sanitizer | Sanitize data using a number of mutation methods | Validation library

 by   daylerees PHP Version: 1.0.2 License: No License

kandi X-RAY | sanitizer Summary

kandi X-RAY | sanitizer Summary

sanitizer is a PHP library typically used in Utilities, Validation applications. sanitizer has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

Sanitizers can be used to standardize data to ease validation, or provide data consistency.
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            kandi-support Support

              sanitizer has a low active ecosystem.
              It has 256 star(s) with 22 fork(s). There are 12 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 2 open issues and 8 have been closed. On average issues are closed in 136 days. There are 1 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of sanitizer is 1.0.2

            kandi-Quality Quality

              sanitizer has 0 bugs and 0 code smells.

            kandi-Security Security

              sanitizer has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              sanitizer code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              sanitizer does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
              OutlinedDot
              Without a license, all rights are reserved, and you cannot use the library in your applications.

            kandi-Reuse Reuse

              sanitizer releases are available to install and integrate.
              Installation instructions, examples and code snippets are available.
              sanitizer saves you 102 person hours of effort in developing the same functionality from scratch.
              It has 259 lines of code, 30 functions and 5 files.
              It has medium code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed sanitizer and discovered the below as its top functions. This is intended to give you an instant insight into sanitizer implemented functionality, and help decide if they suit your requirements.
            • Sanitize a field .
            • Execute a sanitizer .
            • Run all global saniters .
            • Sanitize fields .
            • Resolve callback .
            • Get the sanitizer accessor .
            Get all kandi verified functions for this library.

            sanitizer Key Features

            No Key Features are available at this moment for sanitizer.

            sanitizer Examples and Code Snippets

            No Code Snippets are available at this moment for sanitizer.

            Community Discussions

            QUESTION

            Why does malloc produce seg fault when accessing a member reference from C++ struct?
            Asked 2022-Mar-28 at 13:39

            Consider the following code example:

            ...

            ANSWER

            Answered 2022-Mar-28 at 13:39

            The reason of the SEGV is because the new operator calls the class default constructor, it is where the initialization of the non-static data members is done, in this case setting x to 2 and rx to x.

            When you allocate the memory with malloc the default constructor is not called. So the SEGV rises because rx is never set to point to x, it is an undefined behavior.

            You have to call the default constructor explicitly, with "new(f2) Foo", it is called placement new operator.

            Source https://stackoverflow.com/questions/71647993

            QUESTION

            gdb: Get last changes of value
            Asked 2022-Mar-26 at 22:01

            I have a C-application which has a bug: There's a value (at a specific location in an static array; so the address is well-known) which has at some point an unexpected value. I've tried these things:

            • Using address sanitizer: It did not detect anything
            • Using watch-point: Unfortunately the value can change many many times in a valid way until the change is invalid. Even the final value might an will appear many times (which is valid). So it's not possible to check for a specific value.

            As soon as the value is "unexpected", the application will hang (basically a spin-lock will loop forever). If this happens I would like to get the last changes for the specific address.

            Is it somehow possible to do this with gdb?

            Thank you very much

            -edit-

            It would already be sufficient to always dump the stacktrace when the value changes and automatically continue. I'm not sure if that's easily possible with gdb.

            ...

            ANSWER

            Answered 2022-Mar-26 at 22:01

            Using watch-point: Unfortunately the value can change many many times in a valid way until the change is invalid. Even the final value might an will appear many times (which is valid). So it's not possible to check for a specific value.

            A GDB watchpoint does not only support breaks if the value at a particular memory address changes to a particular value. It also supports more complex conditional expressions, such as:

            Source https://stackoverflow.com/questions/71630701

            QUESTION

            Why is address sanitizer not indicating a memory leak after malloc() memory was not freed?
            Asked 2022-Mar-10 at 06:57

            (I did not write this code, my professor did...) I was looking at some code that my professor wrote and it all made sense to me, except for one thing. (Because we were running out of time, he did not bother to free any of the memory), however, he was compiling with address sanitizer on. But when he ran the code, no address sanitizer error warning was shown?

            We were running gcc 9.3 on an Ubuntu machine. When I comment out the add_line function, it throws leaks, only for crnt. I guess lines does not throw a memory leak because it was declared in the global space? But why doesn't crnt throw a memory leak when the add_line function is called?

            (Also, here are the compile flags that are used. -g -std=c99 -Wall -Wvla -fsanitize=address,undefined)

            Here is the code:

            ...

            ANSWER

            Answered 2022-Mar-10 at 06:57

            The issue here is the definition of "memory leak". I would have liked to have quoted a section in LeakSanitizer's documentation where it offers a clear and precise definition of the concept, which seems fundamental to its operation, but I couldn't find one, so you'll have to bear with a bit of projection on my part.

            A region of dynamically allocated (i.e. with malloc or friends) memory has leaked when there is no possible way for it to be freed. In other words, if your program allocates memory and throws away the address before the allocation has been free'd, the memory has leaked.

            That's subtly different from what you might think the definition is. You might think that memory has leaked if your program terminates without freeing every block of memory it allocated. That's certainly a possible definition, and I'm not going to criticise it (much), but it's actually not very precise.

            At what point has the program terminated? It hasn't really terminated when main() returns, because you might still have clean-up functions registered with atexit(), and those functions don't execute until after main() returns. (Or when exit() is called, which is effectively the same thing.) It's actually pretty common (though, to my mind, pointless) to use atexit() functions precisely in order to free() objects which might not have been deallocated before exit().

            OK, you can't check whether a memory allocation has been freed by checking whether it has been freed when main returns. If you want to do it that way, you need to defer the test until really the last possible moment. But at what's really the last possible moment, the process is about to cease to exist and the operating system is going to reclaim all the memory used by the process, including whatever resources were acquired by the memory allocation library. So at the last possible moment, there is no memory leak, because there is no memory.

            (There are embedded systems which have no concept of separate processes memory, etc., and so what I wrote up there might not apply to every possible computation system. But it applies to everything on which AddressSanitizer is implemented.)

            A key point is that the atexit() handler needs to be able to find the objects it is cleaning up, and since it executes after main() has terminated, it cannot use any automatic (i.e. stack-allocated) object. Only objects with static lifetime are available to it. So for it to be able to do its task, the address of the object to be cleaned up on termination must be stored in global memory. If the region's memory is not stored somewhere persistent, the memory has leaked (as per my definition above) and we don't actually have to wait to see whether an atexit manages to free the memory.

            Which brings us back to what I claim is a workable definition of a memory leak: dynamically allocated memory whose address is no longer present in the executable. That memory region can no longer be used, so it's garbage, but it cannot be freed because there the program doesn't know what its address is.

            Your lines array is a global variable. Indeed, you point that out in your question:

            I guess lines does not throw a memory leak because it was declared in the global space?

            That's correct. lines is a global variable, so its contents are still accessible even after main() returns. Not only are its contents accessible, so is any memory pointed to by some object in the array it points to. You could, if you wanted to, free the saved lines in an atexit handler:

            Source https://stackoverflow.com/questions/71418808

            QUESTION

            Can typescript property decorators modify instance members instead of the entire class?
            Asked 2022-Mar-03 at 03:34

            I want to write a sanitizer decorator which I can put on all user-input string fields. This simply replaces the standard .set(newValue) with .set( sanitize(newValue) ). However I have found the below code only works for one instance. A second instance of the same class ends up sharing the currentValue. After further reading this is actually expected, but I can't work out how to make it per-instance.

            ...

            ANSWER

            Answered 2022-Mar-03 at 03:34

            The main issue here is that Sanitize() gets called once per decorated class property declaration, and so for any given class property there will be only one currentValue. Meaning that two instances of the class will share the same currentValue. If you want to store one value per decorated class property per class instance, then you need access to class instances, and you will have to store the value either in those instances (via a property key that isn't going to interfere with any other properties), or in some map whose key is those instances. In the following I will show how to store the value in the class instances, and to avoid worrying about property name collision I will use the symbol output of the Symbol function, which is guaranteed to be unique.

            Also note that Sanitize() is passed the class prototype as the target argument, so any manipulation you perform on target will affect the prototype and not any instance of the class. When you write target[propertyKey], you are looking up the property in the class prototype, and string-valued properties will almost certainly not be set in the prototype. So this is probably not necessary or useful, and we should get rid of it.

            So if you only have direct access to the class prototype, how do you do anything with class instances? Well, to do this, you should use the this context of the get method and set method of the accessor property descriptor you pass to defineProperty(). And that means get and set need to be methods or at least function expressions, and not arrow function expressions which have no distinct this context.

            Okay, enough explanation, here's the code:

            Source https://stackoverflow.com/questions/71314708

            QUESTION

            dangling reference in nested vector when parent container reallocates
            Asked 2022-Feb-25 at 23:49

            thing contains 2 vectors, one of foo and one of bar.

            The bar instances contain references to the foos - the potentially dangling ones.

            The foo vector is filled precisely once, in things's constructor initializer list, and the bar vector is filled precisely once in things's constructor body.

            main() holds a std::vector but this vector is filled incrementally without .reserve(), and is therefore periodically reallocating.

            I am struggling to reproduce it in the minimal example below, but in the more heavyweight complete code the f1 and f2 references trigger the address sanitizer with "use after free".

            I find this "slightly" surprising, because yes, the "direct members" of std::vector in thing (ie the start_ptr, size, capacity), they get realloc'd when things in main() grows. But I would have thought that the "heap resource" of foos could (?) stay the same when the std::vector get's realloc'd because there is no need to move them.

            Is the answer here, that: "Yes the foo heap objects may not move when things realloc's, but this is by no means guaranteed and that's why I am getting inconsistent results"?

            What exactly is and isn't guaranteed here that I can rely on?

            ...

            ANSWER

            Answered 2022-Feb-25 at 23:49

            What you are guaranteed is, upon moving a std::vector, no iterator, pointer or reference will be invalidated. This would apply to the vectors inside thing. See notes in https://en.cppreference.com/w/cpp/container/vector/vector

            When a std::vector grows, all iterators, pointers and references to it become invalid. So if you had a reference to a thing, those would be blown away, but you do not have that, so we are good.

