eggo | Ready-to-go Parquet-formatted public 'omics datasets
kandi X-RAY | eggo Summary
kandi X-RAY | eggo Summary
Eggo is two things:. Eggo includes all the of scripts for processing the data, including the necessary DDL statements to register the data sets with the Hive Metastore and make them accessible to Hive/Impala. At the moment, Eggo is geared specifically towards scaling up variant stores and related functionality (e.g., population genomics, clinical genomics).
Support
Quality
Security
License
Reuse
Top functions reviewed by kandi - BETA
- Downloads a dataset using hdfs
- Create a temporary temporary directory
- Generate a UUID4
- Create a temporary directory
- Context manager for tunnel
- Creates a non blocking tunnel
- Sleep in progress
- Reset the status of a cm
- Generate XML elements
- Get s3 properties
- Get the AWS access key ID
- Get an environment variable
- Convert a URI to a filename
- Sanitize a string
- Generates eggo environment variables
- Get cluster info
- Update an XML file
- Dump the contents of the elements
- Return the content of the README md file
- Update core site - site configuration
- Get the EC2 private key file
- Get EC2 key pair
- Returns the directory of the resources
- Return AWS Secret access key
eggo Key Features
eggo Examples and Code Snippets
Community Discussions
Trending Discussions on eggo
QUESTION
So I've been studying this concept of length extension attacks and there are few things that I noticed during my study about it which are not very bright to me.
1.Research papers are explaining how you can append some type of data to the end and make newly formed data. For example
Desired New Data: count=10&lat=37.351&user_id=1&long=-119.827&waffle=eggo&waffle=liege
(notice 2 waffles). My question is if a parser function on the server side can track duplicate attributes, could then the entire length extension attack be nonsense? Because the server would notice duplicate attributes. Is a proper parser that is made to check any duplicates a good solution versus length extension attacks? I'm aware of HMAC approach and other protections, but specifically talking just about parsers here now.
2.Research says that only vulnerable data is H(key|message). They claim that H(message|key) won't work for the attacker because we would have to append a new key (which we obviously don't know). My question is why would we have to append a new key? We don't do it when we are attacking H(key|message). Why can't we rely on the fact that we will pass the verification test (we would create the correct hash) and that if the parser tries to extract the key from it, that it would take the only key in the block we send out and resume from there? Why would we have to send 2 keys? Why doesn't attack against H(message|key) work?
...ANSWER
Answered 2021-Feb-25 at 11:25
- My question is if a parser function on server side can track duplicate attributes, could then the entire length extension attack be a nonsense? You are talking about a well-written parser. Writing software is hard and writing correct software is very hard.
In that example, you have seen an overwritten attribute. Are you able to say that a good parser must take the last one or the first one? What is the rule? There can be stations that the last one must be taken! That is an attack that can be applied or not. This depends on the station. If you consider that the knowledge of the length extension attack goes back to 1990s, then finding a place applicable to this should amaze someone!. And, it is applied in the wild to Flickr API in 2009, after almost 20 years;
- My question is why would we have to append new key? We don't do it when we are attacking H(key|message). Why can't we relay on the fact that we will pass verification test (we would create correct hash) and that if parser tries to extract key from it, that it would take the only key in the block we send out and resume from there. Why would we have to send 2 keys? Why doesnt attack against H(message|key) work?
The attack is a signature forgery. The key is not known to the attacker, but they can still forge new signatures. The new message and signature - extended hash - is sent to the server, then the server takes the key and appends it to the message to execute a canonical verification, that is; if it does the signature is valid.
The parser doesn't extract the key, it already knows the key. The point is that can you make sure that the data is really extended or not. The padding rule is simple, add 1
and fill many zeroes so that the last 64 (128) is the length encoding (very simplified, for example, the final length must be multiple of 512 for SHA256). To see that there is another padding inside you must check every block and then you may claim that there is an extension attack. Yes, you can do this, however, the one of aims of cryptography is to reduce the dependencies, too. If we can create a better signature that eliminates the checking then we suggest to left the others. This enables the software developers to write more secure implementation easily.
Why doesn't attack against H(message|key) work?
Simple, you get the extended message message|extended
and send the extended hash
H(message|key|extended)
to the server. Then the server takes the message message|extended
and appends the key message|extended|key
and hashes it H(message|extended|key)
and clearly this is not equal to the extended one H(message|key|extended)
Note that the trimmed version of the SHA2 series like SHA-512/256 has resistance to length extension attacks. SHA3 is immune to it by design and that enables a simple KMAC signature scheme. Blake2 is also immune since it is designed with the HAIFA construction.
QUESTION
ANSWER
Answered 2020-Dec-10 at 05:15You have used same instance for set item name. Change your viewDidLoad method.
QUESTION
I'm running a python script that will display messages on a board. One of the subroutines that I've created is supposed to grab a random line from a small text file, and display that line. It mostly works, except after looping a few times, it gets stuck on the same number, and just displays the same thing over and over.
I am running this in Python 2.7, on a Raspberry Pi in Raspbian. I am using this github as the base for the project, and added lines of my own to it: https://github.com/CalebKussmaul/Stranger-Things-Integrated This is part of a halloween display that will be Stranger Things-themed, so the preloaded messages have a reference to the show. I noticed this issue the other day, and have been pouring over the internet to try and figure out what the problem could be. I've tried doing different methods of selecting a randomized number, including some in some similar (but different) threads on this site. All of them produce exactly the same issue.
Below is the subroutine I created:
...ANSWER
Answered 2019-Oct-17 at 17:57This appears to work for me. Note that I'm seeding the RNG.
QUESTION
I'm trying to create an app with a table with 3 cells
I want to extend the UITableViewController rather than UIViewController, so I come up with this
...ANSWER
Answered 2018-Aug-01 at 14:15Well, actually the UITableViewController
expects that its' 'view' property is of type UITableView
. The easiest way to create one in storyboard is to use corresponding object from the collection (panel in the bottom right corner). In your case seems like you took UIViewController
from the collection and then just added UITableView
on it.
So you have two options now:
- Still the easiest way to fix this is to delete existing one and take
Table view controller
from the collection - Also you can delete the root view of the controller, put the table view on its' place and then connect it to the
view
property of your controller. And don't forget to also connect delegate and data source of your table view in this case
QUESTION
I am trying to replace every instance of the "id" with a random unique ID value.
Is there a way to replace all of them at once?
My code:
...ANSWER
Answered 2018-Jun-08 at 20:03Using ramda
to help with modifying the object, and cuid
to generate the unique ids:
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install eggo
AWS_ACCESS_KEY_ID
AWS_SECRET_ACCESS_KEY
EC2_KEY_PAIR -- the name of the EC2-registered key pair to use for instance authentication
EC2_PRIVATE_KEY_FILE -- the local path to the corresponding private key
Support
Reuse Trending Solutions
Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items
Find more librariesStay Updated
Subscribe to our newsletter for trending solutions and developer bootcamps
Share this Page