deREferencing | IDA Pro plugin that implements more user-friendly register | Plugin library
kandi X-RAY | deREferencing Summary
kandi X-RAY | deREferencing Summary
deReferencing is an IDA Pro plugin that implements new registers and stack views. Adds dereferenced pointers, colors and other useful information, similar to some GDB plugins (e.g: PEDA, GEF, pwndbg, etc). Supports following architectures: x86, x86-64, ARM, ARM64, MIPS32 and MIPS64.
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Top functions reviewed by kandi - BETA
- Modify the expression value
- Add a new line
- Get the current word
- Resolve the current expression
- Resolve an expression
- Switch the value
- Reload the view information
- Set current dereferencing levels
- Reload process info
- Reload register flags
- Add a new line
- Create the icon view
- Keydown event handler
- Click event handler
- Parse the chain
- Increment a register
- Set thread info
- Toggle the value of the selected register
- Registers the DB hook
- Jump to current expression
- Jump an expression in the current window
- Double click event handler
- Jump in the disassembly view
- Creates the stimulus viewer
- Jump to the current expression in hexade
- Set the number of stack entries to show
- Create a desktop widget
deREferencing Key Features
deREferencing Examples and Code Snippets
Community Discussions
Trending Discussions on deREferencing
QUESTION
This C code works fine (the compiler is GNU11). I'm sure it can improved since it gives a "dereferencing type-punned pointer" warning, but I don't know exactly how.
A uint8_t array contains 4 bytes that compose a floating point number. These 4 bytes are then stored in a uint32_t variable, and finally casted into a float variable:
...ANSWER
Answered 2022-Mar-24 at 11:40The well defined method for type punning is using a memcpy
between variables of the different types. I.e.
QUESTION
I've looked for an answer to this one, but I can't seem to find anything, so I'm asking here:
Do reference parameters decay into pointers where it is logically necessary?
Let me explain what I mean:
If I declare a function with a reference to an int as a parameter:
...ANSWER
Answered 2022-Mar-04 at 21:18The compiler can decide to implement references as pointers, or inlining or any other method it chooses to use. In terms of performance, it's irrelevant. The compiler can and will do whatever it wants to when it comes to optimization. The compiler can implement your reference as a pass-by-value if it wants to (and if it's valid to do so in the specific situation).
Caching the result won't help because the compiler will do that anyways.
If you want to explicitly tell the compiler that the value might change (because of another thread that has access to the same pointer), you need to use the keyword volatile (or std::atomic if you're not already using a std::mutex).
Edit: The keyword "volatile" is never required for multithreading. std::mutex is enough.
If you don't use the keyword volatile, the compiler will almost certainly cache the result for you (if appropriate).
There are, however, at least 2 actual differences in the rules between pointers and references.
- Taking the address (pointer) of a temporary value (rvalue) is undefined behavior in C++.
- References are immutable, sometimes need to be wrapped in std::ref.
Here I'll provide examples for both differences.
This code using references is valid:
QUESTION
I have a repeated print that prints a bunch of non null-terminated char*
's like so:
ANSWER
Answered 2022-Jan-04 at 00:45When you write printf("%.*s", len1, str1)
, where len1
is zero and str1
is a null pointer, you are using a s
specifier and setting the precision to 0. I looked through the relevant parts of section 7.21.6 of N1570. When documenting the s
specifier, it says:
the argument shall be a pointer to the initial element of an array of character type. Characters from the array are written up to (but not including) the terminating null character. If the precision is specified, no more than that many bytes are written.
So, technically, just looking at the first part of that quote, you do need to provide a pointer to an array instead of providing a null pointer. So your code is not following that part of the standard.
However, you set your precision to 0, so the second part of the quote tells us that the printf
function is not actually going to write any characters from that array to the output. This implies to me that it won't try to read any characters either: reading past the end of the array is unsafe so printf
implementations should not do that. So your code will probably work in practice and it's hard to imagine a case where it would fail. The biggest problem I can think of in practice is that static analyzers or validators might complain about your code.
