nevermind | Clean DQN implementation | Machine Learning library
kandi X-RAY | nevermind Summary
kandi X-RAY | nevermind Summary
Implementation of the original Deep Q-network algorithm from Mnih et al. 2015.
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Top functions reviewed by kandi - BETA
- Train a DeepQNetwork
- Plot training summaries
- Linearly decay function
- Save a matplotlib figure
- Adds an experience to this experiment
- Compute all greedy actions
- Train a model
- Train cartpole training
- Plot a cartpole value function
- Create a callback for saving cartpole - value plot
- Returns a function that returns True if the average returns is greater than the given minimum
- Update the model
- Update the target model
- Train a forest
- Reset the environment
- Creates a function that saves the last return value if it is improved
- Train the lunar lander
- Perform a step
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Trending Discussions on nevermind
QUESTION
I'm brand new to programming using classes. I want to create a method that takes only one class variable and have no idea if it's even possible, nevermind how to do it. My code is working fine but it seems that there should be a more elegant solution. As you can see in the code below, the same code is virtually repeated with the main difference being whether it's "player_pieces" or "pc_pieces" being examined. So I wanted to create a separate method but I have no idea how to single out a class variable to pass to it.
The code below is finding the highest doubles in either the players or the pc's pieces.
...ANSWER
Answered 2022-Jan-31 at 14:43First of all, you can place the repetitive code in a separate function.
Secondly, I would also change the for
loop to a while
loop - where the loop exits if double_in_hand
is True
(or if we finished running on all the doubles
).
You can also make the double_in_hand
variable - part of an instance of the class (as it does represent part of the object's state). Then you can just initialize it to False
before the loop, and update it to True
if the condition is met.
You can also set the status
variable inside of the other function, as that logic is also repetitive:
QUESTION
EDIT: Nevermind, see answer below
There seems to be a ton of noise about this across the internet (yes, I've read all the stack overflows and github issues), but not much signal for my particular problem. Also, I'm new to docker, so possibly user error, but none of the obvious....
Here's what's happening:
- I've created a single node swarm for a pet project and have successfully logged in to both ghcr and docker hub.
- I've created a simple docker image based on the standard mysql image and published it as a private ghcr package
- I've created a docker context on my local machine pointing to the docker socket that I'm forwarding from the swarm node.
- Using that context, when I run
docker image pull ghcr.io/my-name/my-image:latest
, it works fine and pulls the image down to the swarm node. - I then remove the image and run
docker stack deploy -c test.yml test
(test.yml
included below) and it fails with "No such image: ghcr.io/my-name...."
It does appear to have something to do with authentication, but unclear exactly what.... I also tested with a public ghcr package and it worked fine, so the difference seems to be public vs private.
Here's what test.yml
looks like (sub my-name/my-image
in for any private ghcr package you have access to):
ANSWER
Answered 2022-Jan-22 at 16:45Total embarrassing facepalm - I seem to have gotten stuck in a web of false-negatives. In the end, it was as simple as adding --with-registry-auth
to my deploy command, which many people on the internet have said before. I had done that several times and it hadn't worked, so I thought it wasn't that, but for whatever reason, I tried it again and it seems to work now. My bad for cluttering up SO with duplicates.
For others, as @Chris Becke notes in the comment above, the full command would be:
QUESTION
EDIT BELOW
The current version of pytube does not work anymore. Youtube actually made a good way of preventing automated video downloads, shocker...
ANOTHER EDIT Nevermind, there is an easy bypass. In the pytube directory, there is a file called cipher.py. Currently, in pytube 11.0.2, the cipher file has a cipher class with an init function. In the function, there is a variable called regex. Make sure that it is assigned to re.compile(r"^$*\w+\W") and the problem will be fixed.
I am getting this error pytube.exceptions.RegexMatchError: __init__: could not find match for ^\\w+\\W\n
,
I get this error when I run:
...ANSWER
Answered 2022-Jan-20 at 14:21In the pytube directory, there is a file called cipher.py. Currently, in pytube 11.0.2, the cipher file has a cipher class with an init function. In the function, there is a variable called regex. Make sure that it is assigned to re.compile(r"^$*\w+\W") and the problem will be fixed.
QUESTION
I just learned about H3 and would like to basically get the "standard reference" point, referencing each hexagon (and the 12 pentagons) at each resolution, and then determine what the lat/lng coordinates are for each hexagon. How does this work?
The H3 grid is constructed on the icosahedron by recursively creating increasingly higher precision hexagon grids until the desired resolution is achieved. Note that it is impossible to tile the sphere/icosahedron completely with hexagons; each resolution of an icosahedral hexagon grid must contain exactly 12 pentagons at every resolution, with one pentagon centered on each of the icosahedron vertices.
The first H3 resolution (resolution 0) consists of 122 cells (110 hexagons and 12 icosahedron vertex-centered pentagons), referred to as the base cells. These were chosen to capture as much of the symmetry of the spherical icosahedron as possible. These base cells are assigned numbers from 0 to 121 based on the latitude of their center points; base cell 0 has the northern most center point, while base cell 121 has the southern most center point.
