameter and get access to files of other users.
- users can upload a file, go and do other stuff, and later come back to actually import the file, however:
- if users end their session, you lose the filename. Also, users can not upload the file on one device, change to another device, and then go on with the import, since the other device will have a different session.
The last point correlates with the leftover files problem: If you lose your information about which files are still needed, it makes cleaning up harder (although, in theory, you can retrieve which files are still needed from the session store).
If it is a problem that sessions might end or change because users clear their cookies or change devices, you could consider adding the filename to the UserProfile
in the database. This way, it is not bound to sessions.
c) At first my wish was to avoid to save the csv-file. But I could not figure out how to do it? Reading all the file to request.session seems not a good idea for me. Is there some possibility to upload the file into memory in Django?
You want to store state. The go-to ways of storing state are the database or a session store. You could load the whole CSVFile and put it into the database as text. Whether this is acceptable depends on your databases ability to handle large, unstructured data. Traditional databases were not originally built for that, however, most of them can handle small binary files pretty well nowadays. A database could give you advantages like ACID guarantees where concurrent writes to the same file on the file system will likely break the file. See this discussion on the dba stackexchange
Your database likely has documentation on the topic, e.g. there is this page about binary data in postgres.
d) If I have to use the tmp-file. How should I handle the situation if user abandon upload at the middle (for example, he sees the confirmation page, but does not click "yes" and decide to re-write his file). How to remove the tmp-file?
Some ideas:
- Limit the count of uploaded files per user to one by design. Currently, your filename is based on a timestamp. This breaks if two users simultaneously decide to upload a file: They will both get the same timestamp, and the file on disk may be corrupted. If you instead use the user's primary key, this guarantees that you have at most one file per user. If they later upload another file, their old file will be overwritten. If your user count is small enough that you can store one leftover file per user, you don't need additional cleaning. However, if the same user simultaneusly uploads two files, this still breaks.
- Use a unique identifier, like a UUID, and delete the old stored file whenever the user uploads a new file. This requires you to still have the old filename, so session storage can not be used with this. You will still always have the last file of the user in the filesystem.
- Use a unique identifier for the filename and set some arbitrary maximum storage duration. Set up a cronjob or similar that regularly goes through the files and deletes all files that have been stored longer than your specified maximum duration. If a user uploads a file, but does not do the actual import soon enough, their data is deleted, and they would have to do the upload again. Here, your code has to handle the case that the file with the stored filename does not exist anymore (and may even be deleted while you are reading the file).
You probably want to limit your server to one file stored per user so that attackers can not fill your filesystem.
e) Small additional question : what kind of checks there are in Django about uploaded file? For example, how could I check that the file is at least a text-file? Should I do it?
You definitely want to set up some maximum file size for the file, as described e.g. here. You could limit the allowed file extensions, but that would only be a usability thing. Attackers could also give you garbage data with any accepted extension.
Keep in mind: If you only store the csv as text data that you load and parse everytime a certain view is accessed, this can be an easy way for attackers to exhaust your servers, giving them an easy DoS attack.
Overall, it depends on what guarantees you want to make, how many users you have and how trustworthy they are. If users might be malicious, you want to keep all possible kinds of data extraction and resource exhaustion attacks in mind. The filesystem will not scale out (at least not as easily as a database).
I know of a similar setup in a project where only a handful of priviliged users are allowed to upload stuff, and we can tolerate deletion of all temporary files on failure. Users will simply have to reupload their files. This works fine.
QUESTION
I have a table with posts that can have multiple categories, and a table with categories that can have multiple posts. models.py:
...ANSWER
Answered 2021-Jun-15 at 11:16This might help you:
QUESTION
I need help uploading a file directly from an HTML form to an API. I've seen this being done for remote URLs, but I don't know how to do this for local files? I tried writing this, but its not working:
...ANSWER
Answered 2021-Jun-15 at 09:58The request.files['file']
is an instance of a FileStorage class. refer to api, you cannot use with open(uploadmedia, 'rb') as file:
.
try using stream attribute :
QUESTION
Starting with the sample from https://docs.gradle.org/current/samples/sample_jvm_multi_project_with_code_coverage.html (i.e., the code here https://github.com/gradle/gradle/tree/master/subprojects/docs/src/samples/java/jvm-multi-project-with-code-coverage ) and simply adding Spring Boot by changing application/build.gradle
to
ANSWER
Answered 2021-Jun-01 at 20:54Just do that and you will be fine (all external classes will be excluded):
QUESTION
I followed the instructions at Structured Streaming + Kafka and built a program that receives data streams sent from kafka as input, when I receive the data stream I want to pass it to SparkSession variable to do some query work with Spark SQL, so I extend the ForeachWriter class again as follows:
...ANSWER
Answered 2021-Jun-15 at 04:42do some query work with Spark SQL
You wouldn't use a ForEachWriter for that
QUESTION
I'm new in React and state hooks.I'm trying to make a website about creating booklist and save it to local storage. Also uploading image to cloudinary. My problem is ; when i trying to save cloudinary image url to the localstorage, it saves previous url. I think i have a problem about useState hooks but i couldnt figure it. Below is my code.
LocalStorage.js
...ANSWER
Answered 2021-Jun-15 at 00:57
setUploadUrl(result.url);
id = new Date().getTime().toString();
const newBook = {
id: id,
bookName: bookName,
writerName: writerName,
pageNumber: pageNumber,
uploadUrl: uploadUrl
};
QUESTION
I want to get the creation date of 20000 files and store it in an array.
Total time to complete is 35 minutes, quite a long time. (Image Processing Time)
Is there a way to create the array with faster processing time?
Is there any problem with the current logic to get an array of file creation dates like below?
① Array declaration: var arr = [];
② I used the code below to get the file creation date:
ANSWER
Answered 2021-Jun-10 at 03:45You're using fs.statSync
which is a synchronous function, meaning that every time you call it, all code execution stops until that function finishes. Look into using fs.stat
(the asynchronous version), mapping over your array of filepaths, and using Promise.all.
Using the fs.stat
(the asynchronous version) function, you can start the calls of many files at a time so that it overall happens faster (because multiple files can be loaded at once without having to wait for super slow ones)
Here's an example of what I mean, that you can run in the browser:
QUESTION
I am using the following docker-compose image, I got this image from: https://github.com/apache/airflow/blob/main/docs/apache-airflow/start/docker-compose.yaml
...ANSWER
Answered 2021-Jun-14 at 16:35Support for _PIP_ADDITIONAL_REQUIREMENTS
environment variable has not been released yet. It is only supported by the developer/unreleased version of the docker image. It is planned that this feature will be available in Airflow 2.1.1. For more information, see: Adding extra requirements for build and runtime of the PROD image.
For the older version, you should build a new image and set this image in the docker-compose.yaml
. To do this, you need to follow a few steps.
- Create a new
Dockerfile
with the following content:
QUESTION
I'm not sure what is going wrong but the data from the user is not pre populating into the form, even after following the django documentation, I'm only getting a empty form , in the url I have the correct id for the item , I have text and 2 'filefields' that i need to request into the update form and want the user to be able to update one or more of the fields , appreciate the help ?
here are my views and updateform html
views
...ANSWER
Answered 2021-Jun-14 at 14:48You are not passing the track instance properly
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