minit | A WordPress plugin to combine CSS and Javascript files | Content Management System library

Taken directly from the docs. Read them for more info.

function hook_requirements

Check installation requirements and do status reporting.
This hook has three closely related uses, determined by the $phase argument:

• Checking installation requirements ($phase == 'install').
• Checking update requirements ($phase == 'update').
• Status reporting ($phase == 'runtime').

The 'runtime' phase is not limited to pure installation requirements but can also be used for more general status information like maintenance tasks and security issues. The returned 'requirements' will be listed on the status report in the administration section, with indication of the severity level. Moreover, any requirement with a severity of REQUIREMENT_ERROR severity will result in a notice on the administration configuration page.

Why does it output differently using employees[0], employees[1], employees[2], versus employees[i]?

In this find method (db.employee.find( { 'ssn': employees[i] })), the result is a cursor. Note that a find always returns a cursor and findOne returns a document (or a null, if there is no matching document found). The cursor object can have zero or more documents, depending upon the query filter and the matched documents.

So, in your code if you want to print the result of the output of the query db.employee.find( { 'ssn': employees[i] }), you need to iterate thru the cursor. For example, you can do this in mongo shell:

I suspect that you incorrectly updated dataSource for mat-table.

Since you're using MatTableDataSource then you need to go with:

Do you really need the NOT IN ? You could work around that by using a function and then creating a function based index. Make sure you where clause matches the predicate exactly. Example:

You already put readAgain to false it means it only read the first time.

readAgain boolean: Whether to re-read the default values. If false, this method will set the default values only if this method has never been called in the past (or if the KEY_HAS_SET_DEFAULT_VALUES in the default value shared preferences file is false). To attempt to set the default values again bypassing this check, set readAgain to true.

When you call this, it means you using default SharedPreference of your app.

You don't see the table in the result of your query because you have not granted any privileges on the table level, only on the column level.

You'd have to look in information_schema.role_column_grants:

In both cases you violated the primary key of the table, which must be unique. "Houston" is repeated for DEPT_LOCATIONS, as is "Alice" for DEPENDENTS.

First, you need a GROUP BY clause to make your query a valid aggregation query: that clause should include all non-aggreated columns (I also added the project number, in case two projects have the same name).

Then, you can use a HAVING clause to filter on projects that have more than one employee:

I am not sure what your teacher means by query, but I bet he means to create a View.

Example: