Expression | Pragmatic functional programming for Python inspired by F | Functional Programming library
kandi X-RAY | Expression Summary
kandi X-RAY | Expression Summary
Expression aims to be a solid, type-safe, pragmatic, and high performance library for frictionless and practical functional programming in Python 3.8+. By pragmatic we mean that the goal of the library is to use simple abstractions to enable you to do practical and productive functional programming in Python (instead of being a Monad tutorial). Python is a multi-paradigm programming language that also supports functional programming constructs such as functions, higher-order functions, lambdas, and in many ways favors composition over inheritance. Better Python with F#.
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Top functions reviewed by kandi - BETA
- Rebalance a key - value pair .
- Post a message to the server .
- Applies a key to a map .
- Wrap a function with num_args .
- Combine two sequences .
- Fold fold_back function .
- Create a pipeline from a function .
- Returns a function that applies the given function to the given list .
- Decorator to catch an exception .
- Creates a function that returns the elements that satisfy the given predicate .
Expression Key Features
Expression Examples and Code Snippets
def _parse_lambda(lam):
"""Returns the AST and source code of given lambda function.
Args:
lam: types.LambdaType, Python function/method/class
Returns:
gast.AST, Text: the parsed AST node; the source code that was parsed to
genera
def regex_find(orig_screen_output, regex, font_attr):
"""Perform regex match in rich text lines.
Produces a new RichTextLines object with font_attr_segs containing highlighted
regex matches.
Example use cases include:
1) search for specif
def preprocess_input_exprs_arg_string(input_exprs_str, safe=True):
"""Parses input arg into dictionary that maps input key to python expression.
Parses input string in the format of 'input_key=' into a
dictionary that maps each input_key to it
while True:
try:
x = int(input("Enter x: "))
y = int(input("Enter y: "))
z = x / y
except ZeroDivisionError:
print("Undefined. Zero division error.")
continue
except ValueError:
A = [*map(lambda x: x - 1, A)]
a = [5, 6, 7, 11]
a = [*map(lambda x: x - 1, a)]
print(a)
[4, 5, 6, 10]
A = [i - 1 for i in A]
In [5]: %%tim
def gematria(word):
# using a "generator expression"
return sum(alphabet[char] for char in word)
with open('input.txt', encoding='utf8') as f:
# A generator expression that stores a sorted tuple of
# the calculation a
-?\d[\d .,]*\b
-?\d[\d .,]*\b(?:\.? *(?:×|-) *-?\d[\d .,]*\b)*
│ | | || |
└─────X──────┘(?:└─────Y──────┘└─────X──────┘)*
teamCommentsButton[x].configure(command=onClick)
canvas[x].create_window((20, 20), window=buttonFrame)
def create_lambda(x):
return lambda: comments(x + 10)
df = pd.DataFrame({"Col1": ["123-abc"] * 3 + ["12345-abcde"] * 3})
df[["Col1", "Col2"]] = (
df["Col1"]
.str.split("-", expand=True)
.rename(columns={0: "C1", 1: "C2"})
.assign(C2=lambda df: df["C2"].where(df["C1"].str.len(
def ipRange(start_ip, end_ip):
start = list(map(int, start_ip.split(".")))
end = list(map(int, end_ip.split(".")))
temp = start
ip_range = set()
ip_range.add(start_ip)
while temp != end:
start[3] += 1
for i i
Community Discussions
Trending Discussions on Expression
QUESTION
I have this code which prints multiple tables
...ANSWER
Answered 2021-Jun-15 at 20:59So, this is a good opportunity to use purrr::map
. You are half way there by applying code to one dataframe.
You can take the code that you have written above and put it into a function.
QUESTION
I have a simple code where I try to define a vector as one of two initializer lists using a ternary operator:
...ANSWER
Answered 2021-Jun-15 at 21:48Because you can't have braces in that context. If you look at cppreference on list initialization, you see that the case inside a ternary operator isn't defined. So it can't be parsed correctly and you get the error you have.
You'd have to use something like this :
QUESTION
I am practicing regular expressions in Kotlin and trying to start with a multiline string. However, I am not receiving any matches. I feel like I am doing it right and can't figure out the problem.
Test lines:
...ANSWER
Answered 2021-Jun-15 at 21:32Here is how it works:
QUESTION
GNU grep's basic (BRE) and extended (ERE) syntax is documented at https://www.gnu.org/software/grep/manual/html_node/Regular-Expressions.html and PCRE is summarized at man pcresyntax
, but there is no explicit comparison. What are the differences between GNU grep's basic/extended and PCRE (-P
) regular expressions?
ANSWER
Answered 2021-Jun-15 at 20:55My research of the major syntax and functionality differences from http://www.greenend.org.uk/rjk/tech/regexp.html:
.
in GNU grep does not match null bytes and newlines (but does match newlines when used with--null-data
), while Perl, everything except\n
is matched.[...]
in GNU grep defines POSIX bracket expressions, while Perl uses "character" classes. I'm not sure on the details. See http://www.greenend.org.uk/rjk/tech/regexp.html#bracketexpression- "In basic regular expressions the meta-characters
?
