eval_expr | Nspire CX II python library to evaluate TI | Apps library
kandi X-RAY | eval_expr Summary
kandi X-RAY | eval_expr Summary
A TI-Nspire CX II python library to evaluate arbitrary TI-Basic expressions.
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- Cleans the string .
- Evaluate the given expression .
- Return number if possible .
- Evaluate a thing .
- Call function with pyargs
eval_expr Key Features
eval_expr Examples and Code Snippets
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Trending Discussions on eval_expr
QUESTION
ANSWER
Answered 2022-Mar-05 at 00:22The type checker is warning you that your dictionary that maps AST node types for operators to their implementations is incomplete. The type checker knows all of the possible types of node.op (which it seems to be describing as subtypes of the ast.operator and ast.unaryop parent types), and has noticed that your dictionary doesn't handle them all.
Since there are operators that you haven't included, it's possible for a parsable expression (like, say "2 << 5" which does a left shift, or "~31" which does a bitwise inversion) to fail to be handled by your code.
While I don't use PyCharm and thus can't test it for myself, you can probably satisfy its type checker by adding some error handling to your code, so that operator types you don't support will still be dealt with appropriately, rather than causing an uncaught exception (such as a KeyError from the dictionary) to leak out. For instance, you could use OPERATORS.get(type(node.op)) and then test for None before calling the result. If the operator type isn't in the dictionary, you'd raise an exception of your own.
QUESTION
I'm trying to implement an extension for the list operations. It checks whether a list is empty or not; if the argument is not a list it should produce an error. I handle the error propagation in the backend with (>>=) function. The empty function I implemented below first checks the value whether is a list using a helper function (list_of_listVal). Then if the list is empty returns true, else returns false. The corresponding code is shown below:
...ANSWER
Answered 2021-Oct-16 at 21:41The problem is that you're destructuring the list into its head and tail (or first element and the rest of the list, respectively), which of course assumes that there is at least one element in the list, hence the warning and the exception when an empty list is encountered.
What do you expect v1 and v2 to be here, when given the empty list?
Furthermore, you're then putting the head and tail together again in the exact same way, without using it in any other way, before comparing it against the empty list. Which can never be true, because you've just constructed a list with at least one element.
The solution then, is to simply not destructure and then immediately reassemble the list. Replace v1::v2 with vs (or any other identifier of your choice). There's also no need to wrap the lists in ListVal, as it's just more indirection.
QUESTION
The relevant function (not everything shown) is
...ANSWER
Answered 2021-Apr-23 at 00:16The token val is a keyword in OCaml. You just need to change to a different name. I often use valu.
QUESTION
Below is the question I am trying to solve. I am a novice python3 learner and tried below mentioned approach. I am unable to figure out why the second for loop prints "test4" as well and throwing exceptions/errors while I was expecting only "test0" during the last iteration. I am sure there must be many easy ways to solve this problem but I would like to know why it's happening like this with my piece of code? Can someone please explain to me what I am doing wrong? Thanks in Advance!!
Question:
Given an arithmetic expression in Reverse Polish Notation, write a program to evaluate it.
The expression is given as a list of numbers and operands. For example: [5, 3, '+'] should return 5 + 3 = 8.
For example, [15, 7, 1, 1, '+', '-', '/', 3, '*', 2, 1, 1, '+', '+', '-'] should return 5, since it is equivalent to ((15 / (7 - (1 + 1))) * 3) - (2 + (1 + 1)) = 5.
You can assume the given expression is always valid.
Code:
...ANSWER
Answered 2021-Feb-22 at 13:11As you'd expect last iteration prints test0 only.
test4 prints that the statement is coming from the very first call of the eval_expr() function.
Since this is a recursive call when you reach the last iteration the program tries to complete the remaining iteration.
(last_iteration -1), (last_iteration -2), (last_iteration -3)... until the very first call.
When you called the j for-loop for the first time input_list_copy would have had value:
[15, 7, 2, '-', '/', 3, '*', 2, 1, 1, '+', '+', '-'].
So the j for-loop would have been set to execute 13 times.
The recursive call of the eval_expr() function started when it reaches '-' (j=3) in input_list_copy.
After completing all recursive function calls the control goes to first j for-loop call where it is set to execute 13 times.
when the 4th iteration started it prints "test4" statement, but by this time input_list_copy list is being updated as a single member list.
So when you try to access element that is not available in input_list_copy you get: IndexError: list index out of range.
QUESTION
Given the following code:
...ANSWER
Answered 2020-Dec-02 at 21:40The init callback should return {ok, SomeState}. In your case the return value of init is the return value of io_lib:print()
QUESTION
so I'm making a programming language using python and the lark library for parsing. When I'm parsing the following
ANSWER
Answered 2020-Nov-14 at 14:41I'm not familiar with lark, but this looks wrong:
QUESTION
for example this random(-1) in geq:
ANSWER
Answered 2020-Oct-08 at 11:28It uses a linear congruential generator with multiplier 1664525 and increment 1013904223.
You can of course modify it to suit your needs. Check out av_get_random_seed for more sources of randomness.
QUESTION
I am trying to start a supervisor of type one_for_one with one child and am getting this error:
ANSWER
Answered 2020-Mar-01 at 16:55The second argument of start_link with 3 arguments is supposed to be the module name; it should be
QUESTION
#split the equation into 2 parts using the = sign as the divider, parse, and turn into an equation sympy can understand
equation = Eq(parse_expr(.split("=")[0]), parse_expr(.split("=")[1]))
answers = solve(equation)
#check for answers and send them if there are any
if answers.len == 0:
response = "There are no solutions!"
else:
response = "The answers are "
for answer in answers:
response = response + answer + ", "
response = response[:-2]
await self.client.send(response, message.channel)
ANSWER
Answered 2020-Jan-07 at 18:08parse_expr allows flexible input via its transformations= parameter.
The implicit_multiplication_application allows among others to leave out the * when a multiplication can be presumed. Very often, people also want ^ for powers, while Python standard uses ** for power and reserves ^ for exclusive or. The transformation convert_xor takes care of that conversion.
Here is an example:
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Install eval_expr
Transfer it to your calculator, in the PyLib folder.
Enjoy!
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