kandi X-RAY | maze Summary
kandi X-RAY | maze Summary
Maze generator with crossing;. will produce a pdf, much like this one by default;. Run maze without any arguments to see all help and options. Installation === pip3 install maze.
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Top functions reviewed by kandi - BETA
- Create a grid
- Connect this tree to another one
- Search the grid for a given grid
- Creates a maze
- Render the trail
- Return the direction
- Round float to decimal point
- Takes two points
- Takes 3 points
- Draws a 3 character
- Takes a point
- Convenience function
- Takes two tiles
- Draws a triangle
- Crop the matrix
- Calls c7
- Draws the right hand side
- Causes an image
- Channels
- Performs the cg
- Draws the center of the circle
- Draws an 8 color
- Draws the arc
- Calls c2
- Draws a 4 character
- Render the grid
maze Key Features
maze Examples and Code Snippets
Lines of Code : 67License : Permissive (MIT License)
Copydef solve_maze(maze: list[list[int]]) -> bool:
"""
This method solves the "rat in maze" problem.
In this problem we have some n by n matrix, a start point and an end point.
We want to go from the start to the end. In this matrix ze def run_maze(maze: list[list[int]], i: int, j: int, solutions: list[list[int]]) -> bool:
"""
This method is recursive starting from (i, j) and going in one of four directions:
up, down, left, right.
If a path is found to destinatio private void initializeMaze(String text) {
if (text == null || (text = text.trim()).length() == 0) {
throw new IllegalArgumentException("empty lines data");
}
String[] lines = text.split("[\r]?\n");
maze = Community Discussions
Trending Discussions on maze
QUESTION
I am reading Adam Drozdek's book on DSA, and in solving the mouse in maze problem, he is using stacks. But how would I (if i wanted) count the number of steps the rat takes ? Because according to his stack solution , false positive neighbors (ie. the neigbors that failed to reach destination) also get marked, and there is no backtracking which unmarks these cells. Pls help me. Pls.
EDIT: his algorithm
...ANSWER
Answered 2021-Jun-11 at 14:12With a little change to the algorithm, you're left at the end with the path on the stack:
QUESTION
I'm writing an app for playing different audio files (play them in loops). In the app I want multiple files to be able to play simultaneously , but they need to start at the same point. This means additional audio tracks I have activated would only start playing upon completion of an already playing audio file's loop.
My components are currently two -
- App.js (presents different audio files), parent.
- Play.js (present the option to play and stop each audio file), child . I'm trying to pass an update (via hooks) to the parent once an audio file has started to play, but each time I do such an update I lose the functionality the children i.e. I can start playing a file but can't stop it.
This is the code of my child:
...ANSWER
Answered 2021-Jun-08 at 18:47In your play component use state for the currentlyPlaying and the audio.
QUESTION
How can i get selected checkbox of the datatable by inputing numbers
I'm trying to code a bootstrap data table which able to select check box of the rows by inserting no of rows in the input box
I dont have any idea about how to do it.
e.g: I typed number three in the input box then automatically checkbox table of two rows will get selected at [the beginning -> no problem]
...ANSWER
Answered 2021-Jun-07 at 15:39This should select the checkbox in the first TD of every row based on the number
QUESTION
#include
#include
#include
struct person
{
char name[10];
char size[6];
char timestamp[15];
};
int main ()
{
FILE *outfile;
// open file for writing
outfile = fopen ("ads.txt", "a");
if (outfile == NULL)
{
fprintf(stderr, "\nError opend file\n");
exit (1);
}
struct person input1 = {"runner", "100", "4376482682"};
//struct person input2 = {"maze", "300", "3232365436"};
// write struct to file
fwrite (&input1, sizeof(struct person), 1, outfile);
//fwrite (&input2, sizeof(struct person), 1, outfile);
if(fwrite != 0)
printf("contents to file written successfully !\n");
else
printf("error writing file !\n");
// close file
fclose (outfile);
FILE *infile;
struct person input;
infile = fopen ("ads.txt", "r");
if (infile == NULL)
{
fprintf(stderr, "\nError opening file\n");
exit (1);
}
// read file contents till end of file
char name[10] = "maze";
char size[6] = "500";
char timestamp[15] = "437838322";
int remaining_size = 100;
int alreadythere =0;
//unpcoming file size
int incoming_file_size = 200;
int target_file_size_toremove = incoming_file_size - remaining_size;
while(fread(&input, sizeof(struct person), 1, infile)){
if(target_file_size_toremove > 0) {
int x = atoi(input.size);
if(target_file_size_toremove < x) {
strcpy(input.name, name);
strcpy(input.size, size);
strcpy(input.timestamp, timestamp);
}
}else {
if(strcmp(input.name, name) == 0) { // if name is eqUAL
if(strcmp(input.size, size) != 0) {
strcpy(input.size, size);
}
if(strcmp(input.timestamp, timestamp) !=0) {
strcpy(input.timestamp, timestamp);
}
alreadythere = 1;
}
printf ("id = %s name = %s %s\n", input.name,
input.size, input.timestamp);
}
}
if(alreadythere == 0) {
struct person incoming = {name, size, timestamp};
fwrite (&incoming, sizeof(struct person), 1, outfile);
}
// close file
fclose (infile);
return 0;
}
ANSWER
Answered 2021-Jun-02 at 07:08I have fixed a number of small bugs in your code related to opening the file in correct mode and checking if fwrite and fread where successful. Then I added the part you where really asking: update the record "maze".