,+
,{
,|
,(
, and)
lose their special meaning; instead use the backslashed versions\?
,\+
,\{
,\|
,\(
, and\)
." From https://www.gnu.org/software/grep/manual/html_node/Basic-vs-Extended.html. ERE matches PCRE syntax. - GNU grep
\w
and\W
are the same as[[:alnum:]]
and[^[:alnum]]
, while Perl uses alphanumeric and underscore. - GNU grep has
\<
and\>
for start and end of word.
Perl supports much more additional functionality:
- "nongreedy {}" with syntax
re{...}?
- additional anchors and character types
\A
,\C
,\d
,\D
,\G
,\p
,\P
,\s
,\S
,\X
.\Z
,\z
. (?#comment)
- shy grouping
(?:re)
, shy grouping + modifiers(?modifiers:re)
- lookahead and negative lookahead
(?=re)
and(?!re)
, lookbehind and negative lookbehind(?<=p)
and(?
- Atomic groups
(?>re)
- Conditional expression
(?(cond)re)
- ... and more, see
man pcresyntax
QUESTION
I am generating lexical analyzer with JLEX. I found a regular expression for string literal from this link and used it in .jflex file same of other expressions. but it gives me this error :
unterminated string at the end of the line
StringLiteral = \"(\\.|[^"\\])*\"
can anyone help me please, thanks.
...ANSWER
Answered 2021-Jun-15 at 20:46The regular expression you copied is for (f)lex, which uses a slightly different syntax for regular expressions. In particular, (f)lex treats "
as an ordinary character inside bracketed classes, so [^"\\]
is a character class matching anything other than (^
) a quotation mark ("
) or a backslash (\\
).
However, in JFlex, the "
is a quoting character, whether outside or inside brackets. So the "
in the character class is unterminated. Hence the error message.
So you need to backslash-escape it:
QUESTION
I have to parse lists of names, addresses, etc. that were OCRed and have invalid/incorrect characters in them and on the state postal code I need to recognize the pattern with a 2 character state followed by a 5 digit postal code and replace any non numeric characters in the postal code. I might have OK 7-41.03
at the end of a string I need to remove the hyphen and period. I know that re.sub('[^0-9]+', '', '7-41.03')
will remove the desired characters but I need it only replace characters in numbers when found at the end of the string and only if preceded by a two character state wrapped in spaces like OK
. It seems if I add anything to the regular expression as far as a lookbehind expression then I can't seem to get the characters replaced. I've come up with the following but I think there must be a simpler expression to accomplish this. Example:
ANSWER
Answered 2021-Jun-15 at 20:02You need to make use of re.sub
callbacks:
QUESTION
I am using a method to remove univariate outliers. This method only works if the vector contains outliers.
How is it possible to generalize this method to work also with vectors without outliers. I tried with ifelse
without success.
ANSWER
Answered 2021-Jun-15 at 19:58Negate (!
) instead of using -
which would work even when there are no outliers
QUESTION
I get it again and again
...ANSWER
Answered 2021-Jun-15 at 18:09You have to make the property overridable, so make it virtual
:
QUESTION
I have a WPF app, linked to a SQL-server. I am using the MVVM-light package (I do actually have Prism.Core installed, but I'm not sure if I'm using it or not.... new to MVVM).
There's a DataGrid
, bound to an ObservableCollection
.
I have been trying to implement the PropertyChangedEventHandler
, but I can't seem to get it to work.
I have a Delete button bound, and I am able to remove rows, but when I re-open the form, the changes does not carry over.
I tried to change the binding-mode for the DataGrid
from OneWay
to TwoWay
. With OneWay
, the changes does not carry over when I re-open the form. With TwoWay
, I get this error message when opening the child form (which contains the DataGrid
):
System.InvalidOperationException: 'A TwoWay or OneWayToSource binding cannot work on the read->only property 'licenseHolders' of type 'Ridel.Hub.ViewModel.LicenseHoldersViewModel'.'
So, If I then add a set;
to my public ObservableCollection licenseHolders { get; }
,
the program runs, but the previous problem persists, like it did when there was a OneWay
mode configuration on the DataGrid
.
What do I need to do to get this to work without communicating directly with the Sql-server
, which would defy the whole point of using this methodology in the first place?
ANSWER
Answered 2021-Jun-15 at 13:26You are confusing topics. The VM needs InotifyPropertyChanged
events, which you have but are not using, to notify the Xaml in the front-end that a VMs property has changed and to bind to the new data reference.
This is needed for List
s or ObservableCollection
s. Once that is done, the ObservableCollection
will then send notifications on changes to the list as items are added or removed.
Because you miss the first step:
QUESTION
I am using class based projection with constructor expressions. here is a sample code form my work
...ANSWER
Answered 2021-Jun-15 at 00:02try using left join
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