7x | BOA specific Drupal 7 fork | Content Management System library
kandi X-RAY | 7x Summary
kandi X-RAY | 7x Summary
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Top functions reviewed by kandi - BETA
- Returns canonical path .
- Extracts data from a file .
- Resolve base name .
- Unserializes a string
- Set stream metadata
- Trigger duplicate alias warning
- Checks if a path contains a phar extension .
- Checks if a base file does not contain meta - data issues .
- Creates a new Target from given content .
- Asserts that the assertion is complete .
7x Key Features
7x Examples and Code Snippets
Community Discussions
Trending Discussions on 7x
QUESTION
I am currently trying to horizontally stack multiple video files and receiving this error
...ANSWER
Answered 2022-Mar-30 at 04:25Looks like the first input's resolution is changing midway.
Suppress reinitializing filters, and force initial resolution using scale.
ffmpeg -reinit_filter 0 -i RT05974d20e9550b89697b15f8bc3feb78.mkv -i RTb295d0534191e1acb22a45bb971a12e6.mka -i RTc2de0d06575c6c225b44dbce73104ed8.mkv -i RT3904b3a60273760ec9e9c181ea35bdc4.mka -i RT13386752138abbe5eb941da3f7fdfdc5.mka -i RTe31da14ad7c898ad8d8ce6bbafc5e387.mkv -i RT103bfe5f4b129860f69cd8e820f3a10b.mka -i RT2e5859b6a555070f3305735c698966d0.mka -filter_complex "[0:v]scale=iw:ih,setsar=1[v0];[2:v]tpad=start_duration=120:color=black[vpad]; [3:a]adelay=120000:all=1[a2pad]; [4:a]adelay=150000:all=1[a3pad]; [5:v]tpad=start_duration=20:color=black[v2pad]; [6:a]adelay=200000:all=1[a5pad]; [7:a]adelay=240000:all=1[a6pad]; [v0][vpad][v2pad]hstack=inputs=3[vout]; [1:a][a2pad][a3pad][a5pad][a6pad]amix=inputs=5:weights=1|1|1|1|1[aout]" -map [vout] -map [aout] output.mkv
QUESTION
Recently I was working on a discord bot to compute the roots of a cubic equation.
I have already made another program beforehand in C# that basically does the same thing, and is proven to work correctly, so I straight up copied the codes into the one which I am working with now.
(Suppose that I am calculating the roots of 7x3 + 2x2 + 12x + 9 = 0)
The code below is from the program which was created beforehand:
(Once again, the program and the results are proven to be correct, results are listed at the bottom of the code)*
ANSWER
Answered 2022-Mar-18 at 12:13Refering @mikuszefski 's comment,
The real cause behind this is that the Cbrt() function I have created calculates negative numbers wrongly.
For example, Cbrt(-1)
should yield the result -1
.
However, the answer I have gotten instead is (NaN, 0)
.
I have found the solution in another thread.
QUESTION
Target Environment: Wordpress VIP header.php
goal: click icon div to open third party chat, toggle to close if needed, chat icon to persist acrross all pages.
Hi All
I've been tasked with integrating a 3rd Party Chat app in our site. I want it to perform like a traditional chat in-page chat app (in a div) , however, the shared script uses js the window.open method and open the chat into a separate window. I've tried unsuccefully to use , tags. Suspect this shouldnt be to hard but I can't figure it out. I hope I have enough information here.
Thanks in advance! The code I am replacing is straight forward yet opens into a new window but I need the window to look like a modern chat
...ANSWER
Answered 2022-Mar-15 at 05:12No idea why you are over complicating this. is there a specific reason you want to load the iframe after? if not using css to style it and just toggling it to be visible is the best solution.
HTML
QUESTION
Hello I need to write a function that will automatically make a specific string
For example I have a List of elements:
...ANSWER
Answered 2022-Feb-06 at 18:38in a compact way to create the list
, you could use enumerate
:
QUESTION
Recently my friends and I decided to make a multi-functional calculator to automatically find
the roots of quadratic equations.
It wasn't that challenging after all, so we decided to go onto the next level, to make a calculator for a cubic equation.
(ax^3 + bx^2 + cx + d)
However, we stumbled across some trivial problems, and no matter how hard we tried, the results are still the same. we are beginners in terms of coding, so we're not sure if we are actually making some stupid mistakes here but at least we want to learn something from others.
Basically, we have tried a lot of combinations of different cubic equations, or even re-coding the whole thing. The problem is that the results we yield are always wrong, but only for the real parts of the second root and third root.
For a better understanding, we have tried 9x^3 + 8x^2 + 7x + 6, as an example.
The correct answer, according to a cubic equation calculator website, is
First root = -0.87285
Second root = -0.00802 + 0.87391 i
Third root = -0.00802 - 0.87391 i
However, our result to this equation is :
First root = -0.87285
Second root = -0.2963 + 0.87391 i
Third root = -0.2963 + -0.87391 i
It is apparently noticeable that only parts of the second and third roots are wrong.
We have tried finding similar threads to help, but those are a little bit too difficult for us to understand or those problems are not the same as ours.
We look forward to finding the solution and the causes to this problem.
