collage | Generate Image Collage with PHP and Laravel | Computer Vision library
kandi X-RAY | collage Summary
kandi X-RAY | collage Summary
Create Image Collage with ease now with PHP. This package uses intervention/image package to leverage image manipulation. Using this package is very easy and creating Beautiful Collages are not tough anymore. NOTE: Currently this package only supports 4 images. You can write your own generator to add 5 if you like.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of collage
collage Key Features
collage Examples and Code Snippets
Lines of Code : 44License : Permissive (MIT)
Copyuse Tzsk\Collage\MakeCollage;
$collage = new MakeCollage($driver); // Default: 'gd'
$image = $collage->make(400, 400)->from($images);
// Add Padding:
$image = $collage->make(400, 400)->padding(10)->from($images);
// Add Background use Tzsk\Collage\Facade\Collage;
$image = Collage::make(400, 400)->from($images);
$image = Collage::make(400, 400)->from($images);
// Add Padding:
$image = Collage::make(400, 400)->padding(10)->from($images);
// Add Background Color:
use Tzsk\Collage\Contracts\CollageGenerator;
class FiveImage extends CollageGenerator
{
/**
* @param Closure $closure
* @return \Intervention\Image\Image
*/
public function create($closure = null)
{
// Your code to Community Discussions
Trending Discussions on collage
QUESTION
I am not interested how to set a wallpaper, because there are a lot of examples and documentation. Also for saving the wallpaper to the mobile gallery, or taking the photo paths from the gallery. I've already read about this. I am not finding a way to create different layouts (collages) to merge some images into a single image. I found the Image Collage Widget, but there is no documentation at all, and I don't know how to put manually the images instead of choosing from the gallery, to save the resulted collage etc.
...ANSWER
Answered 2022-Mar-21 at 13:43As of now there is no readymade solution for this but you can use staggered_grid_view to create collage & make custom collage layouts based on number of images selected for the collage. This is already covered in this link.
Also in this tutorial, it is shown how to put the images manually instead of choosing from the gallery & to save the resulted collage on local file storage.
QUESTION
I am trying to create a collage/montage of 15000 images using imagemagick montage command.The tool works perfectly for a small subset of the images but when trying to create a montage using 15K images the program crashes because it can't just load 15K images into main memory. I think opening the files in streams and then stacking in batches of 100 would work but if someone has a nice solution,it would be helpful.
...ANSWER
Answered 2022-Jan-27 at 23:23It's a bit late here to write and test anything, but I'd probably do something like this:
- generate a text file with all the filenames to montage
- use
splitcommand to break that into groups of 100 - iterate over all the groups making a row of images from each
- stack the rows
First part is like:
QUESTION
I want to add images from phone's photo library into a collage layout that I made. First I made the collage layout as a separate view in SwiftUI called CollageLayoutOne.
...ANSWER
Answered 2022-Feb-17 at 04:44image.itemProvider.loadObject is an asynchronous function, and it loads images one by one.
When the first image is processed, you add it to pickerResult and your pickerResult.isEmpty check becomes false, but your array contains only one item so far.
The safe thing to do here is to check the count:
QUESTION
This problem occurs in the Next.js project with Node version 17 I tried a lot of solutions but this solution is the best you can solve this problem if it occurred with you
...ANSWER
Answered 2022-Feb-08 at 12:19First, install cross-env
QUESTION
I have some code which generates collages from sets of photos, im doing this by averaging the pixels' colors of the images themselves and eventually, after a certain manipulation i just point(x,y) with the averaged color. The only problem is that when I zoom on retina screens (above certain resolution) it is very visible that this is indeed a bunch of points on the screen and not 1 complete image. I guess it has something to do with pixelDensity() but after a lot of experimentations with that, it didn't help as well.
attached here is an example of a zoomed crop -
The main loop which combines the pixels is very basic and looks like this -
...ANSWER
Answered 2022-Jan-29 at 21:53The point function is specifically going to draw a tiny round shape with a diameter equal to the pixelDensity. When you scale up the canvas either by CSS transform or by using your browsers zoom function you are going to start to see the sub-pixel artifacts of this. There are two ways to make sure your "points" of color are square and completely fill the plane even when zoomed in: 1) use the set() function to explicitly draw pixels, 2) use the square() or rect() functions to deliberately draw a square. (Theoretically you could also directly manipulate the pixels array, but this would be significantly more complicated).
Here is an example that demonstrates the original issue, as well as the different solutions.
QUESTION
So I recently started my studies on data structures and algorithms, specifically big O notation. I get the basics so far. As an exercise I wanted to determine the time complexity of an algorithm I wrote not too long ago.
My program uses PIL or pillow to make a contact sheet. Basically a collage of self.imageCount amount of images. I spent allot of time thinking on how to efficiently calculate the size that each image has to be in order to fit all of them on the sheet.
