eggo | Ready-to-go Parquet-formatted public 'omics datasets

 by   bigdatagenomics Python Version: Current License: Apache-2.0

kandi X-RAY | eggo Summary

kandi X-RAY | eggo Summary

eggo is a Python library typically used in Big Data, Spark, Hadoop applications. eggo has no bugs, it has no vulnerabilities, it has build file available, it has a Permissive License and it has low support. You can download it from GitHub.

Eggo is two things:. Eggo includes all the of scripts for processing the data, including the necessary DDL statements to register the data sets with the Hive Metastore and make them accessible to Hive/Impala. At the moment, Eggo is geared specifically towards scaling up variant stores and related functionality (e.g., population genomics, clinical genomics).
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            kandi-support Support

              eggo has a low active ecosystem.
              It has 28 star(s) with 7 fork(s). There are 9 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 21 open issues and 84 have been closed. On average issues are closed in 55 days. There are 3 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of eggo is current.

            kandi-Quality Quality

              eggo has 0 bugs and 0 code smells.

            kandi-Security Security

              eggo has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              eggo code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              eggo is licensed under the Apache-2.0 License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              eggo releases are not available. You will need to build from source code and install.
              Build file is available. You can build the component from source.
              Installation instructions, examples and code snippets are available.
              eggo saves you 434 person hours of effort in developing the same functionality from scratch.
              It has 1028 lines of code, 93 functions and 16 files.
              It has high code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed eggo and discovered the below as its top functions. This is intended to give you an instant insight into eggo implemented functionality, and help decide if they suit your requirements.
            • Downloads a dataset using hdfs
            • Create a temporary temporary directory
            • Generate a UUID4
            • Create a temporary directory
            • Context manager for tunnel
            • Creates a non blocking tunnel
            • Sleep in progress
            • Reset the status of a cm
            • Generate XML elements
            • Get s3 properties
            • Get the AWS access key ID
            • Get an environment variable
            • Convert a URI to a filename
            • Sanitize a string
            • Generates eggo environment variables
            • Get cluster info
            • Update an XML file
            • Dump the contents of the elements
            • Return the content of the README md file
            • Update core site - site configuration
            • Get the EC2 private key file
            • Get EC2 key pair
            • Returns the directory of the resources
            • Return AWS Secret access key
            Get all kandi verified functions for this library.

            eggo Key Features

            No Key Features are available at this moment for eggo.

            eggo Examples and Code Snippets

            No Code Snippets are available at this moment for eggo.

            Community Discussions

            QUESTION

            Length extension attack doubts
            Asked 2021-Feb-25 at 11:25

            So I've been studying this concept of length extension attacks and there are few things that I noticed during my study about it which are not very bright to me.

            1.Research papers are explaining how you can append some type of data to the end and make newly formed data. For example

            Desired New Data: count=10&lat=37.351&user_id=1&long=-119.827&waffle=eggo&waffle=liege

            (notice 2 waffles). My question is if a parser function on the server side can track duplicate attributes, could then the entire length extension attack be nonsense? Because the server would notice duplicate attributes. Is a proper parser that is made to check any duplicates a good solution versus length extension attacks? I'm aware of HMAC approach and other protections, but specifically talking just about parsers here now.

            2.Research says that only vulnerable data is H(key|message). They claim that H(message|key) won't work for the attacker because we would have to append a new key (which we obviously don't know). My question is why would we have to append a new key? We don't do it when we are attacking H(key|message). Why can't we rely on the fact that we will pass the verification test (we would create the correct hash) and that if the parser tries to extract the key from it, that it would take the only key in the block we send out and resume from there? Why would we have to send 2 keys? Why doesn't attack against H(message|key) work?

            ...

            ANSWER

            Answered 2021-Feb-25 at 11:25
            1. My question is if a parser function on server side can track duplicate attributes, could then the entire length extension attack be a nonsense? You are talking about a well-written parser. Writing software is hard and writing correct software is very hard.

            In that example, you have seen an overwritten attribute. Are you able to say that a good parser must take the last one or the first one? What is the rule? There can be stations that the last one must be taken! That is an attack that can be applied or not. This depends on the station. If you consider that the knowledge of the length extension attack goes back to 1990s, then finding a place applicable to this should amaze someone!. And, it is applied in the wild to Flickr API in 2009, after almost 20 years;

            1. My question is why would we have to append new key? We don't do it when we are attacking H(key|message). Why can't we relay on the fact that we will pass verification test (we would create correct hash) and that if parser tries to extract key from it, that it would take the only key in the block we send out and resume from there. Why would we have to send 2 keys? Why doesnt attack against H(message|key) work?