Each subsequent resolution beyond resolution 0 is created using an aperture 7 resolution spacing (aperture refers to the number of cells in the next finer resolution grid for each cell); as resolution increases the unit length is scaled by sqrt(7) and each hexagon has 1/7th the area of a hexagon at the next coarser resolution (as measured on the icosahedron). H3 provides 15 finer grid resolutions in addition to the resolution 0 base cells. The finest resolution, resolution 15, has cells with an area of less than 1 m2.
I would like to go down to resolution 10, which is about 15m^2 area. I would like to store a custom generated key with each hexagon at this resolution, associating the key with the index or hash of the hexagon, which I assume is somehow associated to the origin of the system, and somehow the origin is hardcoded to a specific place on the globe.
So it appears that h3.getRes0Indexes
will give us the 122 origin cells at base 0. And the hierarchy docs show in the JavaScript library how to traverse the resolutions at least.
ANSWER
Answered 2022-Jan-13 at 17:54where is the origin?
There is no single origin. The grid is based on a projection of a regular icosahedron onto the surface of the globe (using a spherical model).
Where is the part where it maps the stuff to the actual Earth globe? Is that hardcoded somehow in the codebase somewhere?
The orientation of the icosahedron is fixed relative to the Earth - you can see the center coordinates of each face here (these are, as you suggested, hardcoded in the codebase).
How do I know that when I use the library today, the 122 base hexagons I get from the API will have the same hash as the last time I used it?
All H3 indexes are stable - this is a function of the algorithm we use to create the index, and of the API guarantee we offer that we won't make any changes to the library that change cell indexes or geographic locations.
You can see more info on the methodology of the indexing function here.
QUESTION
Otherwise, I want their original value.
Basic desired outcome: For this example, type a name to see the result. Erase the name and I want it to say "[empty]" instead of the name (in the text below the field). If I type the name again it should show the name again.
I am using "span" in a larger program so I used it in this example just in case, regardless the result should be the same.
EDIT: nevermind, this is false. The result is not the same. I need it to work when "span" is in the declared variable.
I am having a huge issue here. if/else statements are not working and I have tried all variations of ternary arguments.
I got this working halfway by doing the following after declaring nameHere, however, it would not return to having the inputted name value when it was entered:
...ANSWER
Answered 2022-Jan-10 at 20:20Please run following snippet. Once you type a name, it will be printed in the result div, once you erase EMPTY will be shown instead.
QUESTION
I am trying to build a web scraper to get informations about some products and store them inside a database. I'm getting the HTML source code with Nightmare (because javascript code has to run on the server before the page content is created) then I'm parsing that source with Cheerio. Once I do the parsing there are some images I have to download for the products. I have a simple download function and, based on if the image which I'm trying to download is available or not on the server, I'd like to return a string (or an array of strings) containing either the image name (which I downloaded) or a default image name from my computer. I tried calling the download function as a promise, I tried passing Promise.all() when I know there are multiple images to download, but to no avail. While I'm positive my code is working (the images are downloaded as should, the final object looks great at almost every property and value), it is the images properties fields which, when I'm printing the object to the console, still holds [Promise] / [ Promise { } ] and I'm not quite sure how to solve this matter. I'm positive those promises resolve, but they're not resolved when I'm outputting the resulting object to the console. And that's a problem, 'cause I have to pass that object to be stored in the database and I don't think they'll be resolved then.
The code (minus the exact links) is down below:
...ANSWER
Answered 2022-Jan-04 at 23:40You are getting an array of Promises returned by the map() method, so you will need to use Promise.all() or one of its variants.
For example, here you get the array of promises of "images", then you use Promise.all() to wait for all promises to be resolved, and finally you chain a then() to use the values.
QUESTION
I can't seem to figure out how to align in Jetpack Compose. Here's what I want it to look:
Now I tried the following, but it does not work as expected: Nevermind the exact colors btw, I'm only really interested in the concept of how to position those views, each rotated 90 degrees, and aligned to the edges of the Tablet in my case
...ANSWER
Answered 2021-Dec-23 at 02:09Modifier.fillMaxSize()
makes all your items as big as the parent, and as they're placed inside aBox
container - only the top one will be visible. This modifier isn't needed for such layout.By applying
contentAlignment = Alignment.CenterStart
, you're layoutBox
children views, e.g. your text. Instead you need to align the item relative to parent container, which can be done withModifier.align(Alignment.CenterStart)
Modifier.rotate
won't change the view position, so you need to manually update it after rotation. To understand what's going on, you can run the following code:
QUESTION
I have a class that looks like this:
...ANSWER
Answered 2021-Dec-20 at 15:22Just needed to add OuterClass.s = s
in the setUp()
.
I also introduced an issue where I used PowerMockito.mockStatic(Outerclass.class)
which was causing my static logger to become null. I removed this line.
QUESTION
I'm trying to save my arguments and their parameters from the command line as follows
./run cat hello.txt : grep left : wc -c
I want to seperate each argument in an array as follows withouth knowing the number of :
ANSWER
Answered 2021-Dec-08 at 01:13Allocate an array of pointers dynamically with malloc()
. There can be at most argc/2
commands, since the worst case is alternating word : word : word : ...
, so allocate that many elements. The array elements can point to the elements of argv
, and you can replace the :
argument with a null pointer to end each subcommand.
QUESTION
I need to do the following:
...ANSWER
Answered 2021-Dec-06 at 17:17You can filter out all rows which have a pkey_ip_range
that's already contained by an existing pkey_ip_range
:
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