Cup | Sublime Text 3 plugin to enhance your CoffeeScript | Plugin library
kandi X-RAY | Cup Summary
kandi X-RAY | Cup Summary
A Sublime Text 3 plugin to enhance your CoffeeScript 2 experience
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Top functions reviewed by kandi - BETA
- Run the tool
- Run command
- Run a shell command
- Returns true if the current view is a literal literal
- Fix imports
- Start a daemon process
- Return an error message for the given executable
- Prompt the user to resolve imports
- Run the editor
- Runs a brew process
- Sorts the view
- Return the import region
- Sorts imports
- Returns the import code of the given code
- Run selection
- Called when a view has been modified
- Put text into the window
- Runs the script
- Run snippet
- Stop the watcher
- Run Coffeelint
- Finish a task
- Execute compile on save
- Creates output tab
- Run editor
- Start the view
Cup Key Features
Cup Examples and Code Snippets
const groupBy = (arr, fn) =>
arr
.map(typeof fn === 'function' ? fn : val => val[fn])
.reduce((acc, val, i) => {
acc[val] = (acc[val] || []).concat(arr[i]);
return acc;
}, {});
groupBy([6.1, 4.2, 6.3], Math.floor)
from datetime import timedelta, date
def days_ago(n):
return date.today() - timedelta(n)
days_ago(5) # date(2020, 10, 23)
const hasDecimals = num => num % 1 !== 0;
hasDecimals(1); // false
hasDecimals(1.001); // true
def volume_conversion(value: float, from_type: str, to_type: str) -> float:
"""
Conversion between volume units.
>>> volume_conversion(4, "cubicmeter", "litre")
4000
>>> volume_conversion(1, "litre", "gallon")
Community Discussions
Trending Discussions on Cup
QUESTION
I have the following dictionary:
...ANSWER
Answered 2022-Mar-27 at 19:10file.write(str(sorted_dict)
QUESTION
I'd like to create a df that has a header and a subheader. Example below:
I want to take the following input:
...ANSWER
Answered 2022-Jan-19 at 18:17library(tidyverse)
input %>%
pivot_longer(-Region) %>%
na.omit() %>%
group_by(Region, name) %>%
mutate(id = row_number()) %>%
pivot_wider(names_from = id, values_from = value) %>%
data.table::transpose(make.names = TRUE)
Central Central Central Pacific Pacific Pacific Eastern Eastern Eastern
1 Day_1 Day_2 Day_3 Day_2 Day_1 Day_3 Day_1 Day_2 Day_3
2 Boat Shoe Table Boat Table Shoe Boat Shoe Table
3 Watch Cup
4 Chair
QUESTION
my state orderDetail contain orderDetail json
I am getting the _id of the order which I want to delete in function eg _id: 60f1ab20891ced4818b5ea87,
now I want to remove this order from the orders array which is in orderdetail and update the state.
...ANSWER
Answered 2022-Jan-10 at 06:01What you need to so is set a new object with the orders
array filtered as well as a new totalPrice
.
For example
QUESTION
I've created a small dataset comparing coffee drink prices per cup size.
When I pivot my dataset the output automatically reorders the index (the 'Size' column) alphabetically.
Is there a way to assign the different sizes a numerical level (e.g. small = 0, medium = 1, large = 2) and reorder the rows this way instead?
I'm know this can be done in R using the forcats library (using fct_relevel for example), but I'm not aware of how to do this in python. I would prefer to keep the solution to using numpy and pandas.
...ANSWER
Answered 2021-Nov-30 at 18:13You can use a Categorical
type with ordered=True
:
QUESTION
I have a single list that looks like this
...ANSWER
Answered 2021-Nov-21 at 21:49Get the 'comparator' objects in a list
, use %in%
to return a logical vector by comparing the elements with 'main.list', convert to proportion with mean
, and stack
the key/value pair to a data.frame
with two columns
QUESTION
I have the following snowflake query where I am getting a divide by zero error...Can you please help me here..
...ANSWER
Answered 2021-Oct-13 at 11:23I assume that this happens due to the /sum(iff(iscode=1,1,0))
where this presumably sometimes returns 0.