QUESTION
In our lecture we were discussing the inner possible implementation of std::list
. The lecturer showed the approach where a dummy node is created to indicate the end of the list:
ANSWER
Answered 2022-Jan-28 at 21:48First, for your second line
QUESTION
Is it possible to implement something similar to C++20's std::bit_cast
in C? It would be a lot more convenient than using union
or casting pointers to different types and dereferencing.
If you had a bit_cast
, then implementing some floating point functions would be easier:
ANSWER
Answered 2022-Jan-19 at 01:25It is possible in non-standard standard C, thanks to typeof
. typeof
is also a further proposed feature for C23, so it may become possible in standard C23. One of the solutions below makes some sacrifices which allow C99 compliance.
union
Let's look at how the approach using union
works first:
QUESTION
See this sample:
...ANSWER
Answered 2021-Dec-21 at 14:09When you apply filtering using Where
, you eliminate all null values, but this doesn't change the type of values.
All you need is to cast the results after filtering to the proper type:
QUESTION
I had an exercise telling me to input elements into an array by only using pointers. So I looked for a solution in the WEB ( https://codeforwin.org/2017/11/c-program-input-print-array-elements-using-pointers.html)
...ANSWER
Answered 2021-Dec-24 at 21:33Why do we use ptr without dereferencing it with (*ptr).
We're passing scanf
the pointer to memory on which to write the int that it gets from the keyboard. To dereference is to follow that pointer ourselves, which doesn't help scanf know where to write the value.
When we use scanf we type in a value (int or double or float) and not an address so why's that ptr without * ?
The &
in &N
is the address-of operator, meaning "make me a pointer to N". You could write int *N_ptr = &N;
then scanf("%d", N_ptr);
if that makes it clearer.
One other thing: passing arguments/parameters in C is done by copy. Meaning:
QUESTION
I was implementing an iterator that takes another float values producing input iterator and returns true if a rising was detected. So, the iterator works effectively as a Software-ADC (Analog-Digital-Converter).
I've minimized the actual code to the following:
...ANSWER
Answered 2021-Dec-24 at 13:57This can be done by reimplementing the operator so that its internal data holds just the bool
value, instead of the floating point value from which the bool
value is derived only when the iterator gets dereferenced.
In other words, the dereferencing iterator should simply be:
QUESTION
I was casting a field of a struct to a *mut
pointer, so I declared that struct's reference as mutable. But then I started getting warnings that the mut
modifier is not required. That seemed weird to me, I'm clearly mutating something, yet declaring it as mut
is unnecessary? This leads me to this minimal example:
ANSWER
Answered 2021-Nov-10 at 15:05Problem #1: potentially_mutate
is incorrectly marked as a safe function while it can cause undefined behavior (e.g. what if I pass in an invalid pointer?). So we need to mark it unsafe
and document our assumptions for safe usage:
QUESTION
Assume we already know that String
can become &str
after deref for
ANSWER
Answered 2021-Nov-08 at 15:06From The Rust Programming Language:
Deref coercion is a convenience that Rust performs on arguments to functions and methods. Deref coercion works only on types that implement the
Deref
trait. Deref coercion converts such a type into a reference to another type. For example, deref coercion can convert&String
to&str
becauseString
implements theDeref
trait such that it returns&str
. Deref coercion happens automatically when we pass a reference to a particular type’s value as an argument to a function or method that doesn’t match the parameter type in the function or method definition. A sequence of calls to thederef
method converts the type we provided into the type the parameter needs.
Deref coercion converts references into references. It will auto-deref &value
to &*value
, &**value
, &***value
, etc., in order to convert one reference type into another that fits a parameter signature. The starting and ending types are always references.
Notably, it doesn't put the deref on the front. It doesn't do &value
to *&value
to **&value
, which is why it won't convert &String
to String
or String
to &str
.
Turning
&String
intoString
would turn it into a move. If I wrotefunc(&s)
andfunc
takes aString
it would be confusing if that compiled and actually moveds
.Similarly, turning
String
into&str
would turn a move into a pass-by-reference. If I wrotefunc(s)
I'd expects
to be moved, with ownership transferred tofunc
. It should not compile iffunc
takes a&str
and I pass aString
.
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