sanitizer | Sanitize data using a number of mutation methods | Validation library
kandi X-RAY | sanitizer Summary
kandi X-RAY | sanitizer Summary
Sanitizers can be used to standardize data to ease validation, or provide data consistency.
Support
Quality
Security
License
Reuse
Top functions reviewed by kandi - BETA
- Sanitize a field .
- Execute a sanitizer .
- Run all global saniters .
- Sanitize fields .
- Resolve callback .
- Get the sanitizer accessor .
sanitizer Key Features
sanitizer Examples and Code Snippets
Community Discussions
Trending Discussions on sanitizer
QUESTION
Consider the following code example:
...ANSWER
Answered 2022-Mar-28 at 13:39The reason of the SEGV is because the new operator calls the class default constructor, it is where the initialization of the non-static data members is done, in this case setting x to 2 and rx to x.
When you allocate the memory with malloc the default constructor is not called. So the SEGV rises because rx is never set to point to x, it is an undefined behavior.
You have to call the default constructor explicitly, with "new(f2) Foo", it is called placement new operator.
QUESTION
I have a C-application which has a bug: There's a value (at a specific location in an static array; so the address is well-known) which has at some point an unexpected value. I've tried these things:
- Using address sanitizer: It did not detect anything
- Using watch-point: Unfortunately the value can change many many times in a valid way until the change is invalid. Even the final value might an will appear many times (which is valid). So it's not possible to check for a specific value.
As soon as the value is "unexpected", the application will hang (basically a spin-lock will loop forever). If this happens I would like to get the last changes for the specific address.
Is it somehow possible to do this with gdb?
Thank you very much
-edit-
It would already be sufficient to always dump the stacktrace when the value changes and automatically continue. I'm not sure if that's easily possible with gdb.
...ANSWER
Answered 2022-Mar-26 at 22:01Using watch-point: Unfortunately the value can change many many times in a valid way until the change is invalid. Even the final value might an will appear many times (which is valid). So it's not possible to check for a specific value.
A GDB watchpoint does not only support breaks if the value at a particular memory address changes to a particular value. It also supports more complex conditional expressions, such as:
QUESTION
(I did not write this code, my professor did...) I was looking at some code that my professor wrote and it all made sense to me, except for one thing. (Because we were running out of time, he did not bother to free any of the memory), however, he was compiling with address sanitizer on. But when he ran the code, no address sanitizer error warning was shown?
We were running gcc 9.3
on an Ubuntu machine. When I comment out the add_line
function, it throws leaks, only for crnt
. I guess lines
does not throw a memory leak because it was declared in the global space? But why doesn't crnt
throw a memory leak when the add_line
function is called?
(Also, here are the compile flags that are used.
-g -std=c99 -Wall -Wvla -fsanitize=address,undefined
)
Here is the code:
...ANSWER
Answered 2022-Mar-10 at 06:57The issue here is the definition of "memory leak". I would have liked to have quoted a section in LeakSanitizer's documentation where it offers a clear and precise definition of the concept, which seems fundamental to its operation, but I couldn't find one, so you'll have to bear with a bit of projection on my part.
A region of dynamically allocated (i.e. with malloc
or friends) memory has leaked when there is no possible way for it to be free
d. In other words, if your program allocates memory and throws away the address before the allocation has been free'd, the memory has leaked.
That's subtly different from what you might think the definition is. You might think that memory has leaked if your program terminates without freeing every block of memory it allocated. That's certainly a possible definition, and I'm not going to criticise it (much), but it's actually not very precise.
At what point has the program terminated? It hasn't really terminated when main()
returns, because you might still have clean-up functions registered with atexit()
, and those functions don't execute until after main()
returns. (Or when exit()
is called, which is effectively the same thing.) It's actually pretty common (though, to my mind, pointless) to use atexit()
functions precisely in order to free()
objects which might not have been deallocated before exit()
.
OK, you can't check whether a memory allocation has been freed by checking whether it has been free
d when main
returns. If you want to do it that way, you need to defer the test until really the last possible moment. But at what's really the last possible moment, the process is about to cease to exist and the operating system is going to reclaim all the memory used by the process, including whatever resources were acquired by the memory allocation library. So at the last possible moment, there is no memory leak, because there is no memory.
