kchar | A keras-based implementation | Machine Learning library

by jarfo Python Version: Current License: No License

X-Ray Key Features Code Snippets Community Discussions(3)Vulnerabilities Install Support

kandi X-RAY | kchar Summary

kchar is a Python library typically used in Artificial Intelligence, Machine Learning, Deep Learning, Keras, Numpy applications. kchar has no bugs, it has no vulnerabilities and it has low support. However kchar build file is not available. You can download it from GitHub.

Character-Aware Neural Language Models. A keras-based implementation

Support

Quality

Security

License

Reuse

Support

kchar has a low active ecosystem.

It has 119 star(s) with 52 fork(s). There are 7 watchers for this library.

It had no major release in the last 6 months.

There are 0 open issues and 14 have been closed. On average issues are closed in 160 days. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of kchar is current.

Quality

kchar has 0 bugs and 0 code smells.

Security

kchar has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

kchar code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

kchar does not have a standard license declared.

Check the repository for any license declaration and review the terms closely.

Without a license, all rights are reserved, and you cannot use the library in your applications.

Reuse

kchar releases are not available. You will need to build from source code and install.

kchar has no build file. You will be need to create the build yourself to build the component from source.

Installation instructions are not available. Examples and code snippets are available.

kchar saves you 228 person hours of effort in developing the same functionality from scratch.

It has 557 lines of code, 28 functions and 6 files.

It has high code complexity. Code complexity directly impacts maintainability of the code.

Top functions reviewed by kandi - BETA

kandi has reviewed kchar and discovered the below as its top functions. This is intended to give you an instant insight into kchar implemented functionality, and help decide if they suit your requirements.

Compute the log probability of the given line
Get input for given line
Return the index for the word
Set a list of states
LSTMNN
Concatenate CNN
Yield the next batch
Fit a generator
Loads a model from a file
Save the document to a JSON file

Get all kandi verified functions for this library.

kchar Key Features

No Key Features are available at this moment for kchar.

kchar Examples and Code Snippets

No Code Snippets are available at this moment for kchar.

Community Discussions

Trending Discussions on kchar

Codechef KCHAR wrong answer

Generating vampire numbers for a free range in Java (For big ranges)

Tiny Encryption Algorithm implementation produces unexpected results

QUESTION

Codechef KCHAR wrong answer

Asked 2019-Nov-19 at 07:26

Recently I was solving the following problem on codechef:

Alice has quarreled with Chef recently. So Chef gives a problem to Alice. Initially you are given an empty string and are allowed following two operations.

Operation-1: Every 'a' becomes 'c' and every 'c' becomes 'a'. For example, "acc" becomes "caa".
Operation-2: String is reversed. For Example, "acc" becomes "cca".

Chef gives following generating equation S_N = S_N-1 + "a" + Operation-1(Operation-2(S_N-1))

where S0 = "" (empty string).

Alice easily finds out next few sequences as:

S1 = "a"
S2 = "aac"
S3 = "aacaacc"

Now Chef asks to find Kth character of S_LOC, where LOC = 10²⁰¹⁷. You need to help Alice find the answer.

1 ≤ T ≤ 100
1 ≤ K ≤ 10¹⁸

I have tried to solve the problem using following code:

...

ANSWER

Answered 2017-Jul-05 at 20:28

Your code doesn't work for k=576460752303423478. It doesn't terminate. I haven't debugged it fully, but the root cause is numerical inaccuracy: av should be the largest power of 2 less than or equal to k, but it ends up larger than k. I expect there's other cases that terminate but produce the wrong result.

To find the failing case, I wrote my own version of the code and tried testing it for many values of k. That didn't turn up anything, so then tried near-powers-of-2. That found the example above.

Here's the code that finds the problem case (here x() is your code, and y() is my code). I added asserts to your code which demonstrate the problem, but you can remove them and see that the code doesn't terminate.

Source https://stackoverflow.com/questions/44933410

QUESTION

Generating vampire numbers for a free range in Java (For big ranges)

Asked 2019-Sep-05 at 00:41

A vampire number is a natural number with an even number of digits, that can be factored into two integers. These two factors are called the fangs, and must have the following properties:

they each contain half the number of the digits of the original number together they consist of exactly the same digits as the original number at most one of them has a trailing zero

An example of a Vampire number and its fangs: 1260 : (21, 60)

This is a simple code to generate vampire numbers 4 digits . How to modify this to generate vampire numbers for large numbers (100000,200000) efficiently

...

ANSWER

Answered 2019-Sep-01 at 15:34

I came up with this, which is basically the same as your approach, just adjusted for slightly "larger" ranges.

On my pc it takes less than 1 seconds to fully scan all vampiric numbers in the 8 digit range and around 80 seconds for the 10 digit range. Anything beyond that takes a while ...

I have also added in the elimination of two fangs with trailing zeroes, which was not mentioned in your definition.

Source https://stackoverflow.com/questions/57742080

QUESTION

Tiny Encryption Algorithm implementation produces unexpected results

Asked 2017-May-12 at 09:04

Here is an implementation of TEA, that attempts to encrypt a file containing a text message:

main.cpp

...

ANSWER

Answered 2017-May-11 at 14:25

The + operation has a higher precedence than ^, so (z<<4 ^ z>>5) + z^sum + k[sum&3] is parsed as

Source https://stackoverflow.com/questions/43918116

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install kchar

You can download it from GitHub.
You can use kchar like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

Find more information at: