tall | A TALL | Plugin library
kandi X-RAY | tall Summary
kandi X-RAY | tall Summary
A front-end preset for Laravel to scaffold an application using the TALL stack, jumpstarting your application's development.
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Top functions reviewed by kandi - BETA
- Reset the user s password .
- Register a new user .
- Bootstrap the plugin .
- Install package .
- Send a reset link to the user .
- Authenticate user .
- Resend the verification email .
- Confirm the user .
- Create password reset table .
- Update package array .
tall Key Features
tall Examples and Code Snippets
Community Discussions
Trending Discussions on tall
QUESTION
I have been trying to aggregate the sum of one column in a dataframe for all pairwise comparisons of the other columns in a data frame. The dataset I have is very large, but below is a dummy set that illustrates the issue I am having. I want to be able to do this so I can not repeat a ton of code to individually get these pairwise summations.
...ANSWER
Answered 2022-Mar-30 at 00:51You can use combn()
to get the possible combinations of indices and then lapply()
over that.
QUESTION
I am making an interface to store character and dinosaur variables to a list and then print them out when asked.
There is a switch statement to take the users' inputs:
- Case 1: The function allows the user to input character data and then it's put into a list.
- Case 2.: The function allows the user to input dinosaur data and then it put into a list.
- Case 3 The function prints the objects in each list. However, whenever I run it it doesn't print anything and comes up with no errors. If I run the code to print each list in their respective case then they print out fine.
ANSWER
Answered 2022-Mar-27 at 02:11The lists that store the characters and the dinos need to be outside of the MenuChosen
method because as you code is written everytime MenuChosen
is called new lists are created.
You could:
QUESTION
Main Question:
Say I have some algorithm, that runs in O(n^2).
I get that, if I input an n twice the size of the original n I get 4 doubling of the maximal time complexity.
But how does it relate to running the algorithm twice with an input size of n?
Why I am asking:
The reason for why I'm asking, is because I made an algorithm whose big O notation was O(log_2(n)). But running it and comparing it to O(log_2(n)) showed, that it performed FAR better for inputs at the magnitude of 1 billion. The algorithm would only be used on inputs the size of 10k-20k. Meaning that it performed wastly better than $C_1*log_2(n)$
I get that big O notation is the maximum, but it felt like I asked "How tall are you?" and the big O notation answered "I am shorter than 40 meters".
I googled around a bit and found, that big O is - "in industry" - primarily used for scalability. I.e you expect your n to reach that point where it will get close to its big O.
Then, in my case, does it even make sense to use big O notation? How does running the same algorithm multiple times, rather than increasing the input size, relate to big O notation?
...ANSWER
Answered 2022-Mar-10 at 10:22is there then anymore I can gather from the algorithm being O(log(n)) other than, it will be faster than that in the long run?
Time required by an implementation of an O(log n) algorithm will grow very, very slowly with problem size. It will not become faster with larger problem sizes, but the growth will be minimal.
Or would it be "useless" for me to use in practice, with input sizes of my dimension?
It depends on the available alternatives. If there is a faster but "worse" (big-O-wise) algorithm, it can make sense determine the input sizes where implementations of each are faster. An O(log n) will, however, always win over, say, O(n) algorithms in the long run (for big enough n). If there is no faster alternative, why worry? O(log n) is good to have, even if you do not "need" it.
Big-O only helps you to choose algorithms that can scale as expected as problem sizes grow. An algorithm's big-O class says nothing about how well a specific implementation of that algorithm will perform for a specific input on a specific machine. Indeed, it is frequent to use "bad" algorithms (with, say, O(n^2) complexity) instead of "good" algorithms (say, O(n log n)) for smaller problems, simply because they will be faster for those input sizes. Look at sorting: many implementations of quicksort fall back to insertsort for very small inputs:
This line in java's standard library source-code comes to mind: its authors have experimentally determined that, for arrays of less than 7 elements, insert-sort is quicker than quicksort.
QUESTION
I have a dataset that has this structure (lots of questions asked to survey respondents) that I want to reshape from wide to long:
...ANSWER
Answered 2022-Feb-21 at 19:08We could use names_pattern
after rearranging the substring in column names
QUESTION
I want to generate a rank 5 100x600 matrix in numpy with all the entries sampled from np.random.uniform(0, 20), so that all the entries will be uniformly distributed between [0, 20). What will be the best way to do so in python?
I see there is an SVD-inspired way to do so here (https://math.stackexchange.com/questions/3567510/how-to-generate-a-rank-r-matrix-with-entries-uniform), but I am not sure how to code it up. I am looking for a working example of this SVD-inspired way to get uniformly distributed entries.
I have actually managed to code up a rank 5 100x100 matrix by vertically stacking five 20x100 rank 1 matrices, then shuffling the vertical indices. However, the resulting 100x100 matrix does not have uniformly distributed entries [0, 20).
Here is my code (my best attempt):
...ANSWER
Answered 2022-Jan-24 at 15:05Not a perfect solution, I must admit. But it's simple and comes pretty close.
I create 5 vectors that are gonna span the space of the matrix and create random linear combinations to fill the rest of the matrix.
My initial thought was that a trivial solution will be to copy those vectors 20 times.
To improve that, I created linear combinations of them with weights drawn from a uniform distribution, but then the distribution of the entries in the matrix becomes normal because the weighted mean basically causes the central limit theorm to take effect.
A middle point between the trivial approach and the second approach that doesn't work is to use sets of weights that favor one of the vectors over the others. And you can generate these sorts of weight vectors by passing any vector through the softmax function with an appropriately high temperature parameter.
The distribution is almost uniform, but the vectors are still very close to the base vectors. You can play with the temperature parameter to find a sweet spot that suits your purpose.
QUESTION
I use a ZStack
to display a fullscreen background image underneath the main UI. The main UI consists of a VStack
with multiple views separated by flexible Spacers to scale down or up on different device sizes. Now I experience that the Spacers will not scale down on small devices because the background image on small devices remains bigger than the screen size and keeps the ZStack
tall, see screenshot of the preview of iPhone 8. What am I doing wrong here?
Code:
...ANSWER
Answered 2022-Jan-24 at 10:47In described scenario you need to use .background
instead of ZStack
, such so main view form needed full-screen layout and image in background will not affect it.
So the layout should be like
QUESTION
I have a plot with labelled rectangles. To ensure text stays inside the rectangle I'm using the ggfittext package. Example below:
...ANSWER
Answered 2021-Dec-17 at 13:45I'm the author of ggfittext. ggfittext can't automatically rotate the text in the way you're describing, and I'm not aware of any package that will do this.
geom_fit_text()
does include a reflow
argument that will reflow multi-word text to better fit the box. This doesn't work by simply shortening the line length until the text fits, but will find the line length that makes the aspect ratio of the text closest to that of the box. Obviously this is more useful with longer text labels.
QUESTION
I have a dataframe that I want to gather
so that it is in tall format, and then mutate
on another column with values based on membership of a string from another column in a list of lists. For example, I have the following data frame and list of lists:
ANSWER
Answered 2021-Dec-15 at 17:31It may be easier with a regex_left_join
after converting the 'dummylist' to a two column dataset
QUESTION
I am currently taking a laravel 8 framework class and each time I install a laravel/ui (Bootstrap 4, TALL stack, etc) I get an error after running:
npm install && npm run dev
This is fixed by running the command again the second time, without having to troubleshoot or change anything. I don't have an issue with the error but as a freshman and a curious coder, I find myself wondering about what causes the error on the first run.
Here is an image of the error that stops the command the first time.
Can someone please explain what is it that happens the first time the commands are executed that causes the error to stop the execution of the command.
...ANSWER
Answered 2021-Dec-09 at 10:21Did you read the error message?
It says that it installed an additional dependency, and to run again.
That's why it works on the second time.
If you already had "resolve-url-loader": "^4.0.0"
in your "devDependencies"
, chances are Mix wouldn't have needed the extra step.
QUESTION
Many of you faced the error while coding in vs code unexpectedly. I had also faced the issue while coding and it seems to be a tall-order task to fix the issue.
Many of you tried even I also tried the following methods
- removed git folder
- uninstalled all extensions
- disabled the git in the settings.json file
- removed cached files of the software
- even uninstalled VS code and installed it again, but it gives me the same error that says: "Extension host terminated unexpectedly"
so what's the solution for this problem ?
...ANSWER
Answered 2021-Nov-22 at 04:32The solution for the problem :
Open your vscode and launch the command palette by
ctrl
+shift
+p
Start the Extension Bisect
You can see a pop-up window like this
If your vscode works perfectly, select "Good now"
However, if you see the error "Extension host terminated unexpectedly", select the "This is bad" option.
- This program is a binary search algorithm which finds the extensions that cause the root problem and fix the issue that currently faces
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install tall
Then simply run the following commands:.
If you would like to install the preset and its auth scaffolding in a fresh Laravel application, make sure to use the --auth flag on the ui command:.
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