PySocket | PySocket ，一个通过猴子补丁（monkey patch）动态修改 socket 的项目。在不修改源码的情况下给 | Socket library

by falseen Python Version: Current License: Apache-2.0

X-Ray Key Features Code Snippets Community Discussions(1)Vulnerabilities Install Support

kandi X-RAY | PySocket Summary

PySocket is a Python library typically used in Networking, Socket applications. PySocket has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. However PySocket build file is not available. You can download it from GitHub.

PySocket ，一个通过猴子补丁（monkey patch）动态修改 socket 的项目。本项目源于一个朋友的需求，当时他想限制shadowsocks客户端的数量，但又不想修改源码，于是我为他写了这个代码，原代码发布在gist上，现在迁移了过来，并且增加了一些新的功能。以后可能还会增加一些新功能，让我们将 Monkey Patch 进行到底吧！.

Support

Quality

Security

License

Reuse

Support

PySocket has a low active ecosystem.

It has 108 star(s) with 40 fork(s). There are 10 watchers for this library.

It had no major release in the last 6 months.

There are 14 open issues and 8 have been closed. On average issues are closed in 45 days. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of PySocket is current.

Quality

PySocket has 0 bugs and 0 code smells.

Security

PySocket has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

PySocket code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

PySocket is licensed under the Apache-2.0 License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

PySocket releases are not available. You will need to build from source code and install.

PySocket has no build file. You will be need to create the build yourself to build the component from source.

PySocket saves you 1126 person hours of effort in developing the same functionality from scratch.

It has 2545 lines of code, 250 functions and 8 files.

It has high code complexity. Code complexity directly impacts maintainability of the code.

Top functions reviewed by kandi - BETA

kandi has reviewed PySocket and discovered the below as its top functions. This is intended to give you an instant insight into PySocket implemented functionality, and help decide if they suit your requirements.

Negotiates a SOCKS4 request
Convert string to inet format
Get host by name
Convert a packed IP address to inet format
Create a connection to a given destination pair
Convert value to int enum
Get the addresses of the given host and port
Negotiate a connection via HTTP
Send data
Negotiates a TCP connection
Create a new sendto
Add a new method to the given class
Create a socket from a fd
Send bytes to socket
Set timeout
Return the name of the file
Set socksocket proxy
Return the type of the socket
Duplicate the socket
Close the socket
Accepts and returns a new socket
Add server_addrs and port
Read data from b
Get a fully qualified name
Add a network
Regenerate new connections

Get all kandi verified functions for this library.

PySocket Key Features

No Key Features are available at this moment for PySocket.

PySocket Examples and Code Snippets

No Code Snippets are available at this moment for PySocket.

Community Discussions

Trending Discussions on PySocket

How to connect a Python UnetSocket to an Agent that I have created using agentForService?

QUESTION

How to connect a Python UnetSocket to an Agent that I have created using agentForService?

Asked 2020-Mar-31 at 15:59

I am trying to make a link between a Python script and a simulation running on UnetSim. I want to send messages from Python and receive them in UnetStack using a Python_Agent.groovy that I created and added to container of each node in the simulation. I also want to do the reverse.

I used the fjage documentation (https://buildmedia.readthedocs.org/media/pdf/fjage/dev/fjage.pdf) to help me. The problem is that in gateway class Services there is not the PYTHON_AGENT Service that I created. I can understand that as my enum Services does not modified class Services where there are NODE_INFO, PHYSICAL etc... My question is then how the example in the documentation 1.6.3 works ? And is it applicable to my case ?

Here is my code :

PythonSocketExample.py

...

ANSWER

Answered 2020-Feb-28 at 05:57

A few problems in your original code:

You don't need to create a service, since you can address the agent by its name. This should be sufficient for your example here.
To process a request (DatagramReq from your Python code), you should override the processRequest() method in the agent.

Here's a simplified example based on your original code:

PythonAgent.groovy:

Source https://stackoverflow.com/questions/60437685

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install PySocket

You can download it from GitHub.
You can use PySocket like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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