One aproach to deal with division by zero is to use NULLIF
QUESTION
I'm trying to make a boxplot where my MFR (manufacturers) are displayed on the x axis and the rating is on the y axis. However I want to color the different boxplots based on the mean shelf value. (Shelf is a value between 1 and 3)
I tried this code:
...ANSWER
Answered 2021-Sep-28 at 08:49ggplot2
QUESTION
FilterCriterias: any = []
public productChanged(filterValue: any) {
if(this.FilterCriterias?.length == 0) {
this.FilterCriterias.push({
filtercolumnName: 'productType',
filterValueList: [filterValue.name]
})
} else {
this.FilterCriterias.forEach((elem: any, index: number) => {
if(elem.filtercolumnName == 'productType') {
const idx = elem.filterValueList.indexOf(filterValue.name)
if(idx >= 0) {
elem.filterValueList.splice(idx, 1)
// if (elem.filterValueList?.length == 0 && elem.filtercolumnName == 'productType') {
// const idy = elem.filtercolumnName.indexOf('productType')
// if (idy > 0) {
// this.FilterCriterias.splice(idy, 1)
// }
// }
} else {
elem.filterValueList.push(filterValue.name)
}
} else {
this.FilterCriterias.push({
filtercolumnName: 'productType',
filterValueList: [filterValue.name]
})
}
});
}
this.FilterCriterias.forEach((element: any) => {
if(element.filterValueList.length == 0 && element.filtercolumnName == 'productType') {
console.log(true);
const idy = element.filtercolumnName.indexOf('productType')
console.log(idy);
}
});
// removing the duplicates
var filtered = this.FilterCriterias.reduce((filtered: any, item: any) => {
// console.log(item);
if(!filtered.some((filteredItem: any) => JSON.stringify(filteredItem.filtercolumnName) == JSON.stringify(item.filtercolumnName)))
filtered.push(item)
return filtered
}, [])
console.log('filtered',filtered);
}
public collectionChanged(filterValue: any) {
if(this.FilterCriterias?.length == 0) {
this.FilterCriterias.push({
filtercolumnName: 'collections',
filterValueList: [filterValue.name]
})
} else {
this.FilterCriterias.forEach((elem: any, index: number) => {
if(elem.filtercolumnName == 'collections') {
const idx = elem.filterValueList.indexOf(filterValue.name)
if(idx >= 0) {
elem.filterValueList.splice(idx, 1)
// if(elem.filterValueList?.length == 0) {
// const idy = elem.filtercolumnName.indexOf('collections')
// console.log('collectoinindex',idy);
// if(idy > 0) {
// this.FilterCriterias.splice(idy, 1)
// }
// }
} else {
elem.filterValueList.push(filterValue.name)
}
} else {
this.FilterCriterias.push({
filtercolumnName: 'collections',
filterValueList: [filterValue.name]
})
}
});
}
this.FilterCriterias.forEach((element: any) => {
if(element.filterValueList.length == 0 && element.filtercolumnName == 'collections') {
console.log(true);
const idy = element.filtercolumnName.indexOf('collections')
console.log(idy);
}
});
// removing the duplicates
var filtered = this.FilterCriterias.reduce((filtered: any, item: any) => {
// console.log(item);
if(!filtered.some((filteredItem: any) => JSON.stringify(filteredItem.filtercolumnName) == JSON.stringify(item.filtercolumnName)))
filtered.push(item)
return filtered
}, [])
console.log('filtered',filtered);
}
...ANSWER
Answered 2021-Sep-13 at 07:38I am guessing this should do the job if I understood correctly what you want to do. This will loop through all objects of the array, check if their filterValueList array is empty and if so, it will remove them from the array:
QUESTION
I am learning python and working on a sample Kaggle dataset and trying to split comma-separated values in a column into different columns using python or pandas in jupyter notebook.
For instance :
column_A
Garbage: Tissues, Organics: Milk, Recycle: Cardboards
Garbage: Paper Towels, Organics: Eggs, Recycle: Glass, Junk: Feces
Garbage: cups, Recycle: Plastic bottles
I want to split these into different columns based on commas, like below:
Garbage Organics Recycle Junk Tissues Milk Cardboards Null Paper Towels Eggs Glass Feces Cups Null Plastic bottles NullI've tried using Lambda functions but it only worked if there is same length of comma separated strings but not for unequal length and displaying an index error "list index out of range". The code I've used is below:
...ANSWER
Answered 2021-Sep-17 at 18:39We can use a regular expression pattern to find all the matching key-value pairs from each row of column_A
, then map
the list of pairs from each row to dictionary in order to create records then construct a dataframe from these records
QUESTION
I have a df like this one:
...ANSWER
Answered 2021-Jul-14 at 23:18Try:
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install Cup
You can use Cup like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
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