            The attack is a signature forgery. The key is not known to the attacker, but they can still forge new signatures. The new message and signature - extended hash - is sent to the server, then the server takes the key and appends it to the message to execute a canonical verification, that is; if it does the signature is valid.

            The parser doesn't extract the key, it already knows the key. The point is that can you make sure that the data is really extended or not. The padding rule is simple, add 1 and fill many zeroes so that the last 64 (128) is the length encoding (very simplified, for example, the final length must be multiple of 512 for SHA256). To see that there is another padding inside you must check every block and then you may claim that there is an extension attack. Yes, you can do this, however, the one of aims of cryptography is to reduce the dependencies, too. If we can create a better signature that eliminates the checking then we suggest to left the others. This enables the software developers to write more secure implementation easily.

            Why doesn't attack against H(message|key) work?

            Simple, you get the extended message message|extended and send the extended hash H(message|key|extended) to the server. Then the server takes the message message|extended and appends the key message|extended|key and hashes it H(message|extended|key) and clearly this is not equal to the extended one H(message|key|extended)

            Note that the trimmed version of the SHA2 series like SHA-512/256 has resistance to length extension attacks. SHA3 is immune to it by design and that enables a simple KMAC signature scheme. Blake2 is also immune since it is designed with the HAIFA construction.

            Source https://stackoverflow.com/questions/66354748

            QUESTION

            My TableView only lists the last item in my itemArray?
            Asked 2020-Dec-10 at 11:46

            I have four items in my itemArray, but my TableView only lists my last appended item, and it lists it first. However, I can check and uncheck the three rows below the first row that actually has a text.

            ...

            ANSWER

            Answered 2020-Dec-10 at 05:15

            You have used same instance for set item name. Change your viewDidLoad method.

            Source https://stackoverflow.com/questions/65228818

            QUESTION

            Python random.randint stops randomizing after a few loops
            Asked 2019-Oct-17 at 17:57

            I'm running a python script that will display messages on a board. One of the subroutines that I've created is supposed to grab a random line from a small text file, and display that line. It mostly works, except after looping a few times, it gets stuck on the same number, and just displays the same thing over and over.

            I am running this in Python 2.7, on a Raspberry Pi in Raspbian. I am using this github as the base for the project, and added lines of my own to it: https://github.com/CalebKussmaul/Stranger-Things-Integrated This is part of a halloween display that will be Stranger Things-themed, so the preloaded messages have a reference to the show. I noticed this issue the other day, and have been pouring over the internet to try and figure out what the problem could be. I've tried doing different methods of selecting a randomized number, including some in some similar (but different) threads on this site. All of them produce exactly the same issue.

            Below is the subroutine I created:

            ...

            ANSWER

            Answered 2019-Oct-17 at 17:57

            This appears to work for me. Note that I'm seeding the RNG.

            Source https://stackoverflow.com/questions/58422686

            QUESTION

            UITableViewController loadView loaded the "xxx-view-xxx" nib but didn't get a UITableView
            Asked 2019-May-18 at 17:26

            I'm trying to create an app with a table with 3 cells

            I want to extend the UITableViewController rather than UIViewController, so I come up with this

            ...

            ANSWER

            Answered 2018-Aug-01 at 14:15

            Well, actually the UITableViewController expects that its' 'view' property is of type UITableView. The easiest way to create one in storyboard is to use corresponding object from the collection (panel in the bottom right corner). In your case seems like you took UIViewController from the collection and then just added UITableView on it.

            So you have two options now:

            1. Still the easiest way to fix this is to delete existing one and take Table view controller from the collection
            2. Also you can delete the root view of the controller, put the table view on its' place and then connect it to the view property of your controller. And don't forget to also connect delegate and data source of your table view in this case

            Source https://stackoverflow.com/questions/51634855

            QUESTION

            How can I replace every ID instance in a javascript Object
            Asked 2018-Jun-08 at 20:20

            I am trying to replace every instance of the "id" with a random unique ID value.

            Is there a way to replace all of them at once?

            My code:

            ...

            ANSWER

            Answered 2018-Jun-08 at 20:03

            Using ramda to help with modifying the object, and cuid to generate the unique ids:

            Source https://stackoverflow.com/questions/50767568

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install eggo

            Eggo makes use of Fabric, Boto, and Click.
            AWS_ACCESS_KEY_ID
            AWS_SECRET_ACCESS_KEY
            EC2_KEY_PAIR -- the name of the EC2-registered key pair to use for instance authentication
            EC2_PRIVATE_KEY_FILE -- the local path to the corresponding private key

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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            https://github.com/bigdatagenomics/eggo.git

          • CLI

            gh repo clone bigdatagenomics/eggo

          • sshUrl

            git@github.com:bigdatagenomics/eggo.git

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