We have separated the formulas for finding the roots of a cubic equation into 5 parts.
(rootp1-rootp5)
The formulas are coded according to the formulas that can be found in the Chinese version of Wikipedia's page of Cubic equation.
(The formulas)
We have also rounded the real parts of the roots to 5 digits.
(Some code lines might be redundant, but as I have mentioned, we are new to coding)
Code (C#) :
...ANSWER
Answered 2022-Feb-05 at 18:50I admit I haven't tried your code, but you may have a casting issue in the math in your original calculations. Try this:
QUESTION
Looking into UTF8 decoding performance, I noticed the performance of protobuf's UnsafeProcessor::decodeUtf8
is better than String(byte[] bytes, int offset, int length, Charset charset)
for the following non ascii string: "Quizdeltagerne spiste jordbær med flØde, mens cirkusklovnen"
.
I tried to figure out why, so I copied the relevant code in String
and replaced the array accesses with unsafe array accesses, same as UnsafeProcessor::decodeUtf8
.
Here are the JMH benchmark results:
ANSWER
Answered 2022-Jan-12 at 09:52To measure the branch you are interested in and particularly the scenario when while
loop becomes hot, I've used the following benchmark:
QUESTION
i'm trying to write a shell script to analyse some videos by using the first frame of each second of video as a basis. i'm using ffmpeg to extract the frames. i thought i'd hit gold when this thread came up in my searches, but it doesn't handle the deinterlacing.
i'm using a time-based approach that works well for various formats as long as the video is progressive. it doesn't work so well for interlaced video (only the first field is output in that case, creating a half-height image). i've tried various combinations of deinterlacing (yadif/bwdif
) with select
but the filter chains i create either cause errors or still return a half-sized image.
here is my call w/a filter that works correctly for progressive video source :
ffmpeg -i $infile -vf "select='if(eq(n\,0),1,floor(t)-floor(prev_selected_t))" -vsync 0 $outfile
the following still return only half-height images for interlaced source :
... -vf "bwdif=0,select='if(eq(n\,0),1,floor(t)-floor(prev_selected_t))'"
... -vf "bwdif=0,select='between(mod(n\,$ips)\,1\,2)'"
-- $ips is images per second
... -vf "select='between(mod(n\,$ips)\,1\,2)',bwdif=0"
i've also tried various permutations of the above w/explicit frame reference (-r
, -vframes
, ...), still no joy.
can someone help me with the syntax ?
--EDIT--
here is the complete output of running the command with the first filter :
ANSWER
Answered 2021-Dec-22 at 04:45Your input is detected as interlaced but with half-height (288) and double the framerate (50). This may be due to missing or unrecognized boundary markers in the JPEG2000 packets. I assume this is meant to be PAL --> 720x576@25i.
Try using the tinterlace filter first to interleave the input "frames" to double-height and half fps, and then continue the original sequence of filters.
"tinterlace=mode=merge,bwdif=0,select='if(eq(n\,0),1,floor(t)-floor(prev_selected_t))'"
QUESTION
I'm trying to speed up a piece of code convolving a 1D array (filter) over each column of a 2D array. Somehow, when I run it with numba's njit
, I get a 7x slow down. My thoughts:
- Maybe column indexing is slowing it down, but switching to row indexing didn't affect performance
- Maybe slice indexing the results of the convolution is slow, but removing it didn't change anything
- I've checked that numba understands all the types properly
(tested on Windows 10, python 3.9.4 from conda, numpy 1.12.2, numba 0.53.1)
Can anyone tell me why this code is slow?
...ANSWER
Answered 2021-Dec-11 at 04:14The problem comes from the Numba implementation of np.convolve
. This is a known issue. It turns out that the current Numba implementation is much slower than the one of Numpy (version <=0.54.1 tested on Windows).
On one hand, the Numpy implementation call correlate
which itself performs a dot product that should be implemented by the fast BLAS library available on your system. On the other hand, the Numba implementation calls _get_inner_prod
which use np.dot
that should also use the same BLAS library (assuming a BLAS is detected which should be the case)...
That being said, there are multiple issues related to the dot product:
First of all, if the internal variable _HAVE_BLAS
of numba/np/arraymath.py
is manually disabled, Numba use a fallback implementation of the dot product supposed to be significantly slower. However, it turns out that using the fallback dot product implementation used by np.convolve
result in a 5 times faster execution than with the BLAS wrapper on my machine! Using additionally the parameter fastmath=True
in the njit
Numba decorator results in an overall 8.7 times faster execution! Here is the testing code:
QUESTION
I have a video that i need to hardcode subtitles for legacy devices so I usually use ffmpeg for this and it works fine but its so slow.
This is the command i usually use.
...ANSWER
Answered 2021-Dec-08 at 22:53For Handbrake, you use the veryfast preset.
You can also specify a preset with ffmpeg, by default it is set to medium but you can change:-preset veryfast
QUESTION
I intend to plot the following function:
...ANSWER
Answered 2021-Oct-14 at 13:43You can use sympy functions sympy.Function('cos')(x) and ('log')(x) and then lambdify. I didn't write down the exact function being too long but a simplified version works like this
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