ludus | Library to simplify speed up application | Reinforcement Learning library

 by   ejmejm Python Version: 0.1a3 License: MIT

kandi X-RAY | ludus Summary

kandi X-RAY | ludus Summary

ludus is a Python library typically used in Institutions, Learning, Education, Artificial Intelligence, Reinforcement Learning, Deep Learning, Pytorch, Tensorflow applications. ludus has no bugs, it has no vulnerabilities, it has build file available, it has a Permissive License and it has low support. You can install using 'pip install ludus' or download it from GitHub, PyPI.

Ludus is a reinforcement learning library for expediating development of RL applications and research. Ludus is still in an alpha development stage, so new algorithms and models are continuously being added with the growth of the framework. You can find many state-of-the-art algorithms implemented and ready to use. Additionly, the platform has ready to go integration with popular training environments like OpenAI's gym. The high level API of Ludus combined with easily accesible and well documented, open source code allows for both efficiency and control.
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            kandi-support Support

              ludus has a low active ecosystem.
              It has 7 star(s) with 0 fork(s). There are 2 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              ludus has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of ludus is 0.1a3

            kandi-Quality Quality

              ludus has 0 bugs and 0 code smells.

            kandi-Security Security

              ludus has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              ludus code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              ludus is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              ludus releases are not available. You will need to build from source code and install.
              Deployable package is available in PyPI.
              Build file is available. You can build the component from source.
              Installation instructions are available. Examples and code snippets are not available.

            Top functions reviewed by kandi - BETA

            kandi has reviewed ludus and discovered the below as its top functions. This is intended to give you an instant insight into ludus implemented functionality, and help decide if they suit your requirements.
            • Performs a simulation thread
            • Render the chart
            • Perform an action step
            • Transform an act
            • Simulate a network
            • Converts the rollout to a numpy array
            • Discount rewards by gamma
            • Creates a continuous trainer
            • Reshape a numpy array
            • Gaussian likelihood
            • Create a continuous trainer
            • Create discrete trainer
            • Create a discrete trainer
            • Generate episodes
            • Create discrete tracer
            • Close the session
            • Preprocess ANTsImage
            Get all kandi verified functions for this library.

            ludus Key Features

            No Key Features are available at this moment for ludus.

            ludus Examples and Code Snippets

            No Code Snippets are available at this moment for ludus.

            Community Discussions

            QUESTION

            Split a long text in two or more parts each one with a maximum length in python
            Asked 2022-Mar-05 at 18:30

            Let's suppose I have a long text that I want to process with an API having a maximum number of allowed characters (N). I would like to split that text into 2 or more texts with shorter than N characters, and based on a separator. I know I could split by separator but I would like to keep the number of output sub-texts the smallest as possible.

            For example, suppose my text is:

            "Lorem ipsum dolor sit amet, odio salutandi id nam, ferri nostro te duo. Eum ex odio habeo qualisque, ne eos natum graeco. Autem voluptatum ex mea. Nulla putent reformidans cu pro, posse recusabo reprehendunt pro no. An sit ludus oblique. Consulatu cotidieque ex sea, nam no duis prompta expetendis.

            Est ne tempor quaestio complectitur, modo error vim et. Option voluptaria efficiantur te eam, ea appareat evertitur qui, te vix pertinax recteque. Mea eu diceret ceteros. Expetenda torquatos assueverit est ex, te reque voluptatibus signiferumque has."

            which is 550 characters long. Let's suppose that N is 250. I would expect the text to be split in this way:

            • Part 1: "Lorem ipsum dolor sit amet, odio salutandi id nam, ferri nostro te duo. Eum ex odio habeo qualisque, ne eos natum graeco. Autem voluptatum ex mea. Nulla putent reformidans cu pro, posse recusabo reprehendunt pro no. An sit ludus oblique" (237 characters)

            • Part 2: "Consulatu cotidieque ex sea, nam no duis prompta expetendis.

            Est ne tempor quaestio complectitur, modo error vim et. Option voluptaria efficiantur te eam, ea appareat evertitur qui, te vix pertinax recteque. Mea eu diceret ceteros." (232 characters)

            • Part 3: the remaining.

            Any idea on how to do this in Python?

            Thank you for any help. Francesca

            ...

            ANSWER

            Answered 2022-Mar-05 at 17:12
            
            n = 250
            text = """Lorem ipsum dolor sit amet, odio salutandi id nam, ferri nostro te duo. Eum ex odio habeo qualisque, ne eos natum graeco. Autem voluptatum ex mea. Nulla putent reformidans cu pro, posse recusabo reprehendunt pro no. An sit ludus oblique. Consulatu cotidieque ex sea, nam no duis prompta expetendis.
            
            Est ne tempor quaestio complectitur, modo error vim et. Option voluptaria efficiantur te eam, ea appareat evertitur qui, te vix pertinax recteque. Mea eu diceret ceteros. Expetenda torquatos assueverit est ex, te reque voluptatibus signiferumque has."""
            
            if len(text) >= 550:
              print(text[0:n-1])
              print(text[n:])
            else:
              print(text)
            

            Source https://stackoverflow.com/questions/71364193

            QUESTION

            Beautiful Soup adding multiple tags to words in paragraph
            Asked 2021-Jun-12 at 19:51

            I am trying to add a ruby tag for every word in a paragraph. The html doc looks somthing like this

            ...

            ANSWER

            Answered 2021-Jun-12 at 19:51

            Looking at the documentation one way might be to leverage new_tag() and decompose(). As you want to treat punctuation also within separate tags then regex can be used to generate the content for each new ruby tag. I used the regex from @user3850.

            Create a new p tag, during a loop, and append your ruby tags, you can then decompose() the original p tag.

            Source https://stackoverflow.com/questions/67951593

            QUESTION

            How to access the last child tag in a parent tag?
            Asked 2021-Mar-28 at 20:34

            how will I access the last span element in my p tag? I have 4 span tags in my p tag I want to access the last one and do changes to it!! I've added styling to the p span body{} but they all are changing I want the last span tag to be accessible.

            for example here is the code!

            ...

            ANSWER

            Answered 2021-Mar-28 at 20:23

            Use the last-of-type selector

            Source https://stackoverflow.com/questions/66845831

            QUESTION

            Is it possible to use pure CSS to make a HTML container be gradient fade away in a fixed height?
            Asked 2020-Aug-08 at 05:00

            Here is the code

            ...

            ANSWER

            Answered 2020-Aug-08 at 04:54

            Yup, you can use mask-image then gradient

            something like this:

            Source https://stackoverflow.com/questions/63311825

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install ludus

            These instructions will help you quickly get Ludus up and running, ready for RL application. Ludus is built on Python 3, and there is no gaurantee it will work with Python 2.

            Support

            Further, more in depth documentation is in the works, although not ready quite.
            Find more information at:

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            Install
          • PyPI

            pip install ludus

          • CLONE
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            https://github.com/ejmejm/ludus.git

          • CLI

            gh repo clone ejmejm/ludus

          • sshUrl

            git@github.com:ejmejm/ludus.git

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