anbu | Anbu profiler for the Laravel PHP Framework | Monitoring library
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kandi X-RAY | anbu Summary
Anbu profiler for the Laravel PHP Framework.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of anbu
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QUESTION
i created onclick react grid video player using ag-grid. after that passing json data to grid.
after passing json data my ag-grid look like
Now i passed only one local storage video to react video player(Play button )
...ANSWER
Answered 2022-Apr-05 at 05:29Guessing the local storage meant here is the repository folder where videos are present.
The main reason for why it does not work is because videos are not served for your frontend.
I would suggest having a server side setup and serve each video with an url. Then simply refer to that url in your frontend, rather than embedding the whole mp4 within your frontend.
The import myData from "../video.mp4"
which works because of webpack simply embedded the whole video binary within your frontend javascript during compilation.
For multiple videos case, the reason why it does not work is simply they are not require
or import
in your javascript, so they are not embedded to your frontend code.
If you really want to have frontend reading your local files, you may use File System Access API
and take a look at this reference, and this is full guide of the API.
If you want to use the map()
, you may change the json to something like this, with dob as your video url.
QUESTION
public class Array_Learn {
public static void main(String[] args) {
try {
FileInputStream ExcelFile = new FileInputStream(new File("C:\\Users\\Anbu.B\\Desktop\\POI-Test\\mediTask.xlsx"));
XSSFWorkbook book1 = new XSSFWorkbook(ExcelFile);
XSSFSheet sheet = book1.getSheetAt(0);
Iterator rowiter = sheet.iterator();
while (rowiter.hasNext()) {
XSSFRow row = (XSSFRow) rowiter.next();
if (row.getRowNum() == 2) {
Iterator cellIterator = row.cellIterator();
while (cellIterator.hasNext()) {
XSSFCell cell = (XSSFCell) cellIterator.next();
if (cell.getStringCellValue().contains("|")) {
String split[] = cell.getStringCellValue().split("\\|");
}
}
}
}
} catch (Exception e) {
System.out.println(e);
}
}
}
...ANSWER
Answered 2021-Jul-08 at 10:25You almost finished your task. The key here to use one of the algorithms to generate combinations. You could find a general description of such algorithms there, or more close examples with strings on java there.
Full code example (recursive algorithm):
The ParsedRow
class for calculating of different combinations:
QUESTION
I know it is not correct implementation for print_winner function (printf should be inside the if statment). However, I cannot figure out why printf prints names differently when placed outside if-statement?
If I place printf outside if statement, here is the code and output
Code:
...ANSWER
Answered 2020-Jul-19 at 16:56in your first case the winner name you print is candidates[0].name
which is sonia until if (candidates[k].votes == maximum)
become true and you reassign winner, and you print candidate_count times because unconditionally in the loop.
In the second case you only print the name of the person whose votes number equals the maximum (if (candidates[k].votes == maximum)
is true), so only ben and anbu having both 2 votes being the maximum.
Because several persons can have the same number of votes it is useless to have the variable winner, you can do
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