XDiFF | Extended Differential Fuzzing Framework
kandi X-RAY | XDiFF Summary
kandi X-RAY | XDiFF Summary
XDiFF is an Extended Differential Fuzzing Framework built for finding vulnerabilities in software. It collects as much data as possible from different executions an then tries to infer different potential vulnerabilities based on the different outputs obtained. The vulnerabilities can either be found in isolated pieces of software or by comparing:. The fuzzer uses Python and runs on multiple OSs (Linux, Windows, OS X, and Freebsd). Its main goal is to detect issues based on diffential fuzzing aided with the extended capabilities to increase coverage. Still, it will found common vulnerabilities based on hangs and crashes, allowing to attach a memory debugger to the fuzzing sessions.
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Top functions reviewed by kandi - BETA
- Start fuzzer
- Get testcases from fuzz_testcase
- Removes temporary files
- Get the latest test case
- Stop the Web Server
- Count the number of testcases
- Lists the summary statistics
- Return the number of testcase results
- This function is used for debugging
- Print a single CSV row
- Print help
- Load settings
- Get the value for a given constant
- Get the software id for the given piece
- Define software
- Generate testcases
- Print a table
- Perform a POST request
- Given a list of testcases return a list of testcases
- Stops the Web Server
- Perform a GET request
- Help for xdiff
- Migrate from from fromdb todb
- Analyze the output
- Insert a table into the database
- Remove temporary files
- Run a subprocess
- Dump the results of a database
- Delete unused testcases
XDiFF Key Features
XDiFF Examples and Code Snippets
Community Discussions
Trending Discussions on XDiFF
QUESTION
Sorry for the bad phrasing of the question!
I created a function, abc, and it works fine with my data table, DT, by itself.
...ANSWER
Answered 2022-Feb-18 at 20:28sapply
iterates only over the first argument provided, so you would need to change the function call to something like:
QUESTION
I have an R function that calculates the Hamming distance of two vectors:
...ANSWER
Answered 2022-Feb-17 at 23:04If dim(M1)
and dim(M2)
are identical, then you can simply do:
QUESTION
I want to swipe between pages in angular using native events and rxjs. I found this and changed my code to work with rxjs:
...ANSWER
Answered 2022-Jan-26 at 17:11Usage of the pairwise()
operator is wrong here. Based on your expected emission [touchstartEvent, touchendEvent]
, the pairwise()
isn't doing what you think it's doing. The actual values getting emitted are [touchmove[0], touchmove[1]]
.
I'd propose the following
Use
zipWith
operator to mergetouchstart
andtouchend
and ignore thetouchmove
if it's value isn't required.Using
return
inside the subscription callback to stop the further execution doesn't look elegant to me. You could instead flip the condition of theif
statement.
QUESTION
I have two closed QPolygonFs and I need to find out whether their edges (that is their contours) intersect. As these polygons may be included in one another, looking simply at the intersection of the polygons does not work.
PyQt5 has a built-in function for checking if a point is on the contourline of the polygon, contains(QPointF(x,y)). Thus, it seemed obvious to use this method for each point in the QPolygonF:
...ANSWER
Answered 2021-Dec-04 at 01:15Use QPolygonF.intersected
to get the intersection of the two polygons. Assuming both polygons are closed as you said, if one is fully contained inside the other then the returned intersection polygon will be equal to the smaller one. So you can check that it does not equal either of the given polygons.
QUESTION
I need to change the XML file where peci:Organization is a repeated child node. I need to make change that if is present in file for an employee.
I have been trying below code:
...ANSWER
Answered 2021-Nov-24 at 23:11You can do this by simply using two "replace" templates:
QUESTION
I am trying to write a program where it takes the X-Y Coordinates and Radii of 2 Circles from the User. Then, it would determine if the 2 Circles intersect or is contained in one another.
For the contain() function, when I tried printing out the values of c1.x and c2.x, only c1.x appears to give me the user input while c2.x prints out a very large number that has no meaning for me. Why can't I retrieve my user input for c2.x? Thank you
...ANSWER
Answered 2021-Oct-31 at 10:49You have a few problems with argument passing for the intersect
function and some other problems with the format specifier for printf
.
Try something like that:
QUESTION
I have a large background image and some much smaller images for the user to drag around on the background. I need this to be efficient in terms of performance, so i'm trying to avoid libraries. I'm fine with drag 'n' drop if it work's well, but im trying to get drag.
Im pretty much trying to do this. But after 8 years there must be a cleaner way to do this right?
I currently have a drag 'n' drop system that almost works, but when i drop the smaller images, they are just a little off and it's very annoying. Is there a way to fix my code, or do i need to take a whole different approach?
This is my code so far:
...ANSWER
Answered 2021-Sep-27 at 13:58QUESTION
I made a lightbox that runs on Javascript and I recently added a function where swiping left or right on mobile changes the image that appears. However, the code I'm using triggers the function every time my finger moves a few pixels. I want the function to trigger exactly one when I swipe once, no matter the length of the swipe. Here's my current code:
...ANSWER
Answered 2021-Aug-11 at 09:09You could use the touchend
event and split the handleTouchMove
handler in two handlers (+f.e. handleTouchEnd
). For that you need to define xDiff
and yDiff
globally.
QUESTION
I have a List of LocalDate objects (dates
) and I want to find the entry in the list that is closest to a given date (milestoneDate
).
Closest means that the date could be before or after milestoneDate
but it has the least difference. For example something the day before milestoneDate
would be closer than something 2 days after milestoneDate
.
So far the best idea I have is to convert the values in dates
toEpochSecond and then get the absolute value for the difference between that value and the toEpochSecond
of milestoneDate
and select the min value.
ANSWER
Answered 2021-May-31 at 08:55You can find the number of days between the milestone date and each of the dates in the list directly. There is no need to convert to an epoch second.
QUESTION
I am learning HTML canvas and choose to make Tetris game as the first project I have completed the game by watching a few tutorials. But want to make it better by adding a live preview where the Tetromino land on the page can anyone help how can I do that? By preview I mean How can I show the player where the piece land on gameArea.
The Html File:
...ANSWER
Answered 2021-May-15 at 13:11It is funny to answer my own question but, I found my answer in my dreams so let me put it here so if anyone wants to know the answer get helped Because,
That's what the community do.
so let's not waste any more time.
check how the game looks after the edit
SO first I created a new prototype function called shadow then check for where the tetromino collides using a for-loop return the for loop instance(where the Tetromino collides) minus 1. because we want to draw the shadow 1 step before the collision like this
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install XDiFF
You can use XDiFF like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
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