(There are embedded systems which have no concept of separate processes memory, etc., and so what I wrote up there might not apply to every possible computation system. But it applies to everything on which AddressSanitizer is implemented.)
A key point is that the atexit()
handler needs to be able to find the objects it is cleaning up, and since it executes after main()
has terminated, it cannot use any automatic (i.e. stack-allocated) object. Only objects with static lifetime are available to it. So for it to be able to do its task, the address of the object to be cleaned up on termination must be stored in global memory. If the region's memory is not stored somewhere persistent, the memory has leaked (as per my definition above) and we don't actually have to wait to see whether an atexit
manages to free
the memory.
Which brings us back to what I claim is a workable definition of a memory leak: dynamically allocated memory whose address is no longer present in the executable. That memory region can no longer be used, so it's garbage, but it cannot be free
d because there the program doesn't know what its address is.
Your lines
array is a global variable. Indeed, you point that out in your question:
I guess
lines
does not throw a memory leak because it was declared in the global space?
That's correct. lines
is a global variable, so its contents are still accessible even after main()
returns. Not only are its contents accessible, so is any memory pointed to by some object in the array it points to. You could, if you wanted to, free
the saved lines in an atexit
handler:
QUESTION
I want to write a sanitizer decorator which I can put on all user-input string fields. This simply replaces the standard .set(newValue)
with .set( sanitize(newValue) )
. However I have found the below code only works for one instance. A second instance of the same class ends up sharing the currentValue. After further reading this is actually expected, but I can't work out how to make it per-instance.
ANSWER
Answered 2022-Mar-03 at 03:34The main issue here is that Sanitize()
gets called once per decorated class property declaration, and so for any given class property there will be only one currentValue
. Meaning that two instances of the class will share the same currentValue
. If you want to store one value per decorated class property per class instance, then you need access to class instances, and you will have to store the value either in those instances (via a property key that isn't going to interfere with any other properties), or in some map whose key is those instances. In the following I will show how to store the value in the class instances, and to avoid worrying about property name collision I will use the symbol
output of the Symbol
function, which is guaranteed to be unique.
Also note that Sanitize()
is passed the class prototype as the target
argument, so any manipulation you perform on target
will affect the prototype and not any instance of the class. When you write target[propertyKey]
, you are looking up the property in the class prototype, and string
-valued properties will almost certainly not be set in the prototype. So this is probably not necessary or useful, and we should get rid of it.
So if you only have direct access to the class prototype, how do you do anything with class instances? Well, to do this, you should use the this
context of the get
method and set
method of the accessor property descriptor you pass to defineProperty()
. And that means get
and set
need to be methods or at least function
expressions, and not arrow function expressions which have no distinct this
context.
Okay, enough explanation, here's the code:
QUESTION
thing
contains 2 vectors, one of foo
and one of bar
.
The bar
instances contain references to the foos
- the potentially dangling ones.
The foo
vector is filled precisely once, in things
's constructor initializer list, and the bar
vector is filled precisely once in things
's constructor body.
main()
holds a std::vector
but this vector is filled incrementally without .reserve()
, and is therefore periodically reallocating.
I am struggling to reproduce it in the minimal example below, but in the more heavyweight complete code the f1
and f2
references trigger the address sanitizer with "use after free".
I find this "slightly" surprising, because yes, the "direct members" of std::vector
in thing (ie the start_ptr, size, capacity), they get realloc'd when things
in main()
grows. But I would have thought that the "heap resource" of foos
could (?) stay the same when the std::vector
get's realloc'd because there is no need to move them.
Is the answer here, that: "Yes the foo
heap objects may not move when things
realloc's, but this is by no means guaranteed and that's why I am getting inconsistent results"?
What exactly is and isn't guaranteed here that I can rely on?
...ANSWER
Answered 2022-Feb-25 at 23:49What you are guaranteed is, upon moving a std::vector
, no iterator, pointer or reference will be invalidated. This would apply to the vectors inside thing
. See notes in https://en.cppreference.com/w/cpp/container/vector/vector
When a std::vector
grows, all iterators, pointers and references to it become invalid. So if you had a reference to a thing
, those would be blown away, but you do not have that, so we are good.