To update the record, we need to read it, change the value and write it back to the file exactly where we have read it. So before reading a record, we query the current file pointer with ftell and before writing, we call fseek to move the file pointer back to the place we read. A call to fflush (another fseek would do as well) is required so that the next fread take place at the correct position.
For testing, I added a third record after "maze" so that we can see - by looking at the file content - that we don't overwrite data.
QUESTION
Let me write the relation that A is a sub-class of B by A < B. Suppose there is a relation A < B < C between three classes.
Now, what I want to do is to define a function/class-method that can take argument of all A, B and C (all the sub-class of A). Is it possible? and if so, how can I do this?
EDIT: MOTIVATION
The motivation of this is as follows:
Let say I want to solve a maze. The solver function solve_maze takes a Maze and solve the maze. By default, is_obstacle_free is set to return true always. This means that default maze is the empty space.
What I want to do is, enabling the user to define their custom CustomMaze by inheriting the Maze class if they want. User can change the shape of the maze by tweaking the is_obstacle_free function. Maybe, another user want to define class CustomMaze2 inheriting from CustomMaze.
If I can define solve_maze function that accept any sub-type of Maze, we can avoid defining solve_maze anytime users added a new maze type.
ANSWER
Answered 2021-Jun-03 at 18:32void sample(A& a);
QUESTION
I am fairly new to Haskell and trying to comprehend writing functions and if else conditions and everything else. I am trying to write a very basic function but I don't fully understand if-then-else usage. I have a maze that i represent as [[Char]]. And this function will simply look at the position x,y in the maze and returns if it's a valid position or not. (whether it's in the maze boundaries or not)
I have written this so far:
...ANSWER
Answered 2021-Jun-02 at 13:50The if-else expression requires both parts. You can nest the expressions, so something like if c1 then a else if c2 then b else c.
QUESTION
Below is my Python and Html code:-
Python:
...ANSWER
Answered 2021-May-18 at 03:52error_img.save(byte_io, 'png')
QUESTION
I havet this codepen: https://codepen.io/sp2012/pen/VwpyWdp . Unfortunately, this code is too advanced for me. The game has three maps. I want to keep only the first map and when the game is finished, if you click on the map the game restarts.
The code follows:
This is the HTML:
...ANSWER
Answered 2021-Jun-01 at 06:17Just comment out the second and third level section of the levels[0] object (maps). Change the HTML content that makes reference to other levels.
QUESTION
i'm trying to make a pacman game like pygame, now i just want him to walk through the maze without going beyond the walls of the maze. However I have faced some problems, when I press the keys to move the pacman, he ends up telephoning between the walls, although he does not exceed them it ends up bugging the coordinate system and starts to give a series of errors during the game commands . Does anyone know why this is happening and how to solve it?
...ANSWER
Answered 2021-May-27 at 14:47There are 2 issues:
- The
intention_columnandintention_linedepends on the currentcolumeandlineinstead of the previousintention_columnandintention_line.intention_columnandintention_lineare incremented even if there is a wall.columeandlinehowever are only incremented if the movement is possible:
QUESTION
I'm doing some graph exercises in C and was confused by the sample solutions. I've attached my code below with additions from the sample solutions I don't understand yet.
My question is why in the sp_algo function multiple declaration and initialization of struct queueNode adjCell; and struct Point new_point; works? On the other hand, if I, for example, declare and initalize struct Point end = {2, 6}; in the main function twice, it returns an error:
ANSWER
Answered 2021-May-26 at 12:31struct queueNode adjCell and struct Point new_pointare being initialized twice, but not in the same scope.
Eg.
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install maze
You can use maze like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
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