            While a std::vector grows, it will move the previous elements to the new allocation if the contained type has a noexcept move constructor. For std::vectors, this is the case after C++17. The automatically generated move constructor of thing therefore should also qualify.

            Considering these, the code you have posted is correct. As we do not see all the code, there must be an issue somewhere else that interacts with the code you have. Perhaps you have a user defined move constructor in the real code that you did not mark as noexcept, or you push_back to one of the foo vectors.

            Also, the reserve call is a no-op: foos.reserve(bars.size());. bars.size() here is 0. Did you mean bars.reserve(foos.size());?

            Source https://stackoverflow.com/questions/71272476

            QUESTION

            How can I apply a filter when I check the checkbox in my Wordpress plugin?
            Asked 2022-Feb-24 at 09:06

            I am building a wordpress plugin, and I want to apply and use a file that has the code bellow, when I check the checkbox inside the plugin's settings page.

            Function I want to apply:

            ...

            ANSWER

            Answered 2022-Feb-24 at 09:06

            I hope I understand what you mean. Yo should check the option homepage_text and to add the filter.

            Source https://stackoverflow.com/questions/71146156

            QUESTION

            Occasional crash in Swift async/await concurrency code - only in release builds
            Asked 2022-Feb-10 at 13:26

            I'm hitting an occasional crash in some code which uses Swift's new concurrency features. This crash never seems to happen on development builds, either in the simulator or when I install the code on a device directly from Xcode. However it's happening pretty frequently when folks install the code from TestFlight.

            The actual crash is this:

            ...

            ANSWER

            Answered 2022-Feb-10 at 13:26

            You cannot use semaphores in conjunction with async-await. See Swift concurrency: Behind the scenes:

            [Primitives] like semaphores ... are unsafe to use with Swift concurrency. This is because they hide dependency information from the Swift runtime, but introduce a dependency in execution in your code. Since the runtime is unaware of this dependency, it cannot make the right scheduling decisions and resolve them. In particular, do not use primitives that create unstructured tasks and then retroactively introduce a dependency across task boundaries by using a semaphore or an unsafe primitive. Such a code pattern means that a thread can block indefinitely against the semaphore until another thread is able to unblock it. This violates the runtime contract of forward progress for threads.

            You might consider testing with the LIBDISPATCH_COOPERATIVE_POOL_STRICT environment variable as discussed here, in the same video.

            You ask:

            I'm trying to bridge the divide between synchronous and asynchronous code (perhaps the wrong way).

            You should refactor the code that calls this synchronous method to adopt asynchronous pattern, and then excise all blocking API (e.g., semaphore wait, dispatch group wait, etc.). Those were anti-patterns in the GCD world and are to be avoided within Swift concurrency. I understand why developers who are unfamiliar with asynchronous programming are so attracted to those synchronous anti-patterns, but it has always been a mistake, and should be excised from one’s code.

            Bottom line, in Swift concurrency one must “maintain a runtime contract that threads are always able to make forward progress.” Just embrace asynchronous patterns (i.e., stay within async-await without any old-school thread-blocking techniques) and you should be good.

            FWIW, the Swift concurrency: Update a sample app shows interesting techniques for incrementally updating an old app. E.g., mark this blocking method as deprecated, and then the compiler will warn you where it is called and you can direct your refactoring efforts to those offending routines.

            Source https://stackoverflow.com/questions/71065319

            QUESTION

            Error getting a simple example to work in Rails / Turbo / Hotwire
            Asked 2022-Feb-09 at 10:13

            I am learning Hotwire-rails, following both the gorails.com and the Hotwire.dev examples. I am running Ruby 3.0.2 and Rails 6.1.4.1. The symptom is at the very start. After rails new xxx, I edit Gemfile to add gem 'hotwire-rails', then bundle install. At this point my app/javascript/packs/application.js is now:

            ...

            ANSWER

            Answered 2021-Nov-11 at 12:27

            This seems like everything is working correctly rails just likes to output what its doing to the console but it should have added those to your file.

            Source https://stackoverflow.com/questions/69916763

            QUESTION

            How to get the load address of an ios app running on simulator
            Asked 2022-Jan-27 at 14:00

            Without the load address it is not possible to run atos on a binary correctly. I'm debugging an iOS app inside (lldb) and the app has reported a diagnostic message (thread sanitizer report) which has list of addresses like this:

            ...

            ANSWER

            Answered 2022-Jan-27 at 14:00

            lldb has target module lookup -a flag that shows the name of the module and it's load address.

            e.g.,

            Source https://stackoverflow.com/questions/70873456

            QUESTION

            Seeing if a value is present in a dictionary
            Asked 2022-Jan-10 at 06:17

            Is there a way to see if an item is located in a dictionary values.

            My attempt:

            ...

            ANSWER

            Answered 2022-Jan-10 at 05:24

            You could simplify your search this way:

            Source https://stackoverflow.com/questions/70648092

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install sanitizer

            The Sanitizer package can be used stand-alone or with the Laravel Framework.

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            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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