Finally I came up with this
I'll let the function speak for itself.
...ANSWER
Answered 2022-Jan-22 at 17:55Assuming, the aspect ratio of the sheet and the aspect ratio of the images are equal, the answer would be O(sheetHeight).
Let's consider the worst-case scenario. Let's assume for a moment that imageCount is very large, so much so that an image would have to shrink down to one pixel. Then, the number of times the while loop is executed would be equal to self.sheetHeight - 1. Therefore, the function would be O(sheetHeight).
It seems like in your case the aspect ratios are equal, but assuming they are not equal, then the answer is one of O(sheetHeight) or O(sheetWidth). Say for example the image width is 1/2 image height. Since 2/3 > 1/2, the limiting direction is the height (the height would hit the limit first). Then the answer would be O(sheetHeight).
Edit: For a Big O in terms of imageCount, consider the following:
For simplicity, I'll assume the aspect ratios of the sheet and image are the same.
Let's take imageHeight to be the required height of the image. Say imageCount = 100. Then imageHeight=sheetHeight/10.
Now, say we multiply imageCount by 4. Now the imageHeight would have to be sheetHeight/20. Thus, we can see that the image height is proportional to 1/sqrt(imageCount).
But, the time complexity is actually dependent on sheetHeight - imageHeight since that's the number of times the while loop would be executed. Thus, we can say that the solution is O(sheetHeight - imageHeight) = O(sheetHeight - sheetHeight/sqrt(imageCount)) = O(1 - 1/sqrt(imageCount)) (assuming sheetHeight is constant).
So, if we take n = imageCount, the solution is O(1-1/sqrt(n)). This explains why for large imageCounts, the solution approaches a constant time consumption.
QUESTION
I have conducted a large survey (consisting of 42 subsurveys for different treatments) and have trouble getting my data in shape.
I have ~ 16 000 answers, each answer (i.e. what is an alternative use for a newspaper) is a cell in a data frame. These answers are in the form of Data 1 (below).
Depending on how many times an answer is given, it is worth 0-6 points (the more points, the less people have thought of it, the more creative the answer). This list is identical in form to Data 2 (listed below).
Now I want to sum each row of each of the 42 surveys (=participant) according to the breakdown in Data 2. This score should be an extra column in the dataframe called "score".
Simple example:
Participant 1 answers: "schuhe", "basteln", ... => score = 1 + 0 points = 1
Participant 2 answers: "brennmaterial", "schiff", ... => score = 1 + 1 points = 2
So the code should do:
- If the string in cell x of Data 1 (e.g. "schuhe") matches a string in column 1 in Data 2 (here: "schuhe") (it always does, since data 2 is a table created out of data 1), pick the value corresponding to that matching string in data 2 of column "points", keep it in memory or assign to variable.
- Go to next cell in row, do step 1.
- If all columns of name "mycolumns" are done in one row, sum up the points.
- Write the sum of points in column "score" in data 1.
- Repeat for next row.
Data 1: The answers given in 1 of 42 surveys (snippet):
...ANSWER
Answered 2021-Dec-22 at 09:17if I've understood, then the values in d2$Var1 match up to all the column Q's in d1. If so I think this will work, where d1 is data 1 and d2 is data2
QUESTION
ANSWER
Answered 2021-Dec-20 at 17:33QUESTION
I want to initialize two Collage objects, would it be feasible by creating them with threads and if so how? I want to create two collages and then call 2-stitch on them individually in different threads and in the end combine their modified images in a new image vector for a new collage. This is my .h file of the collage
...ANSWER
Answered 2021-Dec-16 at 11:14It looks like you are trying to call the member function Collage::twoStitch on the instances subCollage1 and subCollage2 - but Collage::twoStitch needs a bool argument which you do not provide. Also, to call a member function, you need to provide a pointer to the instance.
Example:
QUESTION
In summary, I have 100k lines of data as a csv file. Here is sample of it:
ID,Name,Surname,Birthdate,Details
0, Agjqyru, Qtltzu, 1923-02-23, "{City=Neftchala, Gender=male, Education=collage}"
1, Zkaczi, Gvuvwwle, 2002-02-28, "{City=Mingachevir, Gender=female, Education=doctor}"
2, Hkbfros, Llmufk, 1948-02-29, "{City=Ujar, Gender=male, Education=collage}"
3, Dddtulkeo, Fdnccbp, 1903-07-01, "{City=Dashkasan, Gender=female, Education=bachelor}"
4, Wssqm, Kzekihhqjmrd, 1935-05-10, "{City=Baku, Gender=female, Education=uneducated}"
5, Iurg, Nglzxwu, 1915-04-02, "{City=Khojavend, Gender=male, Education=school}"
My task is to divide details column to 3 separate columns and save data as parquet file. Here is my attempt so far:
...ANSWER
Answered 2021-Nov-27 at 16:10The error is because of below code.
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