ludus | Library to simplify speed up application | Reinforcement Learning library
kandi X-RAY | ludus Summary
kandi X-RAY | ludus Summary
Ludus is a reinforcement learning library for expediating development of RL applications and research. Ludus is still in an alpha development stage, so new algorithms and models are continuously being added with the growth of the framework. You can find many state-of-the-art algorithms implemented and ready to use. Additionly, the platform has ready to go integration with popular training environments like OpenAI's gym. The high level API of Ludus combined with easily accesible and well documented, open source code allows for both efficiency and control.
Support
Quality
Security
License
Reuse
Top functions reviewed by kandi - BETA
- Performs a simulation thread
- Render the chart
- Perform an action step
- Transform an act
- Simulate a network
- Converts the rollout to a numpy array
- Discount rewards by gamma
- Creates a continuous trainer
- Reshape a numpy array
- Gaussian likelihood
- Create a continuous trainer
- Create discrete trainer
- Create a discrete trainer
- Generate episodes
- Create discrete tracer
- Close the session
- Preprocess ANTsImage
ludus Key Features
ludus Examples and Code Snippets
Community Discussions
Trending Discussions on ludus
QUESTION
Let's suppose I have a long text that I want to process with an API having a maximum number of allowed characters (N). I would like to split that text into 2 or more texts with shorter than N characters, and based on a separator. I know I could split by separator but I would like to keep the number of output sub-texts the smallest as possible.
For example, suppose my text is:
"Lorem ipsum dolor sit amet, odio salutandi id nam, ferri nostro te duo. Eum ex odio habeo qualisque, ne eos natum graeco. Autem voluptatum ex mea. Nulla putent reformidans cu pro, posse recusabo reprehendunt pro no. An sit ludus oblique. Consulatu cotidieque ex sea, nam no duis prompta expetendis.
Est ne tempor quaestio complectitur, modo error vim et. Option voluptaria efficiantur te eam, ea appareat evertitur qui, te vix pertinax recteque. Mea eu diceret ceteros. Expetenda torquatos assueverit est ex, te reque voluptatibus signiferumque has."
which is 550 characters long. Let's suppose that N is 250. I would expect the text to be split in this way:
Part 1: "Lorem ipsum dolor sit amet, odio salutandi id nam, ferri nostro te duo. Eum ex odio habeo qualisque, ne eos natum graeco. Autem voluptatum ex mea. Nulla putent reformidans cu pro, posse recusabo reprehendunt pro no. An sit ludus oblique" (237 characters)
Part 2: "Consulatu cotidieque ex sea, nam no duis prompta expetendis.
Est ne tempor quaestio complectitur, modo error vim et. Option voluptaria efficiantur te eam, ea appareat evertitur qui, te vix pertinax recteque. Mea eu diceret ceteros." (232 characters)
- Part 3: the remaining.
Any idea on how to do this in Python?
Thank you for any help. Francesca
...ANSWER
Answered 2022-Mar-05 at 17:12
n = 250
text = """Lorem ipsum dolor sit amet, odio salutandi id nam, ferri nostro te duo. Eum ex odio habeo qualisque, ne eos natum graeco. Autem voluptatum ex mea. Nulla putent reformidans cu pro, posse recusabo reprehendunt pro no. An sit ludus oblique. Consulatu cotidieque ex sea, nam no duis prompta expetendis.
Est ne tempor quaestio complectitur, modo error vim et. Option voluptaria efficiantur te eam, ea appareat evertitur qui, te vix pertinax recteque. Mea eu diceret ceteros. Expetenda torquatos assueverit est ex, te reque voluptatibus signiferumque has."""
if len(text) >= 550:
print(text[0:n-1])
print(text[n:])
else:
print(text)
QUESTION
I am trying to add a ruby tag for every word in a paragraph. The html doc looks somthing like this
...ANSWER
Answered 2021-Jun-12 at 19:51Looking at the documentation one way might be to leverage new_tag()
and decompose()
. As you want to treat punctuation also within separate tags then regex can be used to generate the content for each new ruby
tag. I used the regex from @user3850.
Create a new p
tag, during a loop, and append your ruby
tags, you can then decompose()
the original p
tag.
QUESTION
how will I access the last span element in my p tag? I have 4 span tags in my p tag I want to access the last one and do changes to it!! I've added styling to the p span body{}
but they all are changing I want the last span tag to be accessible.
for example here is the code!
...ANSWER
Answered 2021-Mar-28 at 20:23Use the last-of-type
selector
QUESTION
Here is the code
...ANSWER
Answered 2020-Aug-08 at 04:54Yup, you can use mask-image
then gradient
something like this:
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install ludus
Support
Reuse Trending Solutions
Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items
Find more librariesStay Updated
Subscribe to our newsletter for trending solutions and developer bootcamps
Share this Page