While a std::vector
grows, it will move the previous elements to the new allocation if the contained type has a noexcept
move constructor. For std::vector
s, this is the case after C++17. The automatically generated move constructor of thing
therefore should also qualify.
Considering these, the code you have posted is correct. As we do not see all the code, there must be an issue somewhere else that interacts with the code you have. Perhaps you have a user defined move constructor in the real code that you did not mark as noexcept
, or you push_back to one of the foo vectors.
Also, the reserve
call is a no-op: foos.reserve(bars.size());
. bars.size()
here is 0. Did you mean bars.reserve(foos.size());
?
QUESTION
I am building a wordpress plugin, and I want to apply and use a file that has the code bellow, when I check the checkbox inside the plugin's settings page.
Function I want to apply:
...ANSWER
Answered 2022-Feb-24 at 09:06I hope I understand what you mean. Yo should check the option homepage_text
and to add the filter.
QUESTION
I'm hitting an occasional crash in some code which uses Swift's new concurrency features. This crash never seems to happen on development builds, either in the simulator or when I install the code on a device directly from Xcode. However it's happening pretty frequently when folks install the code from TestFlight.
The actual crash is this:
...ANSWER
Answered 2022-Feb-10 at 13:26You cannot use semaphores in conjunction with async-await. See Swift concurrency: Behind the scenes:
[Primitives] like semaphores ... are unsafe to use with Swift concurrency. This is because they hide dependency information from the Swift runtime, but introduce a dependency in execution in your code. Since the runtime is unaware of this dependency, it cannot make the right scheduling decisions and resolve them. In particular, do not use primitives that create unstructured tasks and then retroactively introduce a dependency across task boundaries by using a semaphore or an unsafe primitive. Such a code pattern means that a thread can block indefinitely against the semaphore until another thread is able to unblock it. This violates the runtime contract of forward progress for threads.
You might consider testing with the LIBDISPATCH_COOPERATIVE_POOL_STRICT
environment variable as discussed here, in the same video.
You ask:
I'm trying to bridge the divide between synchronous and asynchronous code (perhaps the wrong way).
You should refactor the code that calls this synchronous method to adopt asynchronous pattern, and then excise all blocking API (e.g., semaphore wait
, dispatch group wait
, etc.). Those were anti-patterns in the GCD world and are to be avoided within Swift concurrency. I understand why developers who are unfamiliar with asynchronous programming are so attracted to those synchronous anti-patterns, but it has always been a mistake, and should be excised from one’s code.
Bottom line, in Swift concurrency one must “maintain a runtime contract that threads are always able to make forward progress.” Just embrace asynchronous patterns (i.e., stay within async-await without any old-school thread-blocking techniques) and you should be good.
FWIW, the Swift concurrency: Update a sample app shows interesting techniques for incrementally updating an old app. E.g., mark this blocking method as deprecated, and then the compiler will warn you where it is called and you can direct your refactoring efforts to those offending routines.
QUESTION
I am learning Hotwire-rails, following both the gorails.com and the Hotwire.dev examples. I am running Ruby 3.0.2 and Rails 6.1.4.1. The symptom is at the very start. After rails new xxx, I edit Gemfile to add gem 'hotwire-rails', then bundle install. At this point my app/javascript/packs/application.js is now:
...ANSWER
Answered 2021-Nov-11 at 12:27This seems like everything is working correctly rails just likes to output what its doing to the console but it should have added those to your file.
QUESTION
Without the load address it is not possible to run atos
on a binary correctly. I'm debugging an iOS app inside (lldb) and the app has reported a diagnostic message (thread sanitizer report) which has list of addresses like this:
ANSWER
Answered 2022-Jan-27 at 14:00lldb has
target module lookup -a
flag that shows the name of the module and it's load address.
e.g.,
QUESTION
Is there a way to see if an item is located in a dictionary values.
My attempt:
...ANSWER
Answered 2022-Jan-10 at 05:24You could simplify your search this way:
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install sanitizer
Support
Reuse Trending Solutions
Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items
Find more librariesStay Updated
Subscribe to our newsletter for trending solutions and developer bootcamps
Share this Page